criteria

How to paginate a JPA Query

 ̄綄美尐妖づ 提交于 2019-12-02 17:11:27
I have a submission table with columns like ID , Name , Code among other properties. My requirement is to search for records based on the mentioned properties and return a paginated set. This is the pseudocode for what I am looking for: searchSubmission(searchFilter sf,pageIndex,noOfRecords) { query = 'from submisssion where code=sf.code or id=sf.id order by id start_from (pageIndex*noOfRecords) limit noOfRecords' return result(); } There seem to be many options like CriteriaBuilder , NamedQuery , etc. Which is the most efficient one in this situation? Chris For all JPA query objects (except

Referring to a Subform from a Query

萝らか妹 提交于 2019-12-02 11:49:22
In MS Access 2010, I have a Query which quotes the following in the Criteria; [Forms]![frm_Add_Item_Subform].[ActiveControl].[Caption] This lets me use the "Caption" text of a Button within the query. The following code is on the Button to capture the click. Private Sub cmdClickMe_Click() Debug.Print Me.cmdClickMe.Caption Debug.Print Screen.ActiveControl.Caption End Sub I obtained information on how to do this at the following StackOverflow URL. use caption of pressed button from main form in query of other form The functionality works ok when used in a Form. But doesn't when its used within a

count with other fields in group by with hibernate

只谈情不闲聊 提交于 2019-12-02 10:57:39
问题 I want to return count of rows with some other fields in a group by with hibernate, and i have not any field in my entity class representing count. for example i have a Payment entity class: class Payment { private Long id; private String totalCode; private String activityCode; private Long amount; // other fields and setter/getters } sql query: select count(*), sum(p.amount), p.total_code, p.activity_code from tb_payment p group by p.total_code,p.activity_code and my hibernate criteria:

Joining on multiple fields in a NHibernate Criteria query

血红的双手。 提交于 2019-12-02 10:09:43
问题 I have a Dept table and a Emp table. I need to join these two table in such a way that the where clause looks something like this: where dept.deptId = emp.DeptId and dept.deptName = emp.empTrainingName I tried this: Criteria criteria = session.createCriteria(Dept.class).createAlias("empMap","id"); Using this, the first where condition i.e. dept.deptId = emp.DeptId is performed. But I am not sure how to compare dept.deptName with emp.empTrainingName . How do I do this using the Criteria API in

How to convert a JPQL with subquery to Criteria API equivalent?

旧巷老猫 提交于 2019-12-02 08:18:44
Have a simple object model made up of 5 entities: Company Organization Address Club Group A Company is associated with a single Organization. (Group and Club are also associated with a single Organization - these are unidirectional, meaning the Organization does not contain a reference to its owner). An Organization may have 0 or more Address(es). A subquery can be used to access Company objects based on a specific zipcode, which is an attribute of an Address. Here is a JPQL query that can access those companies with a specific zipcode. @Query("select p from Company p, Organization org where

JPQL “NOT MEMBER OF” query using criteria API

此生再无相见时 提交于 2019-12-02 07:25:09
Given the following JPA annotated entity classes: @Entity @Table("foo") public class Foo { @Id private int id; @Column(name="name") private String name; @ManyToMany @JoinTable(name = "foo_tags", joinColumns = {@JoinColumn(name = "foo")}, inverseJoinColumns = {@JoinColumn(name = "tag")}) private Collection<Tag> tags; ... } @Entity @Table(name = "tag") public class Tag { @Id private String tag; ... } I'm trying to formulate a query to get all Foo instances that lack a given tag. The following JPQL query does the trick SELECT f FROM Foo f WHERE :tag NOT MEMBER OF f.tags However, I'm having

C++ struct sorting

蓝咒 提交于 2019-12-02 06:28:00
I have a vector of custom Struct that needs to be sorted on different criteria each time Implementing operator < will allow only one criteria But I want to be able to specify sorting criteria each time I call C++ standard sort. How to do that? Please note it is better to be efficient in running time.. Thanks You can define what comparison function to use in each run of the sort algorithm by using the third argument: template <class RandomAccessIterator, class StrictWeakOrdering> void sort(RandomAccessIterator first, RandomAccessIterator last, StrictWeakOrdering comp); A simple example: struct

获取地理位置

有些话、适合烂在心里 提交于 2019-12-02 05:54:16
要添加的权限,多多益善具体哪个我也不知道<uses-permission android:name="android.permission.INTERNET" /><uses-permission android:name="android.permission.READ_EXTERNAL_STORAGE" /><uses-permission android:name="android.permission.WRITE_PROFILE" /><uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /><uses-permission android:name="android.permission.ACCESS_WIFI_STATE" /><uses-permission android:name="android.permission.READ_PHONE_STATE" /><uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" /><uses-permission android:name="android.permission.CAMERA" /><uses-permission android

mybatis使用Example进行条件查询

天涯浪子 提交于 2019-12-02 05:30:08
参考: https://www.cnblogs.com/zhemeban/p/7183061.html Example类是什么? Example类指定如何构建一个动态的where子句. 表中的每个non-BLOB列可以被包括在where子句中. 例子是展示此类用法的最好方式. Example类可以用来生成一个几乎无限的where子句. Example类包含一个内部静态类 Criteria 包含一个用 anded 组合在where子句中的条件列表. Example类包含一个 List 属性,所有内部类Criteria中的子句会用 ored组合在一起. 使用不同属性的 Criteria 类允许您生成无限类型的where子句. 创建 Criteria 对象 可以使用Example类中的 createCriteria() 或者 or() . 如果 Criteria 对象是用 createCriteria() 创建的,它会自动为 List 属性添加一个 Criteria 对象 - 这使得它更容易写一个简单的where子句, 如果您不需要 or 或者其他几个子句组合的话. 用 or(Criteria criteria) 方法创建 Criteria 对象, 方法里的 criteria 对象会被添加进 Criteria 对象的列表中. 重要 我们推荐您只使用 or() 方法创建 Criteria

count with other fields in group by with hibernate

六眼飞鱼酱① 提交于 2019-12-02 05:20:33
I want to return count of rows with some other fields in a group by with hibernate, and i have not any field in my entity class representing count. for example i have a Payment entity class: class Payment { private Long id; private String totalCode; private String activityCode; private Long amount; // other fields and setter/getters } sql query: select count(*), sum(p.amount), p.total_code, p.activity_code from tb_payment p group by p.total_code,p.activity_code and my hibernate criteria: Session session = getCurrentSession(); ProjectionList projectionList = Projections.projectionList();