datetime

问题 I've been trying to convert this specific date format to a string in Python like so: datetime.strptime(‘2017-01-12T14:12:06.000-0500’,'%Y-%m-%dT%H:%M:%S.%f%Z') But it doesn't work. What am I doing wrong? 回答1: Solution for Python 2.7 From the comments it became clear that OP needs a solution for Python 2.7. Apparently, there's no %z in strptime for python 2.7 even though the documentation claims the contrary, the raised error is ValueError: 'z' is a bad directive in format '%Y-%m-%dT%H:%M:%S

问题 My situation is that we store data in a SQL Server database, supporting 2005 on up. When a DateTime value is stored, it is in the local time of the client. I need to be able to get that date back on any other client, anywhere, without respect to whatever time zone that other client might be in. So for instance, when a user in New York enters a DateTime value of "2012-12-20 00:00", I want the user in California to see that very same DateTime value. These DateTime values should not respect the

问题 Is there a way to keep the culture specific date time formatting but force 12/24 hour rendering? I know I can do a lot with the actual date/time format string like HH:mm:ss and hh:mm:ss but I would like to honor the current user culture formatting (i.e. mm/dd/yyyy or yyyy/mm/dd , etc), just force 12/24 hour time rendering. 回答1: I'd probably do something like this: var culture = CultureInfo.CurrentCulture; var pattern = culture.DateTimeFormat.LongTimePattern; // or pick which one you want to

问题 const dt = new Date('2017-12-12'); console.log(format(dt, 'YYYY-MM-DD')); The above code logs 2017-12-11 in the US, but 2017-12-12 in India. I followed this github thread here and tried out things but am not getting the desired results. My expectation is to print the same date irrespective of time zone Why I need this : Consider a scenario involving birthdates. If i am giving some input date, it has to be displayed as same date in all regions irrespective of their timezones. 回答1: You will

问题 const dt = new Date('2017-12-12'); console.log(format(dt, 'YYYY-MM-DD')); The above code logs 2017-12-11 in the US, but 2017-12-12 in India. I followed this github thread here and tried out things but am not getting the desired results. My expectation is to print the same date irrespective of time zone Why I need this : Consider a scenario involving birthdates. If i am giving some input date, it has to be displayed as same date in all regions irrespective of their timezones. 回答1: You will

问题 An ISO 8601 datetime with a timezone is formatted like this: 2018-09-07T05:28:42Z However, I need to represent some dates in my system where the precision is days, not seconds, which means that it would be an ISO 8601 calendar date. Calendar dates are formatted like this: 2018-09-07 In the Wikipedia article about the standard (I don't have access to the standard itself, as you have to pay for that privilege), there is no mention of timezone when discussing dates. It does talk about omitting

问题 I am working in ruby, i ahave an object containing today's datetime from database. I only want time truncating the date. How can i get that? 回答1: Try DateTime#strftime. DateTime.now.strftime("%H:%M") # => "12:17" 回答2: #!/usr/bin/ruby -w time1 = Time.now puts "Current Time : " + time1.hour + ":" + time1.min + ":" + time1.sec Taken from & credit to - This TutorialsPoint Post. 回答3: If you use it really often you can use the gem time_splitter to help you set some accessors of date, time, hour and

问题 I am working in ruby, i ahave an object containing today's datetime from database. I only want time truncating the date. How can i get that? 回答1: Try DateTime#strftime. DateTime.now.strftime("%H:%M") # => "12:17" 回答2: #!/usr/bin/ruby -w time1 = Time.now puts "Current Time : " + time1.hour + ":" + time1.min + ":" + time1.sec Taken from & credit to - This TutorialsPoint Post. 回答3: If you use it really often you can use the gem time_splitter to help you set some accessors of date, time, hour and

问题 In R I have two strings: t <- c("2010-01-01 00:01:02", "2010-01-01 00:02:02") which I convert to POSIX datetimes: dt <- as.POSIXct(t) Taking the difference of the two dt[2] - dt[1] gives: Time difference of 1 mins Cool. But how do I force the time difference to be in, say, seconds? 回答1: > difftime(dt[2], dt[1], units="secs") Time difference of 60 secs 来源： https://stackoverflow.com/questions/7492247/control-posix-time-difference-output-in-r

问题 In R I have two strings: t <- c("2010-01-01 00:01:02", "2010-01-01 00:02:02") which I convert to POSIX datetimes: dt <- as.POSIXct(t) Taking the difference of the two dt[2] - dt[1] gives: Time difference of 1 mins Cool. But how do I force the time difference to be in, say, seconds? 回答1: > difftime(dt[2], dt[1], units="secs") Time difference of 60 secs 来源： https://stackoverflow.com/questions/7492247/control-posix-time-difference-output-in-r