console.readline

C# Console - How to ReadLine() without a new line? ( or undo a \n or a vertical \b)

最后都变了- 提交于 2020-12-11 04:22:37
问题 I want to know if it is possible to get back to the last line when I'm at the beginning of the next line? (in C# Console, of course) I mean Console.WriteLine() cause going to the next line and I want to stay in my line even after pressing enter. (And I think there isn't another way to ReadLine without going to the next line , is there?) I found that Console.SetCursorPosition() can be useful, like below: int x, y; Console.WriteLine("Please enter the point's coordinates in this form (x,y):");

C# Console - How to ReadLine() without a new line? ( or undo a \n or a vertical \b)

懵懂的女人 提交于 2020-12-11 04:22:30
问题 I want to know if it is possible to get back to the last line when I'm at the beginning of the next line? (in C# Console, of course) I mean Console.WriteLine() cause going to the next line and I want to stay in my line even after pressing enter. (And I think there isn't another way to ReadLine without going to the next line , is there?) I found that Console.SetCursorPosition() can be useful, like below: int x, y; Console.WriteLine("Please enter the point's coordinates in this form (x,y):");

How to change Cursor position in Console?

帅比萌擦擦* 提交于 2020-01-06 09:56:31
问题 I wanted to use Console.ReadLine(); in the previous line and make it display like that: HeresomeText>(input) Not like HeresomeText> (input) Is it possible to do? 回答1: use Write method instead of WriteLine Method: Console.Write("HeresomeText> ") in addition you can use SetCursorPosition: Console.SetCursorPosition(int left, int right); 回答2: Absolutely - look at the various members of the System.Console class. In particular, you want the SetCursorPosition method, but if you're writing a "fancy"

Reading three inputs from the user using Console.ReadLine()

萝らか妹 提交于 2020-01-05 08:43:57
问题 Is this the correct way to do it, since I'm new to C# Console.WriteLine("please enter m,y,n: \n"); double month, year, numberOfMonths = Convert.ToDouble(Console.ReadLine()); 回答1: You can do it by asking user to enter the values split-ed by some delimiter like space, semi colon etc. And then split the value and parse accordingly. for example string input = Console.ReadLine(); string[] split = input.Split(','); double month = Double.Parse(split[0]); double year = Double.Parse(split[1]); double

why getting null value from console in c# for readLine() after using read()

大憨熊 提交于 2019-12-18 08:58:57
问题 I have the following code char c1 = (char)Console.Read(); Console.WriteLine("Enter a string."); string instr = Console.ReadLine(); It takes a value for c1 , after that it prints "Enter a string". However when I try to enter a string, it appears to be working like ReadKey() , meaning that as soon as I press any key it's showing that instr has a null value. If I remove the first line ( char c1 = (char)Console.Read(); ), program works correctly. Why is this? 回答1: When you call Read(), it still

Increase buffer for Console.Readline?

三世轮回 提交于 2019-12-13 04:43:27
问题 I have a line that is about 1.5kb of text. I want my console app to read it but only the first 255 characters can be pasted in. How do I increase this limit? I am literally reading it using Console.ReadLine() in debug mode under visual studio 2013 回答1: From MSDN something like this ought to work: Stream inputStream = Console.OpenStandardInput(); byte[] bytes = new byte[1536]; // 1.5kb int outputLength = inputStream.Read(bytes, 0, 1536); The you can convert your byte array to a string with

No Console found. How to get the console for my JVM?

人盡茶涼 提交于 2019-12-11 12:45:26
问题 This is a follow-up question to this. I asked this question yesterday, and although it is not resolved yet, I tried to make some silly changes to the code to just make it compile once (replacing console.format() statements by System.out.print statements, and adding null as the second argument to the readLine() methods). Luckily the code did run, but it prints No console. (obviously because the JVM does not have a console device. Reference) So how can I get the console device, supposed to be

RabbitMQ BasicConsume and Event Driven Issues relating to Console.ReadLine()

偶尔善良 提交于 2019-12-10 18:05:46
问题 The program below is basically the program from Receiver/Worker program from the C# Rabbit MQ Tutorial here: https://www.rabbitmq.com/tutorials/tutorial-two-dotnet.html (with a counter added). There are two or three things that have me stumped about it: 1) If I comment out the "Console.ReadLine()" it consumes the messages from the Queue and displays: Start Press [enter] to exit. My End - CountMessagesProcessed=0 The first few times I was testing, I couldn't figure out what was going on. 2)

console.readLine() and console.format(): What is meant by arguments referenced by format specifiers?

不羁的心 提交于 2019-12-08 12:20:56
问题 This question has a follow-up question here. Following this tutorial and compiling the given RegexTestHarness is giving the following errors on console.readLine(String) and console.Format(String), respectively: The method readLine() in the type Console is not applicable for the arguments (String) The method format(String, Object[]) in the type Console is not applicable for the arguments (String, String, int, int) According to the documentation, there are two arguments required there: public

Node.js readline: Unexpected token =>

可紊 提交于 2019-12-04 00:46:30
问题 I am learning node.js and need to use readline for a project. I have the following code directly from the readline module example. const readline = require('readline'); const rl = readline.createInterface({ input: process.stdin, output: process.stdout }); rl.question('What do you think of Node.js? ', (answer) => { // TODO: Log the answer in a database console.log('Thank you for your valuable feedback:', answer); rl.close(); }); But when I run the code via node try.js command, it keeps giving