count

Mean per group and with count of variables in group [duplicate]

早过忘川 提交于 2021-02-05 10:26:50
问题 This question already has answers here : How to use dplyr as alternative to aggregate (2 answers) Count number of rows within each group (15 answers) Closed 1 year ago . I would like to generate a table with groups per range, the mean and the count of variables in each group. I have a data.frame like below: Variable Shap 1 0.10 6 0.50 7 0.30 5 0.40 9 0.10 9 0.25 2 0.24 9 0.23 5 0.22 5 0.21 1 0.20 4 0.19 5 0.18 8 0.17 6 0.16 And would like to get a dataframe like this Range Shap_Avg Counts 0-5

how count in pyspark? [closed]

你。 提交于 2021-02-05 09:46:36
问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 24 days ago . Improve this question I have a huge list of title. I wanna count each title in whole data set. for example: `title` A b A c c c output: title fre A 2 b 1 c 3 回答1: You can just groupBy title and then count : import pyspark.sql.functions as f df.groupBy('title').agg(f.count('*')

R Count How Many Time `auto.arima()` Confirm`arima.sim()` to be True

若如初见. 提交于 2021-02-05 08:42:32
问题 Often times I make use of arima.sim() function to simulate ARIMA model and later discover through auto.arima() function that the ARIMA model simulated is not the same with what I specified in arima.sim() function. I went further to investigate to know how does the arima.sim() fair in simulating ARIMA model by simulating same ARIMA model with the same arima.sim() detail good number of times and then check each out with auto.arima() here. result <- matrix(NA_integer_, nrow = 10, ncol = 3)

Single column with value counts from multiple column dataframe

梦想的初衷 提交于 2021-02-05 06:54:04
问题 I would like to sum the frequencies over multiple columns with pandas. The amount of columns can vary between 2-15 columns. Here is an example of just 3 columns: code1 code2 code3 27 5 56 534 27 78 27 312 55 89 312 27 And I would like to have the following result: code frequency 5 1 27 4 55 1 56 2 78 1 312 2 534 1 To count values inside one column is not the problem, just need a sum of all frequencies in a dataframe a value can appear, no matter the amount of columns. 回答1: You could stack and

sql HAVING max(count()) return zero rows

做~自己de王妃 提交于 2021-02-05 06:48:46
问题 I'm trying to get class rooms with overlap course schedule, my tables: courses: COURSE_ID NAME 11 matematika 22 logika 33 himiya 44 sport 55 algoritmika 66 hedva 77 algebra linearit schedule: ID COURSE_ID ID_ROOM DAY HOUR 1 11 105 Mon 10am 2 11 105 Wen 10am 3 11 105 Thu 10am 4 22 105 Mon 10am 5 22 205 Wen 10am 6 22 105 Thu 10am 7 33 305 Mon 11am 8 33 105 Mon 10am class_room: ID_ROOM LOCATION CAPACITY 105 A 20 205 B 10 305 C 30 My sql is: select class_room.ID_ROOM as crid, class_room.LOCATION,

MongoDB Orders/sales aggregation group Per Month Sum Total + Count Field

戏子无情 提交于 2021-02-05 06:48:25
问题 Who knows a better solution to group Orders by date and sum total and count by source. Of course I can group by Source and then I get only totals for this source only, I can alter the result thereafter to get the desired result. But I would like to know if it is possible in one simple $group statement. Eg. ordersByApp = 1, ordersByWEB = 2 Orders collection { _id: 'XCUZO0', date: "2020-02-01T00:00:03.243Z" total: 9.99, source: 'APP' }, { _id: 'XCUZO1', date: "2020-01-05T00:00:03.243Z" total: 9

MongoDB Orders/sales aggregation group Per Month Sum Total + Count Field

≯℡__Kan透↙ 提交于 2021-02-05 06:47:29
问题 Who knows a better solution to group Orders by date and sum total and count by source. Of course I can group by Source and then I get only totals for this source only, I can alter the result thereafter to get the desired result. But I would like to know if it is possible in one simple $group statement. Eg. ordersByApp = 1, ordersByWEB = 2 Orders collection { _id: 'XCUZO0', date: "2020-02-01T00:00:03.243Z" total: 9.99, source: 'APP' }, { _id: 'XCUZO1', date: "2020-01-05T00:00:03.243Z" total: 9

Get each column count where column value is not NULL

这一生的挚爱 提交于 2021-02-04 19:08:34
问题 I have a table and 5 columns in the table. I want row count for each column where column value is not null. column1 column2 column3 column4 column5 1 2 2 2 2 2 2 2 NULL 2 3 NULL 2 2 NULL NULL NULL 2 2 NULL NULL NULL 2 2 NULL i should get output like 3,2,5,4,2 回答1: How about something like SELECT COUNT(Column1), COUNT(Column2), COUNT(Column3), COUNT(Column4), COUNT(Column5) FROM Table1 SQL Fiddle DEMO From COUNT(expr) Returns a count of the number of non-NULL values of expr in the rows

Get each column count where column value is not NULL

二次信任 提交于 2021-02-04 19:08:33
问题 I have a table and 5 columns in the table. I want row count for each column where column value is not null. column1 column2 column3 column4 column5 1 2 2 2 2 2 2 2 NULL 2 3 NULL 2 2 NULL NULL NULL 2 2 NULL NULL NULL 2 2 NULL i should get output like 3,2,5,4,2 回答1: How about something like SELECT COUNT(Column1), COUNT(Column2), COUNT(Column3), COUNT(Column4), COUNT(Column5) FROM Table1 SQL Fiddle DEMO From COUNT(expr) Returns a count of the number of non-NULL values of expr in the rows

C# list count always returns 1 even when list is empty

萝らか妹 提交于 2021-02-04 17:49:07
问题 I'm trying to debug a method in C# but my basic syntax skills here seem to be lacking! The method accepts a list of dates as a comma-separated text string. This string is converted to a list, then processed. However, it seems that even when an empty string is passed to the method, it still outputs 1 when the list is counted. The code is as follows: public static int DaysLeft(DateTime endDate, DateTime startDate, Boolean excludeWeekends, String excludeDates) { int counter = 0; List<string>