decimal-point

问题 I try to show and use the right digit separator depending on the clients browser selected language. I'm using a Blazor Server App. I've tried to use the 'Sytem.Globalization' namespace but this only shows the settings of the Server Side browser. Is there a way to get the Client browser language/culure settings? 回答1: You could use javascripts navigator.language property via Interop. https://developer.mozilla.org/en-US/docs/Web/API/NavigatorLanguage/languages public static class JsInterop {

问题 I have been trying to read a file which has date field and a numeric field. I have the data in an excel sheet and looks something like below - Date X 1/25/2008 0.0023456 12/23/2008 0.001987 When I read this in R using the readxl::read_xlsx function, the data in R looks like below - Date X 1/25/2008 0.0023456000000000 12/23/2009 0.0019870000000000 I have tried limiting the digits using functions like round, format (nsmall = 7), etc. but nothing seems to work. What am I doing wrong? I also

来源： https://stackoverflow.com/questions/38390950/how-to-round-a-number-to-n-decimal-places

问题 I currently have a number input script that behaves similar to a calculator with the way numbers are displayed, but I want to stop the adding of additional numbers to the series after two numbers past the decimal point. Here is what I have so far, though the limiting doesn't occur correctly. It should work like this: 1.25 - Allowed 12.5 - Allowed 125.5 - Allowed 125.55 - Allowed 123.555 - Not Allowed rText = document.getElementById("resultText"); function selectNumber(num) { if (!rText.value

问题 Is there an easy way to read back if the language set uses a decimal comma or a decimal point? 回答1: EDIT: Updating based on @Algar's suggestion; you can directly use: char separatorChar = DecimalFormatSymbols.getInstance().getDecimalSeparator(); As it will always return an instance of DecimalFormatSymbols . NumberFormat nf = NumberFormat.getInstance(); if (nf instanceof DecimalFormat) { DecimalFormatSymbols sym = ((DecimalFormat) nf).getDecimalFormatSymbols(); char decSeparator = sym

问题 Is there an easy way to read back if the language set uses a decimal comma or a decimal point? 回答1: EDIT: Updating based on @Algar's suggestion; you can directly use: char separatorChar = DecimalFormatSymbols.getInstance().getDecimalSeparator(); As it will always return an instance of DecimalFormatSymbols . NumberFormat nf = NumberFormat.getInstance(); if (nf instanceof DecimalFormat) { DecimalFormatSymbols sym = ((DecimalFormat) nf).getDecimalFormatSymbols(); char decSeparator = sym

问题 This question already has answers here : Truncating floats in Python (29 answers) Closed 2 years ago . I want convert a number to a float number with 3 decimal point but I want it without rounding. For example: a = 12.341661 print("%.3f" % a) This code return this number: 12.342 but I need to original number,I need this: 12.341 I write a code that receive a number form user and convert it to a float number. I have no idea that what is the number entered with user. 回答1: My first thought was to

问题 This question already has answers here : Truncating floats in Python (29 answers) Closed 2 years ago . I want convert a number to a float number with 3 decimal point but I want it without rounding. For example: a = 12.341661 print("%.3f" % a) This code return this number: 12.342 but I need to original number,I need this: 12.341 I write a code that receive a number form user and convert it to a float number. I have no idea that what is the number entered with user. 回答1: My first thought was to

问题 This question already has answers here : Truncating floats in Python (29 answers) Closed 2 years ago . I want convert a number to a float number with 3 decimal point but I want it without rounding. For example: a = 12.341661 print("%.3f" % a) This code return this number: 12.342 but I need to original number,I need this: 12.341 I write a code that receive a number form user and convert it to a float number. I have no idea that what is the number entered with user. 回答1: My first thought was to

问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: what is the equivalent for java class : BigDecimal in c# I know in this post: Arbitrary precision decimals in C#? says to use java.math.BigDecimal, but I don't have J# installed. How would I achieve arbitrary precision in C#? I was thinking of using binary strings but I may run into some trouble when multiplying the two. 回答1: See What is the equivalent of the Java BigDecimal class in C#? You could create your