count

Count frequency of each element in vector

孤人 提交于 2021-01-29 03:27:31
问题 I'm looking for a way to count the frequency of each element in a vector. ex <- c(2,2,2,3,4,5) Desired outcome: [1] 3 3 3 1 1 1 Is there a simple command for this? 回答1: rep(table(ex), table(ex)) # 2 2 2 3 4 5 # 3 3 3 1 1 1 If you don't want the labels you can wrap in as.vector() as.vector(rep(table(ex), table(ex))) # [1] 3 3 3 1 1 1 I'll add (because it seems related somehow) that if you only wanted consecutive values, you could use rle instead of table : ex2 = c(2, 2, 2, 3, 4, 2, 2, 3, 4, 4)

How to count the number of occurrence of a word in a column

穿精又带淫゛_ 提交于 2021-01-28 23:30:14
问题 I have a column named word_count which contains the count of all the words in a review. How can I find the number of times the word awesome has occurred in each row of that column and use .apply() method to make it into a new column say awesome . products['word_count'][1] {'and': 3L,'bags': 1L,'came': 1L, 'disappointed.':1L,'does':1L,'early':1L,'highly': 1L,'holder.': 1L, 'awesome': 2L} how can i get the output products['awesome'][1] 2 回答1: What I understood from you is that you have a

Postgresql: count records by time intervals

与世无争的帅哥 提交于 2021-01-28 19:31:54
问题 I am trying to use the following SQL statement with postgresql to generate some report: WITH GRID AS ( SELECT START_TIME, LEAD(START_TIME) OVER (ORDER BY START_TIME) AS END_TIME FROM ( SELECT GENERATE_SERIES('2015-08-01 12:00:00', '2015-09-01 12:00:00', INTERVAL '1 day') AS START_TIME FROM MY_TABLE ) x ) SELECT START_TIME, COUNT(MY_TABLE._ID) AS COUNT FROM GRID LEFT JOIN MY_TABLE ON MY_TABLE.CREATED >= GRID.START_TIME AND MY_TABLE.CREATED < GRID.END_TIME WHERE MY_TABLE.COMPANY_ID = '1001' AND

Java: Why is \n considered 2 characters in a read text file situation?

大城市里の小女人 提交于 2021-01-28 19:19:19
问题 import java.io.*; public class xxx { public static void main(String[] args) throws IOException { FileReader fs = new FileReader("xxx.txt"); int t = fs.read(); int count = 0; while (t!=-1) { count++; t = fs.read(); } System.out.println(count); } } Considering that xxx.txt contains: a b b cccd I'm just confused at why "next line" is considered 2 characters? I manually counted 10 characters (including white space) but the result is a 12. Thank you. 回答1: It is because windows uses 2 characters \r

How do I create N VMs with M disks created and attached per VM?

China☆狼群 提交于 2021-01-28 08:34:08
问题 resource "azurerm_windows_virtual_machine" "virtual_machine" { count = var.vm_count name = "${local.vm_name}${count.index +1}" resource "azurerm_virtual_machine_data_disk_attachment" "datadisk01" { count = var.disk_count **virtual_machine_id = azurerm_windows_virtual_machine.virtual_machine[count.index].id managed_disk_id = element("${module.DISK.datadisk_id}","${count.index}") } Issue - I have 2 diffenent count varaibles vm_count and disk_count. I want a generic solution, Ex. If vm count is

Count Function on Multiple Columns by Date (SQL Server)

爱⌒轻易说出口 提交于 2021-01-28 08:15:46
问题 I'm using SQL Server 2008 R2 and trying to do multiple counts on different columns and can't figure out how to get it to work properly. I have two queries that work independently, but having trouble when trying to combine them. Trying to count the number of tickets opened and closed during each individual date while passing through an @StartDate and @EndDate. For example, here's my first query: (we assign certain codes to differentiate between different reasons tickets are created, just

Check for (whole only) words in string

不问归期 提交于 2021-01-28 01:55:48
问题 Training on Checkio. The task is called Popular words. The task is to search for words from a list (of strings) in a given string. For example: textt="When I was One I had just begun When I was Two I was nearly new" wwords=['i', 'was', 'three', 'near'] My code goes like: def popular_words(text: str, words: list) -> dict: # your code here occurence={} text=text.lower() for i in words: occurence[i]=(text.count(i)) # incorrectly takes "nearly" as "near" print(occurence) return(occurence) popular

add counter column by arranging two variables (dplyr)

点点圈 提交于 2021-01-27 20:53:10
问题 I've been looking for a while here and there but I couldn't find any solution for my situation. I have a data frame with IDs and VAR mixed within it. Here below I tried to reproduced a sample require(dplyr) seed(123) N <- 3 T <- 4 id <- rep(letters[1:N], each = T) var <- rep(sample(seq(1:100),T),N) row <- sample(seq(1:(N*T)),replace = F) dt <- data.frame(ID=id,VAR=var,ROW=row) %>% arrange(ROW) %>% select(-ROW) and I'd like to arrange by ID and VAR and add a counter per group in order to get

Mysql merge count multiple column

て烟熏妆下的殇ゞ 提交于 2021-01-27 19:55:47
问题 I have a table(tb_data) which like this +---------+---------------------+---------------------+---------------------+---------------------+ | Disease | Additional_Disease1 | Additional_Disease2 | Additional_Disease3 | Additional_Disease4 | +---------+---------------------+---------------------+---------------------+---------------------+ | A01 | A03 | A03 | | | | A03 | A02 | | | | | A03 | A05 | | | | | A03 | A05 | | | | | A02 | A05 | A01 | A03 | | +---------+---------------------+------------

What is the difference b/w Countable and Non Countable Objects

天大地大妈咪最大 提交于 2021-01-27 14:26:50
问题 I am trying out to find difference b/w a countable and a non countable object First I found out the Type of object echo gettype($data["current_fiat_currency"]); Which is a Object But when i had checked that it is a countable object or not var_dump($data["current_fiat_currency"] instanceof Countable ); then it returns False Below is the object content var_dump($data["current_fiat_currency"]); object(stdClass)[2010] public 'id' => string '1399' (length=4) public 'currency_name' => string 'US