date

The maximum recursion 100 has been exhausted

只愿长相守 提交于 2020-04-17 19:03:34
问题 When I run this query I am getting error when I increase the date to be above months with calender_cte as ( select convert(date, '2019-01-01') as startdate, convert(date, '2019-12-31') as enddate union all select dateadd(day, 1, startdate), enddate from calender_cte cc where startdate < enddate ) SELECT DATEADD (week, datediff(week, 0, cc.StartDate), -1) as 'WeekOf', DATEADD (week, datediff(week, 0, cc.StartDate), +5) as 'to' --ISNULL(DATEPART(wk, Inter.StartDate), 0) as 'WeekNumber' FROM

The maximum recursion 100 has been exhausted

走远了吗. 提交于 2020-04-17 19:03:29
问题 When I run this query I am getting error when I increase the date to be above months with calender_cte as ( select convert(date, '2019-01-01') as startdate, convert(date, '2019-12-31') as enddate union all select dateadd(day, 1, startdate), enddate from calender_cte cc where startdate < enddate ) SELECT DATEADD (week, datediff(week, 0, cc.StartDate), -1) as 'WeekOf', DATEADD (week, datediff(week, 0, cc.StartDate), +5) as 'to' --ISNULL(DATEPART(wk, Inter.StartDate), 0) as 'WeekNumber' FROM

Convert date to ISO week date

吃可爱长大的小学妹 提交于 2020-04-16 05:47:14
问题 How to convert dates to ISO week date in Impala SQL? For example 2019-12-30 in the ISO week date calendar would be written as 2020-W01-1 or 2020W011 ANSWER: Marked Gordon Linoff answer as correct, as it solves the essential part of the question, the deducing of the year part of ISO week date. For the week part of the ISO week date there is a ready function, and the day part of the ISO week date can be easily converted from Sunday starting week to Monday starting week. The query below contains

Why am I getting “unrecognised argument to dateFromString: 'format'” despite having db version >3.6 which supports the aggregation

南笙酒味 提交于 2020-04-16 03:11:11
问题 I have some dates that are string formatted like this in chats: "_id" : ObjectId("2bfd5d45348ef655b5236d93"), "status" : "closed", "context" : "Chats", "chats" : { "time_initialized" : "2019-02-20T17:35:39.960284505Z", "time_responded" : "2019-02-20T17:42:06.691469546Z", "time_closed" : "2019-02-20T17:44:10.158421784Z" } My DB version in mongo is 3.6.5: In the Mongo documentation, you can see below that the function dateFromString is supported: Here's my code that is failing with: "errmsg" :

Adjust a PHP date to the current year

人走茶凉 提交于 2020-04-16 02:47:05
问题 I have a PHP date in a database, for example 8th August 2011. I have this date in a strtotime() format so I can display it as I please. I need to adjust this date to make it 8th August 2013 (current year). What is the best way of doing this? So far, I've been racking my brains but to no avail. 回答1: strtotime( date( 'd M ', $originaleDate ) . date( 'Y' ) ); This takes the day and month of the original time, adds the current year, and converts it to the new date. You can also add the amount of

javascript user value convert to format [duplicate]

元气小坏坏 提交于 2020-04-11 18:30:40
问题 This question already has answers here : How to convert 12-Jan-2016 like date string in javascript to 2016-01-12 00:00:00 (3 answers) Closed 3 years ago . var t = "Jan. 20, 2017 20:28:53" var s = t.format("%m/%d/%Y %H:%M:%S"); alert(s); How I convert the value into the 01/20/2017 20:28:53 this format.Please help me. Thank you... 回答1: Try the moment library http://momentjs.com/ You can do moment('Jan. 20, 2017 20:28:53').format('MM/DD/YYYY HH:mm:ss') returns -> '01/20/2017 20:28:53 PM' 回答2:

R: how can I split one row of a time period into multiple rows based on day and time

大兔子大兔子 提交于 2020-04-11 13:05:06
问题 I am trying to split rows in an excel file based on day and time. The data is from a study which participants will need to wear a tracking watch. Each row of the data set is started with participants put on the watch (Variable: 'Wear Time Start ') and ended with them taking off the device (Variable: 'Wear Time End'). I need to calculate how many hours of each participant wearing the device on each day (NOT each time period in one row). Data set before split: ID WearStart WearEnd 1 01 2018-05

MongoDb BSON stores Date in UTC time

允我心安 提交于 2020-04-10 02:56:03
问题 If I try to put a date field in a Document (BSON) and write it to Mongo, BSON writes it in UTC. For example, a date DateTime dateTime = new DateTime("2015-07-01"); Document doc = new Document("date", dateTime.toDate()); will be stored as "date" : ISODate("2015-06-30T18:30:00Z") in Mongo. And, if I retrieve it using the same Java Driver I get it as Wed Jul 01 00:00:00 IST 2015 Great. Is there no solution to this? I mean, why can't I store my date as I want it? What If I need to query on the DB

MongoDb BSON stores Date in UTC time

走远了吗. 提交于 2020-04-10 02:55:13
问题 If I try to put a date field in a Document (BSON) and write it to Mongo, BSON writes it in UTC. For example, a date DateTime dateTime = new DateTime("2015-07-01"); Document doc = new Document("date", dateTime.toDate()); will be stored as "date" : ISODate("2015-06-30T18:30:00Z") in Mongo. And, if I retrieve it using the same Java Driver I get it as Wed Jul 01 00:00:00 IST 2015 Great. Is there no solution to this? I mean, why can't I store my date as I want it? What If I need to query on the DB

MongoDb BSON stores Date in UTC time

﹥>﹥吖頭↗ 提交于 2020-04-10 02:54:10
问题 If I try to put a date field in a Document (BSON) and write it to Mongo, BSON writes it in UTC. For example, a date DateTime dateTime = new DateTime("2015-07-01"); Document doc = new Document("date", dateTime.toDate()); will be stored as "date" : ISODate("2015-06-30T18:30:00Z") in Mongo. And, if I retrieve it using the same Java Driver I get it as Wed Jul 01 00:00:00 IST 2015 Great. Is there no solution to this? I mean, why can't I store my date as I want it? What If I need to query on the DB