date

问题 Currently i take today date using below.I need to get yesterday date using this.. how can i get that ? my $today = `date "+%Y-%m-%d"`; 回答1: If you want yesterday's date: use DateTime qw( ); my $yday_date = DateTime ->now( time_zone => 'local' ) ->set_time_zone('floating') ->truncate( to => 'days' ) ->subtract( days => 1 ) ->strftime('%Y-%m-%d'); For example, in New York, at 2019-05-14 01:00:00, it will give 2019-05-13. For example, in New York, at 2019-11-04 00:00:00, it will give 2019-11-03.

问题 I'm developing a spring boot application that handles dates. When I submit an Appointment object that has a startDateTime and an endDateTime (Both are of type java.util.Date ) I send a format like this: { "lastName": "Jhon", "firstName": "Doe", "email": "jhon.doe@gmail.com", "description": "MyDescription", "startDateTime": "2017-10-09T22:43:07.109+0300", "endDateTime": "2017-10-09T21:40:07.109+0300", } When data is persisted in database it's with the correct timezone, when I try to retrieve

问题 I'm developing a spring boot application that handles dates. When I submit an Appointment object that has a startDateTime and an endDateTime (Both are of type java.util.Date ) I send a format like this: { "lastName": "Jhon", "firstName": "Doe", "email": "jhon.doe@gmail.com", "description": "MyDescription", "startDateTime": "2017-10-09T22:43:07.109+0300", "endDateTime": "2017-10-09T21:40:07.109+0300", } When data is persisted in database it's with the correct timezone, when I try to retrieve

问题 Looking to leverage datetime to get the date of beginning and end of the previous week, sunday to saturday. So, if it's 8/12/13 today, I want to define a function that prints: Last Sunday was 8/4/2013 and last Saturday was 8/10/2013 How do I go about writing this? EDIT: okay, so there seems to be some question about edge cases. For saturdays, I want the same week, for anything else, I'd like the calendar week immediately preceding today 's date. 回答1: datetime.date.weekday returns 0 for Monday

问题 Looking to leverage datetime to get the date of beginning and end of the previous week, sunday to saturday. So, if it's 8/12/13 today, I want to define a function that prints: Last Sunday was 8/4/2013 and last Saturday was 8/10/2013 How do I go about writing this? EDIT: okay, so there seems to be some question about edge cases. For saturdays, I want the same week, for anything else, I'd like the calendar week immediately preceding today 's date. 回答1: datetime.date.weekday returns 0 for Monday

问题 Hopefully I can get some help on this. Situation There are two incoming stations and one outgoing station. Items are scanned in and out. I need to know how long an item was in the station. Let's consider 'in station' to be the time between it's incoming date scan and it's outgoing date scan. Problem An item can be (accidentally) scanned multiple times into either station (for this I was thinking of identifying if a scan was made the same day (not looking at hours) then return the earliest

问题 Hopefully I can get some help on this. Situation There are two incoming stations and one outgoing station. Items are scanned in and out. I need to know how long an item was in the station. Let's consider 'in station' to be the time between it's incoming date scan and it's outgoing date scan. Problem An item can be (accidentally) scanned multiple times into either station (for this I was thinking of identifying if a scan was made the same day (not looking at hours) then return the earliest

问题 Can anyone of you help in converting the date from 20150101 to abbreviated form Jan-2015 ? I tried the below method. x = 20150101 zoo::as.yearmon(x, "%b-%y") But I got the below error Error in charToDate(x) : character string is not in a standard unambiguous format Any help would be very much appreciated. 回答1: There are two problems with the code in the question: the input format is specified as "%b-%y" but should be "%y%m" we wish to use as.yearmon.character here rather than as.yearmon

问题 I am trying to add hh:mm:ss with the date. How can i do it? I tried with the following but it works when the hour is string, but when adding time is similar to MySQL Date time it is not working. $new_time = date("Y-m-d H:i:s", strtotime('+5 hours')); I am trying to get solution for the following: $timeA= '2015-10-09 13:40:14'; $timeB = '03:05:01'; // '0000-00-00 03:05:01' OutPut: $timeA + $timeB = 2015-10-09 16:45:15 ? How Can I Add this? 回答1: Use DateInterval(): $timeA = new DateTime('2015

问题 I am just trying to extract the date's year , month and day separately so that I can use it as per my wish. I stored the current date in $today and used substr() to extract the strings from it. But I am getting some strange behaviour from what I am doing. My current code: $today = date("Y/m/d"); $_year = substr($today, 0,4); $_month = substr($today, 5,7); $_day = substr($today, 8, 10); echo $_year . " " . $_month; The $_year works correctly as expected but the problem arises from $_month , no