date

问题 I have the following data.frame: grp nr yr 1: A 1.0 2009 2: A 2.0 2009 3: A 1.5 2009 4: A 1.0 2010 5: B 3.0 2009 6: B 2.0 2010 7: B NA 2011 8: C 3.0 2014 9: C 3.0 2019 10: C 3.0 2020 11: C 4.0 2021 Desired output: grp nr yr nr_roll_period_3 1 A 1.0 2009 NA 2 A 2.0 2009 NA 3 A 1.5 2009 NA 4 A 1.0 2010 NA 5 B 3.0 2009 NA 6 B 2.0 2010 NA 7 B NA 2011 NA 8 C 3.0 2014 NA 9 C 3.0 2019 NA 10 C 3.0 2020 NA 11 C 4.0 2021 3.333333 The logic: I want to calculate a rolling mean for the period of length k

问题 I have the following data.frame: grp nr yr 1: A 1.0 2009 2: A 2.0 2009 3: A 1.5 2009 4: A 1.0 2010 5: B 3.0 2009 6: B 2.0 2010 7: B NA 2011 8: C 3.0 2014 9: C 3.0 2019 10: C 3.0 2020 11: C 4.0 2021 Desired output: grp nr yr nr_roll_period_3 1 A 1.0 2009 NA 2 A 2.0 2009 NA 3 A 1.5 2009 NA 4 A 1.0 2010 NA 5 B 3.0 2009 NA 6 B 2.0 2010 NA 7 B NA 2011 NA 8 C 3.0 2014 NA 9 C 3.0 2019 NA 10 C 3.0 2020 NA 11 C 4.0 2021 3.333333 The logic: I want to calculate a rolling mean for the period of length k

问题 I have the following data.frame: grp nr yr 1: A 1.0 2009 2: A 2.0 2009 3: A 1.5 2009 4: A 1.0 2010 5: B 3.0 2009 6: B 2.0 2010 7: B NA 2011 8: C 3.0 2014 9: C 3.0 2019 10: C 3.0 2020 11: C 4.0 2021 Desired output: grp nr yr nr_roll_period_3 1 A 1.0 2009 NA 2 A 2.0 2009 NA 3 A 1.5 2009 NA 4 A 1.0 2010 NA 5 B 3.0 2009 NA 6 B 2.0 2010 NA 7 B NA 2011 NA 8 C 3.0 2014 NA 9 C 3.0 2019 NA 10 C 3.0 2020 NA 11 C 4.0 2021 3.333333 The logic: I want to calculate a rolling mean for the period of length k

问题 What is the best way to determine the short date format for the current given locale? For example, if my script's locale was set to Dutch, I would like to somehow obtain the short date format used in that specific locale, it would be: dd-mm-yyyy If it was set to American, I would like to get the date format in the American locale: mm/dd/yyyy And so on... 回答1: You can use the Intl PHP extension to format the date according to the chosen locale: $locale = 'nl_NL'; $dateObj = new DateTime;

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 17 days ago . Improve this question So I have a date value I had to convert to a timestamp in order to pass the value to a specific method. However, in order to finish the work, I've been told the value of the timestamp's date has to be set to 1900-01-01. So something like this Date startDate = timesDate

问题 I've the date in format: YYYY-MM-DD Output format required is: "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'" And I want to get the date in ISO format as Start time of the day(starts from 12:00AM) and end time of the day(ends on 11:59PM) in America/Chicago timezone. For eg. For the date: 2020-06-08 (June 8) the converted final output is like: Start time of the day as Date: 2020-06-08T05:00:00.000Z End time of the day as Date: 2020-06-09T04:59:59.999Z Please help me here if anybody has any clue for the same.

问题 Is it possible to change the commit date from my commit to the author date? I adapted some commits and now the dates are all the same. I want to set it back to the old dates (or the author dates). Is this possible? I am using Sourcetree so I have the git command line but I am not a pro at that. My external repository is bitbucket. 回答1: Since git 1.6.3 git rebase has --committer-date-is-author-date for this purpose. git rebase --committer-date-is-author-date Original answer: There's no easy

问题 Is it possible to change the commit date from my commit to the author date? I adapted some commits and now the dates are all the same. I want to set it back to the old dates (or the author dates). Is this possible? I am using Sourcetree so I have the git command line but I am not a pro at that. My external repository is bitbucket. 回答1: Since git 1.6.3 git rebase has --committer-date-is-author-date for this purpose. git rebase --committer-date-is-author-date Original answer: There's no easy

问题 I'm getting a value error saying my data does not match the format when it does. Not sure if this is a bug or I'm missing something here. I'm referring to this documentation for the string format. The weird part is if I write the 'data' Dataframe to a csv and read it in then call the function below it will convert the date so I'm not sure why it doesn't work without writing to a csv. Any ideas? data['Date'] = pd.to_datetime(data['Date'], format='%d-%b-%Y') I'm getting two errors TypeError:

问题 I'd like to record the history of her entry into the textfield. I intend to register this with UserDefaults. But when I try to save it with UserDefaults, "cannot assign value of type 'nsdate'?'to type 'String' " Error. I don't think it's accepting textfield data because it's string. And how can I keep history in memory? formatteddate and formatteddate2 give this error. The date output is as follows : 20/04/2019 20:23 let token = try? keychain.getString("chipnumbernew") chip1InfoString = token