criteria

问题 The following JPA criteria query succeeds on Hibernate (4.2.7 final). CriteriaBuilder criteriaBuilder=entityManager.getCriteriaBuilder(); CriteriaQuery<Boolean>criteriaQuery=criteriaBuilder.createQuery(Boolean.class); Root<UserTable> root = criteriaQuery.from(entityManager.getMetamodel().entity(UserTable.class)); criteriaQuery.multiselect(root.get(UserTable_.enabled)); ParameterExpression<String>parameterExpression=criteriaBuilder.parameter(String.class); criteriaQuery.where(criteriaBuilder

问题 I have a date and duration. I need to add the duration to date. Date's format is timestamp, duration's - Long (milliseconds). How can I wright criteria to deal this issue? Practically i have something like this: 03-17-2014 21:24:57 + 2523566; 回答1: If you want to do it in Java and have a java.sql.Date and a long: public java.sql.Date dateAdd(java.sql.Date inputDate, long duration) { return new java.sql.Date(inputDate.getTime() + duration); } A java.sql.Timestamp can be used in place of a java

问题 I have a many-to-many relationship in JPA 2.0 provided by Hibernate 4.2.0 CR1 (recently upgraded to Hibernate 4.2.7 final) between Product and Colour as follows. The Product entity class: public class Product implements Serializable { private static final long serialVersionUID = 1L; @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Basic(optional = false) @Column(name = "prod_id") private Long prodId; @JoinTable(name = "prod_colour", joinColumns = { @JoinColumn(name = "prod_id",

问题 So I have a Hibernate entity(lets call it Zoos) with a many-to-many relationship set up like this: @ManyToMany(cascade = {}) @JoinTable(name = "animal", joinColumns = @JoinColumn(name = "zoo_id"), inverseJoinColumns = @JoinColumn(name = "animal_id")) @LazyCollection(LazyCollectionOption.FALSE) public List<Animal> getAnimal() { return animals; } So now I want to find all zoos with the animals "lions", "tigers", and "bears". Now I don't care if they have other animals or not, but I don't want

问题 A database function returns id's of all events within a certain radius, ordered by their distance. Afterwards, to preserve performance I'm eagerly loading necessary collections in withCriteria like this: def events = Event.withCriteria { 'in'('id', ids) fetchMode("someRelation", FetchMode.JOIN) // a few more joins setResultTransformer(CriteriaSpecification.DISTINCT_ROOT_ENTITY) } However this messes up the ordering. I've noticed that the result of this criteria query returns all events sorted

问题 I have a scenario where i use a custom user type for a entity field in hibernate using the org.hibernate.usertype.UserType . It's a date conversion to UTC import org.hibernate.usertype.ParameterizedType; import org.hibernate.usertype.UserType; public final class UTCTimestampType implements ParameterizedType, UserType {..} My entity class is like the below @Entity public class Person extends AbstractPerson { @Column(name = "BIRTH_DT_TM") @Type(type = "com.myexample.hibernate.types

问题 I have these two classes @Table(name="candidateinfo") Class CandidateInfo { .... @OneToMany CandidateResume candidate; .... } @Table(name="candidateResume") Class CandidateResume { .... @ManyToOne CandidateInfo candidates; ....... } Now i want to add two restrictoins from 2 different classes(as above) in the below criteria for this i have Criteria crit = session.createCriteria(CandidateResumeInfo.class); crit.add(Restrictions.eq("resumeSearchable", 1)) ;// resumeSearchable is in

问题 I've got an entity Reminder which contains a collection of ReminderSchedule . This is my mapping: <class xmlns="urn:nhibernate-mapping-2.2" mutable="true" name="Reminder" table="Reminders"> <id name="Code" type="System.Guid"> <column name="ReminderCode" /> <generator class="guid.comb" /> </id> ... <set access="field.pascalcase-underscore" cascade="all-delete-orphan" inverse="true" lazy="false" name="Schedules" mutable="true"> <key foreign-key="FK_Schedules_Reminders"> <column name=

问题 I have an SQL query that I would like to convert into a criteria (Hibernate 3.3.2) to use it into my persistancy layer. That's the query : select last_name from member where member.end_date > SYSDATE group by member.last_name having count(member.last_name) >1; I already try a lot a combinations, but there is no result that would be good for me ... This is my code : Criteria criteria = getSession(false).createCriteria(Member.ENTITY_NAME); criteria.setProjection(Projections.projectionList()

问题 I want to fetch specific column from database by using criteria. select name, lastname from sssssss Please reply Thanks in advance. 回答1: you need to use the projecttion Class.. check this documentation for details.. List results = session.createCriteria(SSSS.class) .setProjection( Projections.projectionList() .add( Projections.property("name") ) .add( Projections.property("lastName") ) ) .list(); 来源： https://stackoverflow.com/questions/6715946/hibernate-fetch-specific-column-from-database