convert

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to convert a base64binary string to a byte array in classic ASP. StrConv() doesn't exist in ASP. My objective is to take the base64binary string received from a web service call, and write the binary format to a file. thanks, -m 回答1: When faced with a similar situation some time ago, I used MSXML to convert the data to a byte array before saving it to a file. You will need version 3 or higher. To do this you would: Load the data with MSXML Set the node's dataType property to bin.base64 Read the binary data from the node using the

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to write a unit test class to test my custom classes. When I am trying to call a method in the custom class with a custom object as the input variable, I got: 'Cannot convert value of type "Person" to expected argument type "Person". "Person" is the class, inherited from NSManagedObject, where the input object was created from. I have no problem with other methods taking other value type. The method works fine. The test class is the only one complains this. Is it a bug or limitation? Any suggestion I can dig deeper on this issue?

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I've been looking at Jackson, but is seems I would have to convert the Map to JSON, and then the resulting JSON to the POJO. Is there a way to convert a Map directly to a POJO? 回答1: Well, you can achieve that with Jackson, too. (and it seems to be more comfortable since you were considering using jackson). Use ObjectMapper 's convertValue method: final ObjectMapper mapper = new ObjectMapper(); // jackson's objectmapper final MyPojo pojo = mapper.convertValue(map, MyPojo.class); No need to convert into JSON string or something else; direct

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm currently attempting to make a media player for audio. I'm currently running lollipop. I ran into a problem setting the dataSource for the media player. First, here's how I set the dataSource: public void playSong() { player.reset(); Song selSong = songs.get(songPos); long currSong = selSong.getId(); //Get Uri of song Uri trackUri = ContentUris.withAppendedId( MediaStore.Audio.Media.EXTERNAL_CONTENT_URI, currSong); try { //Tell the player the song to play player.setDataSource(getApplicationContext(), trackUri); } catch (Exception e) {

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: The following is a contrived example of the actual code: int** Ptr = 0; decltype(Ptr[0]) Test = (int*)0; I get the error: error C2440: 'initializing': cannot convert from 'int *' to 'int *&' I'm not sure why I'm getting that since from my understand of decltype (correct me if I'm wrong) it just takes whatever expression you give it and resolve it to its actual type. In this case Ptr[0] is an int* so I'm expecting: int* Test = (int*)0; What am I missing? Why am I getting that error? 回答1: If we go to the draft C++ standard section 7.1.6.2

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I had the following lines of code long longnum = 555L ; int intnum = 5 ; intnum += longnum ; intnum = intnum + longnum ; //Type mismatch: cannot convert from long to int System . out . println ( "value of intnum is: " + intnum ); I think line-3 and line-4 do same task, then why compiler showing error on line-4 "Type mismatch: cannot convert from long to int" please help. 回答1: That's because the compound assignment operator does implicit casting. From JLS Compound Assignment Operator : A compound assignment expression of the form E1

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: As I am completely lost in the dozens of ways you find on stackoverflow to do timestamp conversions, so I will ask here the complete question: Convert this timestamp from an apache log (in CEST timezone): 30/Aug/2015:05:13:53 +0200 Into this: 1440904433 Using $ python --version Python 2.6.6 Verification: $ date --date @1440904433 Sun Aug 30 05:13:53 CEST 2015 $ date -u --date @1440904433 Sun Aug 30 03:13:53 UTC 2015 Bad results are: 1440911633 1440908033 My current code goes until here: >>> from dateutil import parser >>> parser.parse("30

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I know something like this can be accomplished easily using PHP or Perl, but I want to know if there's a way to do it directly on Informix, something like the function FROM_UNIXTIME() on MySQL. 回答1: I think you can do it using dbinfo with 'utc_to_datetime' as a parameter: http://publib.boulder.ibm.com/infocenter/idshelp/v115/index.jsp?topic=%2Fcom.ibm.sqls.doc%2Fids_sqs_1484.htm 文章来源: Is there a direct way to convert Unix Time on Informix to YYYY-MM-DD HH:MM:SS?

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a JODA DateTime 2012-12-31T13:32:56.483+13:00 . I would like to convert it to Date in dd/MM/yy format. So I'm expecting code to return Date like - 31/12/12. Code - // Input dateTime = 2012-12-31T13:32:56.483+13:00 SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/MM/yy"); Date date = simpleDateFormat.parse(dateTime.toString("dd/MM/yy")); Results: Output - Mon Dec 31 00:00:00 NZDT 2012 Expected Output - 31/12/12 When I do the following, I get the expected output but I don't know how to convert it to Date- String string =

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I want to convert an integer i to a logical vector with an i-th non-zero element. That can de done with 1:10 == 2 , which returns 0 1 0 0 0 0 0 0 0 0 Now, I want to vectorize this process for each row. Writing repmat(1:10, 2, 1) == [2 5]' I expect to get 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 But instead, this error occurs: Error using == Matrix dimensions must agree. Can I vectorize this process, or is a for loop the only option? 回答1: You can use bsxfun : >> bsxfun(@eq, 1:10, [2 5].') ans = 0 1 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 Note the