datediff

问题 I am trying to find a set of date functions. Looks like the Joda http://www.joda.org/joda-time/ Does everything I need, but when I call a simple DateTime dt = new DateTime(); it hangs the Eclipse or Emulator for about 15 seconds. I must be doing something wrong as I haven't found anyone else complaining about it being slow. Short of the Joda jar anyone had a datediff() code sample? 回答1: I can confirm this in version 1, 1.5 and 1.62 ... I got bored after that and instead used Date4J which

问题 Below is a simplified version of the data. Daily transaction list for customer ID SalesData = DATATABLE ( "Customer ID", INTEGER, "Date", DATETIME, "Amount", INTEGER, { { 101245, "2019/04/07", 500 }, { 101245, "2018/08/05", 400 }, { 100365, "2018/07/30", 900 }, { 100365, "2018/02/22", 700 }, { 104300, "2019/04/05", 300 }, { 104300, "2019/04/03", 350 }, { 104300, "2019/04/01", 310 }, { 107804, "2018/11/08", 650 }, { 107804, "2018/11/19", 640 }, { 108040, "2019/01/02", 730 } } ) Objective:

问题 I need to get the result from the table, which the date should be difference of 5 from the current date. ie., specific_date column is present in my table. The format of the date is YYYY-MM-DD . I need the query something like, SELECT * FROM `table_name` WHERE DATEDIFF(NOW(), specific_date) < 5 回答1: It looks like you are trying to do this: WHERE specific_date < (NOW() + 5 days) First of all, think carefully about the boundary cases. These boundary cases can bite your ankles in SQL. Do you

问题 I am doing some work in Excel and am running into a bit of a problem. The instruments I am working with save the date and the time of the measurements and I can read this data into Excel with the following format: A B 1 Date: Time: 2 12/11/12 2:36:25 3 12/12/12 1:46:14 What I am looking to do is find the difference in the two date/time stamps in mins so that I can create a decay curve from the data. So In Excel, I am looking to Make this (if the number of mins in this example is wrong I just

问题 Trying to caulculate the difference in time between two two columns, however time 2 in 'difftime' is in the next.row sample data: structure(list(code = c(10888, 10888, 10888, 10888, 10888, 10888, 10889, 10889, 10889, 10889, 10889, 10889, 10890, 10890, 10890 ), station = c("F1", "F3", "F4", "F5", "L5", "L7", "F1", "F3", "F4", "L5", "L6", "L7", "F1", "F3", "F5"), a = structure(c(1365895151, 1365969188, 1366105495, 1367433149, 1368005216, 1368011698, 1366244224, 1366414926, 1367513240,

问题 Trying to caulculate the difference in time between two two columns, however time 2 in 'difftime' is in the next.row sample data: structure(list(code = c(10888, 10888, 10888, 10888, 10888, 10888, 10889, 10889, 10889, 10889, 10889, 10889, 10890, 10890, 10890 ), station = c("F1", "F3", "F4", "F5", "L5", "L7", "F1", "F3", "F4", "L5", "L6", "L7", "F1", "F3", "F5"), a = structure(c(1365895151, 1365969188, 1366105495, 1367433149, 1368005216, 1368011698, 1366244224, 1366414926, 1367513240,

问题 I'm trying to do the equivalent of the following SQL in Django: SELECT * FROM applicant WHERE date_out - date_in >= 1 AND date_out - date_in <= 6 I can do this as a RAW sql query, but this is becoming frustrating in dealing with a RawQuerySet instead of a regular QuerySet object as I would like to be able to filter it later in the code. 回答1: You can use the extra() method and pass in a where keyword argument. The value of where should be a list that contains the SQL WHERE clause of the query

问题 Using JavaScript, How can I subtract from HH:MM:SS? For example, I have 12:54:45 and I want to subtract 11:35:53 for remaining time in 4732 seconds 回答1: var first = (new Date('Jan 01, 2000 12:54:45')).getTime(); var second = (new Date('Jan 01, 2000 11:35:53')).getTime(); var differenceInSeconds = (second - first) / 1000; // 4732 I chose 2000-01-01 as the date, as it does not matter as long it is the same. We only want to calculate the difference. 回答2: This works (Date.parse('January 1, 1970

问题 I have a gant with start date, end date, and % complete columns. By manually entering a number in the % column the bar representing the task gets shaded. What I want to do is instead of representing % completed, I want to show how much time is left before the end date from today. Start End % Time remaining from TODAY() i.e. 12/01/2014 03/15/2015 (End date has not yet occurred) 12/29/2014 12/29/2014 (Task was started and finished this day) 回答1: Assuming your end date is in column B: =IF(TODAY(

问题 I am trying to output number of days between today and the date I enter so I have a problem I encounter error: "Warning: date_diff() expects parameter 2 to be DateTimeInterface" So what's the problem ? <?php $today=date("y-m-d"); $date=date_create("2016-09-16"); echo date_diff($date,$today); ?> 回答1: Your problem lies in that when using date_diff you have to make sure that you're comparing objects that are actual date objects. Also the return type for date_diff is a DateInterval object. You're