debugging

问题 Can anyone recommend a decent extension to Google Chrome that is similar to Firebug? I did see that there are a couple of similar questions here on SO, but the answers seem to be very dated. Thanks! 回答1: You can use firebug lite. But Chrome already has more than decent developer tools built in it. 回答2: It's built in. Press Ctrl + Shift + I . (Or Tools > Developer in the menu) 回答3: Chrome's developer tools has come a long way over the last year. It took a bit to adjust and I kept getting

问题 The HTML below specifies a button and a div that have identical class and contents. <div class="root"><!-- --><button class="outer"><div class="middle"><div class="inner">label</div></div></button><!-- --><div class="outer"><div class="middle"><div class="inner">label</div></div></div ><!-- --></div> In this example, I have explicitly set every CSS property 1 for the classes outer , middle , and inner 2 . This means that both the button.outer and div.outer sub-trees of the DOM should have

问题 After refresh the page, the user selected radio button is missing. How can i always display the user's "selected radio button" even I had refresh the page? <input name="radiobutton" type="radio" value="" id="all" checked /> radio with checked is not suitable, because it will always display the default radio button. Below is my code:- <form name="myfrm" id="myfrm" action="" method="post"> <input name="radiobutton" type="radio" value="" id="all" /> <label>All Languages</label> <input name=

问题 After refresh the page, the user selected radio button is missing. How can i always display the user's "selected radio button" even I had refresh the page? <input name="radiobutton" type="radio" value="" id="all" checked /> radio with checked is not suitable, because it will always display the default radio button. Below is my code:- <form name="myfrm" id="myfrm" action="" method="post"> <input name="radiobutton" type="radio" value="" id="all" /> <label>All Languages</label> <input name=

问题 When I double clicked on QString object in totalview debugger this window appears. How can I get the exact value of it. I have tried command.toUtf8().constData() but it prints Cannot find name "toUtf8" . 回答1: ::TV::TTF::RTF::build_struct_transform { name {^struct QString$} members { { ascii { $wstring_u16 cast { * { d -> unicode } } } } } } ::TV::TTF::RTF::build_struct_transform { name {^struct QString$} members { { ascii { $wstring_u16 cast {* {d -> data} } } } } } Add this to $HOME/.tvdrc

问题 When I double clicked on QString object in totalview debugger this window appears. How can I get the exact value of it. I have tried command.toUtf8().constData() but it prints Cannot find name "toUtf8" . 回答1: ::TV::TTF::RTF::build_struct_transform { name {^struct QString$} members { { ascii { $wstring_u16 cast { * { d -> unicode } } } } } } ::TV::TTF::RTF::build_struct_transform { name {^struct QString$} members { { ascii { $wstring_u16 cast {* {d -> data} } } } } } Add this to $HOME/.tvdrc

问题 I often find myself adding either concatonated strings or using a string formatter in my debug statements in log4net and log4j should I surround these debug statements with an "if debug" block to stop myself from wasting resources by processing these parameters even though the debug statement will not be printed out? I would assume that checking if (isDebug) would be quicker and more efficient than having the string operations occuring, however it would lead to the program operating

问题 I often find myself adding either concatonated strings or using a string formatter in my debug statements in log4net and log4j should I surround these debug statements with an "if debug" block to stop myself from wasting resources by processing these parameters even though the debug statement will not be printed out? I would assume that checking if (isDebug) would be quicker and more efficient than having the string operations occuring, however it would lead to the program operating

问题 I know that you can either step into every property or not step into every property, but I would really like to be able to step into a specific property, and not the rest. Is this possible? (I also know I can use keyboard commands, but I'm asking if there's a more permanent solution.) I have a lot of properties and my setters do important things, so it's silly to step over them, but most of my getters are pointless. I'm looking for something like: public string ImportantProperty { get {

问题 What is debugging a code and how would I go about this ? 回答1: Debugging is the process to in which you make sure your code contains no bugs (or at least as few as possible ;) ). And there is no "way to go about this" per se. But there are widely accepted techniques that are time-proven to work (as you will see in the first link). There are also specialized tools for when in the need to debug some specific peace of code... but that will always depend on your needs. 回答2: Debugging code is