convert

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to convert python opencv image to QPixmap. I follow the instruction shows Page Link and my code is attached below img = cv2.imread('test.png')[:,:,::1]/255. imgDown = cv2.pyrDown(img) imgDown = np.float32(imgDown) cvRGBImg = cv2.cvtColor(imgDown, cv2.cv.CV_BGR2RGB) qimg = QtGui.QImage(cvRGBImg.data,cvRGBImg.shape[1], cvRGBImg.shape[0], QtGui.QImage.Format_RGB888) pixmap01 = QtGui.QPixmap.fromImage(qimg) self.image01TopTxt = QtGui.QLabel('window',self) self.imageLable01 = QtGui.QLabel(self) self.imageLable01.setPixmap(pixmap01)

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 由 翻译 强力驱动 问题: I want to take a string that represents a path and convert it to an absolute Unix-style path. This string could be in either Windows or Unix styles, as it's the result of a call to MainClass.class.getClassLoader().getResource("").getPath() , which returns different style paths depending on your system. (I'm doing this for a game I'm writing, a portion of which gives the user a simple "bash-ish" shell, and I want the user to be able to read files. The fake filesystem is stored as a normal directory tree in a subdirectory of my

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 选择语言 中文(简体) 日语 英语 中文(繁体) 由 翻译 强力驱动 问题: I have a very large dataframe that I would like to avoid iterating through every single row and want to convert the entire column from hex string to int. It doesn't process the string correctly with astype but has no problems with a single entry. Is there a way to tell astype the datatype is base 16? IN : import pandas as pd df = pd . DataFrame ([ '1C8' , '0C3' ], columns =[ 'Command0' ]) df [ 'Command0' ]. astype ( int ) OUT : ValueError : invalid literal for int () with base10 : '1C8' This works but want

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm attempting to convert a Jpeg file with, 200 dpi, to a PDF file, however, when I save the file as a PDF I think it's changing the dpi to 72, and thus making the image larger. I had a similar problem when initially trying to scale my jpeg image to a smaller size, and was able to solve that by specifying the dpi when I save the image. im = Image.open("Image.jpg") dpi=im.info['dpi'] if im.size == (2592, 1728): out = im.resize((1188,792), Image.ANTIALIAS) elif im.size == (1728,2592): out = im.resize((792,1188), Image.ANTIALIAS) out.save

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm using C (not C++). I need to convert a float number into an int . I do not want to round to the the nearest number, I simply want to eliminate what is after the integer part. Something like 4.9 -> 4 .9 -> 4 回答1: my_var = (int)my_var; As simple as that. Basically you don't need it if the variable is int. 回答2: Use in C int C = var_in_float; They will convert implicit Thank you 文章来源: C convert floating point to int

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm using net/http and json to geocode an address using google's Geocoding API. Here is where the error is being thrown: response = Net::HTTP.get_response(URI.parse(url)) result = JSON.parse(response) The response is of class Net::HTTPOK, but I want to access the actual JSON response data (not just the status code). 回答1: You want result = JSON.parse(response.body) http://www.ruby-doc.org/stdlib-1.9.3/libdoc/net/http/rdoc/Net/HTTPResponse.html 文章来源: TypeError: can't convert Net::HTTPOK into String

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am new to libav and I am writing a video manipulation software which uses opencv as its heart. What I did is briefly as below: 1- read the video packet 2- decode the packet into AVFrame 3- convert the AVFrame to CV Mat 4- manipulate the Mat 5- convert the CV Mat into AVFrame 6- encode the AVFrame into AVPacket 7- write the packet 8- goto 1 I read dranger tutorial in http://dranger.com/ffmpeg/tutorial01.html and I also used decoding_encoding example. I can read the video, extract video frames and convert them to CV Mat. My problem starts

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: You'd like to call a stored proc on MS SQL that has a parameter type of TIMESTAMP within T-SQL, not ADO.NET using a VARCHAR value (e.g. '0x0000000002C490C8'). What do you do? UPDATE: This is where you have a "Timestamp" value coming at you but exists only as VARCHAR. (Think OUTPUT variable on another stored proc, but it's fixed already as VARCHAR, it just has the value of a TIMESTAMP). So, unless you decide to build Dynamic SQL, how can you programmatically change a value stored in VARCHAR into a valid TIMESTAMP? 回答1: A timestamp datatype is

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: In my Java application, I was able to get the value of JButton color in terms of Red, Green, Blue values; I have stored these values in three integers. How to convert RGB values into the equivalent hexadecimal value? Example of that like in this format #0033fA 回答1: You can use String hex = String.format("#%02x%02x%02x", r, g, b); Use capital X's if you want your resulting hex-digits to be capitalized ( #FFFFFF vs. #ffffff ). 回答2: A one liner but without String.format: Color your_color = Color.BLACK; String hex = "#"+Integer.toHexString(your

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: How can I transfer uint64_t value to std::string? I need to construct the std::string containing this value For example something like this: void genString(uint64_t val) { std::string str; //.....some code for str str+=(unsigned int)val;//???? } Thank you 回答1: use either boost::lexical_cast or std::ostringstream e.g.: str += boost::lexical_cast<std::string>(val); or std::ostringstream o; o << val; str += o.str(); 回答2: In C++ 11 you may just use: std::to_string() it's defined in header http://www.cplusplus.com/reference/string/to_string/ 回答3: