copy

My current implementation uses lots of copy constructors with this syntax MyClass::Myclass(Myclass* my_class) Is it really (functionnaly) different from MyClass::MyClass(const MyClass& my_class) and why? I was adviced that first solution was not a true copy constructor. However, making the change implies quite a lot of refactoring. Thanks!!! It's different in the sense that the first isn't a copy constructor, but a conversion constructor. It converts from a MyClass* to a MyClass . By definition, a copy-constructor has one of the following signatures: MyClass(MyClass& my_class) MyClass(const

Please, suggest me the best way of copying a folder from assets to /data/data/my_app_pkg/files. The folder from assets (www) contains files and subfolders. which I want to completely copy to the files/ of my internal app path mentioned. I am successfully able to copy a file from assets to internal app files/ path, but unable to do the same in case of copying folder, even assetmanager.list isn't helping me out, as it is copying only the files, but not the directories / subfolders. Please kindly suggest me the better way to do what I want duggu Hope use full to you below code:- Copy files from a

Is it possible to copy a module, and then make changes to the copy? To phrase another way, can I inherit from a module, and then override or modify parts of it? To phrase another way, can I inherit from a module, and then override or modify parts of it? Yes. import module You can use stuff from module or override stuff in your script. You can also do this to create a "derived" module. Call this "module_2". from module import * Which imports everything. You can then use stuff from module or override stuff in this new module, "module_2". Other scripts can then do import module_2 And get all the

There are two data frames x, y . Id like to copy row with number J from X into Y. Something like Y[1,] <- X[j,] Your example happens to pretty much answer your question. (Try it out!) If, instead of replacing a row in the target data.frame, you want to add a row to it, try rbind() instead: X <- data.frame(name=LETTERS[1:3], value=1:3, stringsAsFactors=FALSE) Y <- data.frame(name=letters[1:3], value=rnorm(3), stringsAsFactors=FALSE) X[1,] <- Y[1,] X <- rbind(X, Y[3,]) 来源： https://stackoverflow.com/questions/10013985/how-to-copy-row-from-one-data-frame-in-to-another-r

Compiling the following Rust code that uses operator overloading use std::ops::{Add}; #[derive(Show)] struct Point { x: int, y: int } impl Add for Point { type Output = Point; fn add(self, other: Point) -> Point { Point {x: self.x + other.x, y: self.y + other.y} } } fn main() { let p: Point = Point {x: 1, y: 0}; let pp = p + p; } Results in compiler errors due to ownership of p: <anon>:21:18: 21:19 error: use of moved value: `p` <anon>:21 let pp = p + p; ^ <anon>:21:14: 21:15 note: `p` moved here because it has type `Point`, which is non-copyable <anon>:21 let pp = p + p; ^ The rationale

今天用myeclipse上svn更新代码发现报一个异常： Attempted to lock an already-locked dir svn: Working copy 'D:\xxxx\xxxx-webapp' locked 很明显都知道路径： D:\xxxx\xxxx-webapp 锁着了 找到 D:\xxxx\右键 操作如图 然后从新启动tomcat 就ok了！！！！！ 来源： oschina 链接： https://my.oschina.net/u/152736/blog/94168

Is it possible with a STL algorithm to deep copy a std::map values to a std::set? I don't want to explicitly insert in the new set. I don't want to explicitly do this: std::map<int, double*> myMap; //filled with something std::set<double*> mySet; for (std::map<int, double*>::iterator iter = myMap.begin(); iter!=myMap.end(); ++iter) { mySet.insert(iter->second); } but find a more coincise and elegant way to do this, with a deep copy of values. What about this? std::transform(myMap.begin(), myMap.end(), std::inserter(mySet, mySet.begin()), [](const std::pair<int, double*>& key_value) { return

Several OSX clipboard managers from AppStore show the ability to determine the source-application of content that was copied to the clipboard. I am writing some simple clipboard observer and would like to show the source-application icon near the content, stored in general NSPasteboard. And I would like to know how this can be achieved. As far as I can see, NSPasteboard doesn't provide any additional info except types of data and data itself. Maybe there are some events or notifications to know that a 'copy' command was triggered? Or some other ways? I believe that the way CopyLess and Alfred

Possible Duplicate: What's the best way to make a deep copy of a data structure in Perl? In my code i do: @data_new=@data; and then I change @data . The problem is that @data_new always changes as well. It's like @data_new is just a reference to what's in @data . How do i make a copy of an array which is not a reference but a new copy of all the values? @data is a two dimensional array, by the way. cdhowie The code you have will copy the contents of the list to a new list. However, if you are storing references in the list (and you have to in order to create a two-dimensional array in Perl),

I have a class object which contains a vector<unique_ptr> . I want a copy of this object to run non-const functions on. The original copy must remain const . What would the copy constructor for such a class look like? class Foo{ public: Foo(const Foo& other): ??? {} std::vector<std::unique_ptr> ptrs; }; You cannot simply copy a std::vector<std::unique_ptr> because std::unique_ptr is not copyable so it will delete the vector copy constructor. If you do not change the type stored in the vector then you could make a "copy" by creating a whole new vector like std::vector<std::unique_ptr<some_type>