decimal

Rather than converting an arbitrary decimal to an exact fraction (something like 323527/4362363), I am trying to convert to just common easily-discernible (in terms of human-readability) quantities like 1/2, 1/4, 1/8 etc. Other than using a series of if-then, less than/equal to etc comparisons, are there more optimized techniques to do this? Edit: In my particular case, approximations are acceptable. The idea is that 0.251243 ~ 0.25 = 1/4 - in my usage case, that's "good enough", with the latter more preferable for human readability in terms of a quick indicator (not used for calculation, just

I'm using Java's DecimalFormat class to print out numbers in Scientific Notation. However, there is one problem that I have. I need the strings to be of fixed length regardless of the value, and the sign on the power of ten is throwing it off. Currently, this is what my format looks like: DecimalFormat format = new DecimalFormat("0.0E0"); This gives me the following combinations: 1.0E1, 1.0E-1, -1.0E1, and -1.0E-1. I can use setPositivePrefix to get: +1.0E1, +1.0E-1, -1.0E1, and -1.0E-1, or whatever I like, but it doesn't affect the sign of the power! Is there any way to do this so that I can

I need to store Python decimal type values in a pandas TimeSeries / DataFrame object. Pandas gives me an error when using the "groupby" and "mean" on the TimeSeries/DataFrame. The following code based on floats works well: [0]: by = lambda x: lambda y: getattr(y, x) [1]: rng = date_range('1/1/2000', periods=40, freq='4h') [2]: rnd = np.random.randn(len(rng)) [3]: ts = TimeSeries(rnd, index=rng) [4]: ts.groupby([by('year'), by('month'), by('day')]).mean() 2000 1 1 0.512422 2 0.447235 3 0.290151 4 -0.227240 5 0.078815 6 0.396150 7 -0.507316 But i get an error if do the same using decimal values

So, we know that fractions such as 0.1, cannot be accurately represented in binary base, which cause precise problems (such as mentioned here: Formatting doubles for output in C# ). And we know we have the decimal type for a decimal representation of numbers... but the problem is, a lot of Math methods, do not supporting decimal type, so we have convert them to double, which ruins the number again. so what should we do? For a comprehensive examination of the challenges involved in performing floating-point calculations, see this article: What Every Computer Scientist Should Know About Floating

How to parse string to decimal so it would work for both formats - w/ commas and periods? [Fact] public void foo(){ var a="1,1"; var b="1.1"; Assert.Equal(Parse(a),Parse(b)); } private decimal Parse(string s){ return decimal.Parse(s,NumberStyles.Any, CultureInfo.InvariantCulture); } output: Test 'Unit.Sandbox.foo' failed: Assert.Equal() Failure Expected: 11 Actual: 1,1 You could try that: private decimal Parse(string s){ s = s.Replace(",", CultureInfo.InvariantCulture.NumberFormat.NumberDecimalSeparator); return decimal.Parse(s,NumberStyles.Any, CultureInfo.InvariantCulture); } Bat_Programmer

How can I make my program output a number with at least one number behind the decimal mark C++? Output: 1 = 1.0 or 1.25 = 1.25 or 2.2 = 2.2 or 3.456789 = 3.456789 Thanks in advance Use showpoint to force the decimal point to be printed double x = 1.0; std::cout << std::showpoint << x << "\n"; It will be followed by the number of 0 required to satisfy the precision of the stream. #include <cmath> #include <iostream> #include <limits> struct FormatFloat { static constexpr const double precision = std::sqrt(std::numeric_limits<double>::epsilon()); const double value; FormatFloat(double value) :

I have a vector of a binary string: a<-c(0,0,0,1,0,1) I would like to convert this vector into decimal. I tried using the compositions package and the unbinary() function, however, this solution and also most others that I have found on this site require g-adic string as input argument. My question is how can I convert a vector rather than a string to decimal? to illustrate the problem: library(compositions) unbinary("000101") [1] 5 This gives the correct solution, but: unbinary(a) unbinary("a") unbinary(toString(a)) produces NA. You could try this function bitsToInt<-function(x) { packBits