datetime

Adding Time Interval. e.g hours, minutes and seconds

我是研究僧i 提交于 2021-02-08 11:28:26
问题 I am getting time from the response in hours, minutes and seconds like "01:32:34" of multiple objects. I have saved it in a custom date object, where i am saving the date value and the string value, there are a large number of records so i am saving it in my local db and upon retrieving i get the date value in the format 1999-12-31 19:01:04 +0000 whereas my string value which i am getting from response as well is 19:01:04 . now i would like to add all of these values to return a string e.g 1

Adding Time Interval. e.g hours, minutes and seconds

梦想与她 提交于 2021-02-08 11:27:31
问题 I am getting time from the response in hours, minutes and seconds like "01:32:34" of multiple objects. I have saved it in a custom date object, where i am saving the date value and the string value, there are a large number of records so i am saving it in my local db and upon retrieving i get the date value in the format 1999-12-31 19:01:04 +0000 whereas my string value which i am getting from response as well is 19:01:04 . now i would like to add all of these values to return a string e.g 1

Select data within one month prior to each user's last record

喜夏-厌秋 提交于 2021-02-08 11:25:41
问题 Assume I have a table called "Diary" like this: | id | user_id | recorded_at | record | |----|---------|--------------------------|--------| | 20 | 50245 |2017-10-01 23:00:14.765366| 89 | | 21 | 50245 |2017-12-05 10:00:33.135331| 97 | | 22 | 50245 |2017-12-31 11:50:23.965134| 80 | | 23 | 76766 |2015-10-06 11:00:14.902452| 70 | | 24 | 76766 |2015-10-07 22:40:59.124553| 81 | For each user I want to retrieve the latest row and all rows within one month prior to that. In other words, for user_id

Python - Parsing and converting string into timestamp [closed]

本小妞迷上赌 提交于 2021-02-08 11:21:26
问题 Closed . This question is opinion-based. It is not currently accepting answers. Want to improve this question? Update the question so it can be answered with facts and citations by editing this post. Closed 1 year ago . Improve this question I have string in next format: 2017-02-14T09:51:46.000-0600 What is the best approach to parse and convert string into timestamp? I have options to use regular expression or to write my own function for parsing, but are there any builtin methods which can

Syntax to use df.apply() with datetime.strptime [duplicate]

你说的曾经没有我的故事 提交于 2021-02-08 10:25:59
问题 This question already has answers here : How to convert string to datetime format in pandas python? (2 answers) Closed 2 years ago . Consider the following table 'df': date sales 0 2021-04-10 483 1 2022-02-03 226 2 2021-09-23 374 3 2021-10-17 186 4 2021-07-17 35 I would like to convert the column date that is currently a string to a date by using apply() and datetime.strptime() . I tried the following: format_date = "%Y-%m-%d" df["date_new"] = df.loc[:,"date"].apply(datetime.strptime,df.loc[:

How to sum Time from a DataGridView Columns

一个人想着一个人 提交于 2021-02-08 08:59:22
问题 I have a DataGrid with a time column that I need to sum to get the total time, but I can't get that! I'm using this code to try the time sum, with Linq: foreach (DataGridViewRow row in dataGridView1.Rows) { textBox8.Text = dataGridView1.Rows.Cast<DataGridViewRow>() .AsEnumerable() .Sum(x => decimal.Parse(x.Cells["Duracao"].Value.ToString())) .ToString(); } Can anybody help me here? Regards 回答1: Have a look at below code sample. May be it will help you : private void BindGrid() { // Bind Grid

How to calculate business hours between two dates when business hours vary depending on the day in R?

穿精又带淫゛_ 提交于 2021-02-08 08:39:18
问题 I'm trying to calculate business hours between two dates. Business hours vary depending on the day. Weekdays have 15 business hours ( 8:00-23:00 ), saturdays and sundays have 12 business hours ( 9:00-21:00 ). For example: start date 07/24/2020 22:20 (friday) and end date 07/25/2020 21:20 (saturday), since I'm only interested in the business hours the result should be 12.67 hours. Here an example of the dataframe and desired output: start_date end_date business_hours 07/24/2020 22:20 07/25

timezone-dependant systimestamp and timestamp comparison on Oracle

爷,独闯天下 提交于 2021-02-08 08:34:20
问题 I've run into a weird situation. Could someone explain why comparison between timestamp and timestamp behaves as below (it depends on session timezone...). In addition outputed values are identical in all cases. It looks like timestamp inherits timezone from the session for comparison purposes, but for printing it does not? Queries: alter session set time_zone = '-6:0'; select cast(systimestamp as timestamp), systimestamp, case when cast(systimestamp as timestamp) < systimestamp then

Collating timestamped events into date ranges with pandas

99封情书 提交于 2021-02-08 08:00:13
问题 I have a master data frame with batch numbers and a datetime range for which these batches occured like so: BatchNo StartTime Event A Event B BATCH23797 2013-09-06 02:22:00 0 0 BATCH23798 2013-09-06 06:06:00 0 0 BATCH23799 2013-09-06 14:33:00 0 0 BATCH23800 2013-09-06 18:12:00 0 0 BATCH23801 2013-09-06 21:38:00 0 0 And then I have another of timestamps for events that I am interested in. I have multiple ones of these with the data in different formats but end of the day I will have a list of

Difference between dates in SQLDF in R

我只是一个虾纸丫 提交于 2021-02-08 07:37:45
问题 I am using the R package SQLDF and am having trouble finding the number of days between two date time variables. The variables ledger_entry_created_at and created_at are Unix Epochs and when I try to subtract them after casting to julianday , I return a vector of NA 's. I've taken a look at this previous question and didn't find it useful since my answer to be given in SQL for reasons that are outside the scope of this question. If anyone could help me figure out a way to do this inside SQLDF