controller

Get ActionResult of another controller-action?

感情迁移 提交于 2020-01-13 16:32:20
问题 I want to store items in the application cache so it's lazy loaded from the main layout view. I also want to be able to invalidate the cache, so if it's invalid, next time when the items-collection is requested, it's reloaded to that cache location. Here's what I've implemented: In the controller: protected IEnumerable<Slide> CachedSlides { get { return HttpContext.Application[SlidesCacheKey] as IEnumerable<Slide>; } set { HttpContext.Application[SlidesCacheKey] = value; } } private void

Route to controller in subfolder not working in Laravel 4

我是研究僧i 提交于 2020-01-13 08:49:26
问题 I was updating my Laravel 3 app to Laravel 4 when I hit this problem... Routes I have tried: Route::get('backend/login', 'backend/UserController@login'); Route::get('backend/login', 'backend.UserController@login'); 回答1: I had a similar issue just a few hours ago and had to play a little bit with it to have it working. Routes: Route::group(array('prefix' => 'admin'), function() { Route::resource('/', 'admin\DashboardController'); }); In "controllers/admin" i put the DashboardController:

pass values from the view to the controller ruby on rails

余生长醉 提交于 2020-01-13 06:44:18
问题 This is my controller: def addcar @car = Car.new(params[:car]) render :action => "list" end this is my view: <%(@allcars).each do |cell|%> <p><%= link_to cell.to_s, :controller => "car", :action => "addcar", :car => cell.to_s %></p> <%end %> In the link_to statement I want to pass cell.to_s to the controller. How can I do that please? The cell.to_s is just a string but I want it to be the name of the car object ( car.Name ) 回答1: Car.new(params[:car]) expects params[:car] to be a Hash ( {:foo

How would you tidy up this controller logic?

北城以北 提交于 2020-01-13 05:56:51
问题 I've got some logic in a controller that sets a status of an object if certain conditions are met: if params[:concept][:consulted_legal] == 0 && params[:concept][:consulted_marketing] == 1 @concept.attributes = {:status => 'Awaiting Compliance Approval'} elsif params[:concept][:consulted_marketing] == 0 && params[:concept][:consulted_legal] == 1 @concept.attributes = {:status => 'Awaiting Marketing Approval'} elsif params[:concept][:consulted_marketing] == 0 && params[:concept][:consulted

Route to redirect to a controller + an action by default on CodeIgniter?

南楼画角 提交于 2020-01-13 05:39:07
问题 I'm currently working on a project with Codeigniter. I have one controller called Cat class Cat extends CI_Controller { function __construct(){ parent::__construct(); } function index($action){ // code here } } and a route (in routes.php) $route['cats/:any'] = 'cat/index/$1'; And that works if I use this URL for example: http://www.mywebsite.com/cats/display Nevertheless, if the user changes the URL to http://www.mywebsite.com/cats/ it doesn't work anymore. Codeigniter writes: 404 Page Not

Add new Custom T4 template in Add New Controller Dialog under Scaffold options

℡╲_俬逩灬. 提交于 2020-01-13 03:41:26
问题 I want to implement new T4 templates which should appear under Scaffold options in Add New Controller Dialog. I have tried adding a new View tt template.I was able to add it. I need a reference where I can get basic information on how to create a new Controller template rather than modifying existing one. Thanks Patil 回答1: Have you had a look at MVCScaffolding? http://nuget.org/packages/MVCScaffolding/ You can easily override the controller t4 template using MVCScaffolding: http://blog

Could not find devise mapping for path “/sessions/user” devise log in error

北慕城南 提交于 2020-01-12 12:50:52
问题 Very frustrating for the last few days. I have a rails app with Devise installed where I generated a new User model and I generated Devise views as well. This happens when I try to sign in as an existing user right when I click "Log in" after filling out the email and password fields: AbstractController::ActionNotFound - Could not find devise mapping for path "/sessions/user". This may happen for two reasons: 1) You forgot to wrap your route inside the scope block. For example: devise_scope

filter $scope Error: Unknown provider: $scopeProvider <- $scope <- transformSensorStatusFilter

折月煮酒 提交于 2020-01-12 12:25:15
问题 marsApp.filter("transformSensorStatus", function($scope) { return function(input, options) { var sensorReading = ( input ? ( input / 1000) : 0); var sensorLowLimit = (options["lowLimit"] ? (options["lowLimit"] / 1000) : 0); var sensorHighLimit = (options["highLimit"] ? (options["highLimit"] / 1000) : 0); var curStat; switch (sensorReading) { case 255: case 254: case 253: curStat = generateStateInnerHtml(sensorReading); break; default: curStat = generateStateInnerHtml(options["sensorStatus"]);

filter $scope Error: Unknown provider: $scopeProvider <- $scope <- transformSensorStatusFilter

拟墨画扇 提交于 2020-01-12 12:23:34
问题 marsApp.filter("transformSensorStatus", function($scope) { return function(input, options) { var sensorReading = ( input ? ( input / 1000) : 0); var sensorLowLimit = (options["lowLimit"] ? (options["lowLimit"] / 1000) : 0); var sensorHighLimit = (options["highLimit"] ? (options["highLimit"] / 1000) : 0); var curStat; switch (sensorReading) { case 255: case 254: case 253: curStat = generateStateInnerHtml(sensorReading); break; default: curStat = generateStateInnerHtml(options["sensorStatus"]);

How to initialize JavaFX controllers with the same model object?

三世轮回 提交于 2020-01-11 15:48:10
问题 Scenario I am creating a GUI where multiple views reference the same model object. What I am Accustom to In Swing, if i want all the views to reference the same model i would pass the model into the constructor. What I am Currently Doing In JavaFX, I am passing the model around by having a setter method in the views/controllers (menubars, split panes, tabs, ...), after each view/controller has been loaded. I find this very tacky and cumbersome. Additionally, I find it won't work because in