data-extraction

How to explode an array of strings and store results in another array (php)

99封情书 提交于 2019-12-11 02:29:44
问题 Have text file in format: (400, 530); 6.9; 5.7; 5.0;//------> continues for 100 values. (500, 530); 7.9; 5.1; 5.0; (600, 530); 6.7; 6.7; 7.2; Code: <?php $file="./Speed10.asc"; $document=file_get_contents($file); $rows = explode ('(', $document); //splits document into rows foreach ($rows as &$rowvalue) { explode (';', $rowvalue);<----- How to assign each of these to member of an array?? } } ?> I'm trying to create 2D array, by splitting first into rows, then by element split by ';' 回答1:

Web scrapping in R through Google playstore

纵饮孤独 提交于 2019-12-11 01:46:26
问题 I want to scrap data from google play store of several app's review in which i want. 1) name field 2) How much star they got 3) review they wrote This is the snap of the senerio #Loading the rvest package library('rvest') #Specifying the url for desired website to be scrapped url <- 'https://play.google.com/store/apps/details?id=com.phonegap.rxpal&hl=en_IN' #Reading the HTML code from the website webpage <- read_html(url) #Using CSS gradient_Selector to scrap the name section Name_data_html <

Unable to extract date of birth from a given format

孤街浪徒 提交于 2019-12-08 23:16:35
I have a set of text files from which I have to extract date of birth. The below code is able to extract date of birth from most of the files but is getting failed when given in the below format. May I know how could I extract DOB? The data is very much un-uniform. Data: data=""" Thomas, John - DOB/Sex: 12/23/1955 11/15/2014 11:53 AM" Jacob's Date of birth is 9/15/1963 Name:Annie; DOB:10/30/1970 Code: import re pattern = re.compile(r'.*DOB.*((?:\d{1,2})(?:(?:\/|-)\d{1,2})(?(?:\/|-)\d{2,4})).*',re.I) matches=pattern.findall(data) for match in matches: print(match) expected output: 12/23/1955

How to read file.rar directly from website in R

牧云@^-^@ 提交于 2019-12-08 07:08:42
问题 I wanted to download a file that zipped in open-plaques-all-2017-06-19.rar, but failed to implement it in R. Please have a look at my code below temp <- tempfile() download.file("https://github.com/tuyenhavan/Statistics/blob/master/open-plaques-all-2017-06-19.rar", temp) df<- fread(unzip(temp, files = "open-plaques-all-2017-06-19.csv")) head(df) 回答1: For these respective platforms/pkg managers you'll need: deb: libarchive-dev (Debian, Ubuntu, etc) rpm: libarchive-devel (Fedora, CentOS, RHEL)

How to read some data from a Windows application memory?

匆匆过客 提交于 2019-12-08 06:13:24
问题 I have an application, which displays me some data. I need to attach to this app's process, find the data I need in memory (one single number, actually), and save it somewhere. This application doesn't seem to use standard windows controls, so things aren't going to be as simple as reading controls data using AutoIt or something similar. Currently I'm a self-learner database guy and have quite shallow knowledge about windows apps debugging. Not even sure if I asked my question correctly

How can I speed up extraction of the proportion of land cover types in a buffer from a raster?

人走茶凉 提交于 2019-12-07 04:07:26
问题 I would like to extract spatial data in a buffer of 10 km around 30 000 objects of class SpatialLines and calculate proportion of each land cover type around buffered lines. In a first time, I used the function crop to crop my raster. Then, I used the function extract (package raster) to calculate proportion of 10 land cover types. Here is my code: lapply(1:nrow(tab_lines), FUN=function(k){ First step: to build a buffer of 10 km around the line buf_line <- gBuffer(seg_line[k], width=10000) ##

How can I extract/parse tabular data from a text file in Perl?

北城余情 提交于 2019-12-06 01:06:06
问题 I am looking for something like HTML::TableExtract, just not for HTML input, but for plain text input that contains "tables" formatted with indentation and spacing. Data could look like this: Here is some header text. Column One Column Two Column Three a b a b c Some more text Another Table Another Column abdbdbdb aaaa 回答1: Not aware of any packaged solution, but something not very flexible is fairly simple to do assuming you can do two passes over the file: (the following is partially

How can I speed up extraction of the proportion of land cover types in a buffer from a raster?

一笑奈何 提交于 2019-12-05 06:39:07
I would like to extract spatial data in a buffer of 10 km around 30 000 objects of class SpatialLines and calculate proportion of each land cover type around buffered lines. In a first time, I used the function crop to crop my raster. Then, I used the function extract (package raster) to calculate proportion of 10 land cover types. Here is my code: lapply(1:nrow(tab_lines), FUN=function(k){ First step: to build a buffer of 10 km around the line buf_line <- gBuffer(seg_line[k], width=10000) ## seg_line = Lines objects Second step: to extract land cover types in the buffer from the raster ha <

Paradox database file

ⅰ亾dé卋堺 提交于 2019-12-05 06:09:40
I found paradox database files with different extension. There are db file, mb file, dat file, px file, XG0 file, XG1 file, XG2 file, XG3 file, XG4 file, YG0 file, YG1 file, YG2 file, YG3 file and YG4 file. I already found way to open db file and px file using gnumeric spreadsheet. I found some of needed data from db file. But, rest of data not in db file. So, i have to open rest of files. I cant find software that can read those files. manlio Unfortunately, Borland has never documented the Paradox file format, so there's no definitive information available. Anyway: the actual data are in the

Extracting x value given y threshold from polyfit plot (Matlab)

我是研究僧i 提交于 2019-12-04 06:41:50
问题 As shown by the solid and dashed line, I'd like to create a function where I set a threshold for y (Intensity) from that threshold it gives me corresponding x value (dashed line). Very simple but my while statement is off. Any help would be much appreciated! %% Curve fit plotting %% x1 = timeStamps(1:60); % taking timestamps from 1 - 120 given smoothed y1 values y1 = smooth(tic_lin(1:60),'sgolay',1); % Find coefficients for polynomial (order = 4 and 6, respectively) fitResults1 = polyfit(x1'