dateadd

how to using dateadd in sqlalchemy with filter?

主宰稳场 提交于 2021-02-05 06:31:28
问题 The sql expression : select * from order where status=0 and adddate(created_time, interval 1 day)>now(); python code: from sqlalchemy.sql.expression import func, text from datetime import datetime closed_orders = DBSession.query(Order).filter(func.dateadd(Order.create_time, text('interval 1 day'))>datetime.now()).all() but it's got wrong. how to do it correctly? thanks REF :Using DATEADD in sqlalchemy 回答1: Try this: from sqlalchemy import func import datetime DBSession.query(Order)\ .filter

How to add days to the current date

ぃ、小莉子 提交于 2020-08-01 09:31:27
问题 I am trying to add days to the current date and its working fine but when I add 360 days to the current date it gives me wrong value. eg: Current Date is 11/04/2014 And I am adding 360 Days to it, it should give me 11/04/2015 but it is showing the same date 11/04/2014. the year is not changing. Here is my code select dateadd(dd,360,getdate()) 回答1: Just do- Select (Getdate()+360) As MyDate There is no need to use dateadd function for adding or subtracting days from a given date. For adding

sql datepart ,dateadd,datediff,DateName函数

荒凉一梦 提交于 2020-03-08 16:14:06
[转载]sql datepart ,dateadd,datediff,DateName函数 (2011-09-13 15:16:56) 转载 ▼ 标签: 转载 分类: SQL语句(oracle,sql) 详细!! 原文地址: sql datepart ,dateadd,datediff,DateName函数 作者: 蓝天碧海 1. 当前系统日期、时间 select getdate() 2. dateadd 在向指定日期加上一段时间的基础上,返回新的 datetime 值 例如:向日期加上2天 select dateadd(day,2,'2004-10-15') --返回:2004-10-17 00:00:00.000 3. datediff 返回跨两个指定日期的日期和时间边界数。 select datediff(day,'2004-09-01','2004-09-18') --返回:17 4. datepart 返回代表指定日期的指定日期部分的整数。 SELECT DATEPART(month, '2004-10-15') --返回 10 5. datename 返回代表指定日期的指定日期部分的字符串 SELECT datename(weekday, '2004-10-15') --返回:星期五 6. day(), month(),year() --可以与datepart对照一下

Sql 中常用日期转换Convert(Datetime)

我们两清 提交于 2020-03-02 11:22:47
CONVERT(data_type,expression[,style]) convert(varchar(10),字段名,转换格式) 说明: 此样式一般在时间类型(datetime,smalldatetime)与字符串类型(nchar,nvarchar,char,varchar) 相互转换的时候才用到. 语句 结果 SELECT CONVERT(varchar(100), GETDATE(), 0) 07 15 2009 4:06PM SELECT CONVERT(varchar(100), GETDATE(), 1) 07/15/09 SELECT CONVERT(varchar(100), GETDATE(), 2) 09.07.15 SELECT CONVERT(varchar(100), GETDATE(), 3) 15/07/09 SELECT CONVERT(varchar(100), GETDATE(), 4) 15.07.09 SELECT CONVERT(varchar(100), GETDATE(), 5) 15-07-09 SELECT CONVERT(varchar(100), GETDATE(), 6) 15 07 09 SELECT CONVERT(varchar(100), GETDATE(), 7) 07 15, 09 SELECT CONVERT

一步一步教你制作销售业绩分析报告

爷,独闯天下 提交于 2020-01-19 20:12:38
在入门案例动态销售报告中已经带领大家入门制作PowerBI可视化报告。本文主题销售业绩分析将继续针对入门案例进行进一步优化,让大家更改的了解和掌握使用PowerBI的功能。优化内容主要有两个:   1、数据分析层面:在可视化报告中单独的一个销售业绩指标是没有意义的,只有通过对比指标才能知道销售业绩指标的好坏。对比方法主要通过同指标不同时间的对比,通过PowerBI智能时间函数,可以更加方便的计算累计销售额(YTD),同比(与去年同期对比),环比(与上月对比)等指标。   2、图表层面:使用KPI图表可以更加直观的显示业绩完成状况。通过对同比,环比格式设置可以进行分阶段显示数据。   本文的数据源主要包含有销售明细数据,销售目标数据,以及日期数据源。   销售明细数据   销售目标数据   日期数据   一、创建日期表   日期表作为时间智能函数的基础表,PowerBI可以自动未具有日期或日期时间类型的字段自动创建一个隐藏的日期表。动手操作PowerBI的小伙伴们应该都已经发现了这个功能。软件自带的日期表开启方式如下图:(打开路径:文件=》选项和设置=》选项=》数据加载,默认已勾选自动日期/时间)   上图中的自动日期表并不能够很好的满足不同的业务场景需求,在模型复杂的情况下也会导致文件体积偏大,我们可以通过手动创建日期表。接下来我会教大家创建日期表的三种方式。   1

Is it possible to use values from another table as the interval in a DATEADD function?

杀马特。学长 韩版系。学妹 提交于 2020-01-16 08:48:27
问题 I have a table of events containing a date (smalldatetime). I have a table of intervals (int) (days before) for when a reminder should be sent - DATEADD(D, *interval*, GETDATE()) . I'm trying to write an SQL statement to get all the events where a reminder should be sent today (based on GETDATE() from the DATEADD function. This is instead of me first getting all the intervals and running SQL in a loop, passing each interval as a parameter into the DATEADD function. Any ideas how I'd do this?

Incrementing one day to date in SQL Developer

柔情痞子 提交于 2020-01-16 00:55:13
问题 data_var := dateadd(day,1,data_var); I'm trying this to increment one day to data_var but I keep getting this error 'identifier 'dateadd' must be declared'. I searched all around and found nothing to help me deal with this issue. Help? 回答1: By your mention of SQL Developer I'm going to assume you're using Oracle. If this is the case then the error makes complete sense as the function DATEADD() does not exist . It's always worth searching the documentation if you have a problem; in this

Adding years to a date resets to 1970-01-01

送分小仙女□ 提交于 2020-01-09 11:19:32
问题 $somedate = "1980-02-15"; $otherdate = strtotime('+1 year', strtotime($somedate)); echo date('Y-m-d', $otherdate); outputs 1981-02-15 and $somedate = "1980-02-15"; $otherdate = strtotime('+2 year', strtotime($somedate)); echo date('Y-m-d', $otherdate); outputs 1982-02-15 but $somedate = "1980-02-15"; $otherdate = strtotime('+75 year', strtotime($somedate)); echo date('Y-m-d', $otherdate); outputs 1970-01-01 How to fix? 回答1: It's the 2038 bug which is like y2k where systems can't handle dates

SQL Server: convert to today then add 8 hours

对着背影说爱祢 提交于 2020-01-05 07:13:14
问题 nextUpdate can be any date time value in the past. I'm trying to update the nextUpdate field to today's date but keeping the time unchanged and then add 8 hours. I get error converting string to datetime T-SQLe: UPDATE business.dbo.db_schedule SET nextUpdate = DATEADD(hh, 8, CONVERT(datetime, CONVERT(VARCHAR(8), GETDATE(), 111) + ' ' + CONVERT(VARCHAR(8), nextUpdate, 108), 111)) WHERE sno = 8 datetime format in my location is 111 回答1: UPDATE business.dbo.db_schedule SET nextUpdate= DATEADD(hh