concatenation

问题 Hi I am making a theme for the company i work at and the JS segments will not build properly in uglify. I am trying to use uglify to simply concatenate my files, which works but they output minified and mangled with no comments and i cannot figure out why, below is my gulp task which runs correctly but doesnt output with the options provided gulp.task('js', function() { return gulp.src('./src/js/*.js') .pipe(uglify({ options: { mangle: false, beautify: true, comments: true } })) .pipe(rename(

问题 How do you concatenate bitstrings. I mean bitstrings because I do not know the number of bytes to be a multiple of 8. A = <<3:2>> B = <<1:1>> C = <<15:4>> Solution should A|B|C should be <<127:7>> Thanks 回答1: Construct the binary using /bitstring and all the previous values. Here's an example, running in the erlang shell: 1> A = <<3:2>>. <<3:2>> 2> B = <<1:1>>. <<1:1>> 3> C = <<15:4>>. <<15:4>> 4> D = <<A/bitstring, B/bitstring, C/bitstring>>. <<127:7>> 来源： https://stackoverflow.com/questions

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Does C# optimize the concatenation of string literals? I just found out that we write a line like this: string s = "string"; s = s + s; // this translates to s = string.concat("string", "string"); However I opened the string class through reflector and I don't see where this + operator is overloaded? I can see that == and != are overloaded. [TargetedPatchingOptOut("Performance critical to inline across NGen

问题 I have three columns of x, y, and z coordinates in a dataframe in R that I would like to concatenate into one xyz value, like below. I have tried 'paste' with 'collapse'="" and sep="" but am having trouble, I think it's something to do with text vs. numeric variables. I have: x y z 1 2 3 2 3 2 3 1 4 4 2 1 I want: x y z xyz 1 2 3 123 2 3 2 232 3 1 4 314 4 2 1 421 There has to be some extremely easy/simple way to do this in R but I have been Googling and looking through Stack Overflow off-and

问题 I am trying to take the values passed from a userform that has 4 checkbox options and write them to a single concatenated cell. When I select my userform like this: I would like to save it to a single cell like this: I tried accomplishing this with the following code (see below), but it doesn't work quite right with the commas and such if only the 2nd, 3rd, or 4th item is chosen without the first. I am convinced there is a better way but I can't figure it out or find an answer online. Private

问题 I'm trying to build a concatenated or cascaded(actually don't even know if this is the correct definiton) set of models. For the simplicity my base models are looking like below. ----Input---- | L1-1 | L1-2 | Dense | Softmax I got 7 of these models trained with cross-validation and trying to wrap up them in a cascade fashion such as: -----------------------Input--------------------- | | | | | | | L1-1 L1-2 L1-3 L1-4 L1-5 L1-6 L1-7 | | | | | | | L2-1 L2-2 L2-3 L2-4 L2-5 L2-6 L2-7 | | | | | | |

问题 I am running the following code: for i in range(1000) My_Array=numpy.concatenate((My_Array,New_Rows[i]), axis=0) The above code is slow. Is there any faster approach? 回答1: This is basically what is happening in all algorithms based on arrays. Each time you change the size of the array, it needs to be resized and every element needs to be copied. This is happening here too. (some implementations reserve some empty slots; e.g. doubling space of internal memory with each growing). If you got

问题 I need to concatenate an indeterminate number of strings, and I would like a space in between two adjoining strings. Like so a b c d e f . Also I do not want any leading or trailing spaces, what is the best way to do this in PHP? 回答1: You mean $str = implode(' ', array('a', 'b', 'c', 'd', 'e', 'f')); ? 回答2: $strings = array( " asd " , NULL, "", " dasd ", "Dasd ", "", "", NULL ); function isValid($v){ return empty($v) || !$v ? false : true; } $concatenated = trim( implode( " ", array_map(

问题 If I enter print(cat("")) I get NULL I want to use cat() to print out the progress of an R script, but I don't understand why it is returning NULL at the end of all of my concatenated strings, and more importantly, how to get it to stop? 回答1: All your answers are in the documentation for ?cat . The portions that answer your specific question are: Arguments: fill: a logical or (positive) numeric controlling how the output is broken into successive lines. If ‘FALSE’ (default), only newlines

问题 I'm surprised there's not an overload that can take a string array. Anyway, what is the best way to avoid nesting calls to Path.Combine? pathValue = Path.Combine(path1, Path.Combine(path2, Path.Combine(path3, path4))) This seems inefficient since it results in four new strings being created just to get one. 回答1: The efficiency side of things isn't the problem IMO - it's the usability side of things. Personally I think there ought to be an overload of: Combine(string first, string second,