concatenation

问题 I want to rename each file that ends in .log, but I have similar files like: x.log x01.log y.log y01.log .... I want to rename every file, at a time, with that extension (.*) but without any number, i.e., I want to rename x.log to xN.log, y.log to yNlog, z.log to zN.log, in which N is the number I want to concatenate. Is this possible in a Windows batch script using a regex or even Python? Anything will do, as long as I can give the parameter N. 回答1: SET ext=.log SET num=%1 FOR %%f IN (*%ext%

问题 I have a situation in Excel where I want to combine all values of column A to to all values of column B (where I want to keep all values of B Absolute to All values of column A) Example: Column A - 1 2 3 4 5 6 7 8 Column B - A B C D E F G H The result I want is 1A 2A 3A 4A 5A 6A 7A 8A 1B 2B 3B 4B 5B so on till I reach 8H I have tried simple concatenating but obviously it is taking too long It would be appreciated if someone can look into this and provide me with a formula to help me fix this.

问题 I want to create a recursive Macro the will create the "next" class. Example: #define PRINTME(indexNum) class m_##(indexNum+1) { } The indexNum + 1 is evaluated as an int , and won't concatenate to the class name. How can I cause the compiler to evaluate that, before concatenating? 回答1: The simple answer is that you can't. The preprocessor generally deals in text and tokens; the only place arithmetic is carried out in in #if and #elif directives. Also, macro expansion isn't recursive. During

问题 If each array has the shape (1000, 2, 100), it is easy to use con = np.concatenate((array_A, array_B)) to concatenate them, thus con has the shape (2000, 2, 100). I want to dynamically append or concatenate "con" in a function. The step is described as following: First, read data from the first file and process data to generate an array. Secondly, read date from the second file and append generated array into the first array .... def arrayappend(): for i in range(n): #read data from file_0 to

问题 I have a document in solr which is already indexed and stored like { "title":"Harry potter", "url":"http://harrypotter.com", "series":[ "sorcer's stone", "Goblin of fire", ] } My requirement is,during query time when I try to retrieve the document it should concatenate 2 fields in to and give the output like { "title":"Harry potter", "url":"http://harrypotter.com", "series":[ "sorcer's stone", "Goblin of fire", ], "title_url":"Harry potter,http://harrypotter.com" } I know how to do it during

问题 I have the following table. Animal Vaccine_Date Vaccine Dog 1/1/2016 x Dog 2/1/2016 y Dog 2/1/2016 z Cat 2/1/2016 y Cat 2/1/2016 z I want to be able to combine vaccines that are on the same animal and same date, so that they appear in the same cell. The table below is what the desired end result would be. Animal Vaccine_Date Vaccine Dog 1/1/2016 x Dog 2/1/2016 y,z Cat 2/1/2016 y,z I have tried to create a volatile table to do so but I am not having any luck and I don't think Teradata

问题 I have the following table. Animal Vaccine_Date Vaccine Dog 1/1/2016 x Dog 2/1/2016 y Dog 2/1/2016 z Cat 2/1/2016 y Cat 2/1/2016 z I want to be able to combine vaccines that are on the same animal and same date, so that they appear in the same cell. The table below is what the desired end result would be. Animal Vaccine_Date Vaccine Dog 1/1/2016 x Dog 2/1/2016 y,z Cat 2/1/2016 y,z I have tried to create a volatile table to do so but I am not having any luck and I don't think Teradata

问题 How can I concatenate two-dimensional arrays in Julia? They are of type Array{UInt8, 2} . I have tried hvcat() , but I get the error message LoadError: MethodError: no method matching hvcat(::Array{UInt8,2}, ::Array{UInt8,2}) Any help would be much appreciated. 回答1: How exactly do you want to concatenate them? The following, for example, both work: A = rand(UInt8, 2,2) B = rand(UInt8, 2,2) C = [A B] D = [A ; B] 回答2: Two 2-D arrays of type UInt8 can be concatenated like this: C = cat(1, array1

问题 I want to concatenate two characters '7' and '9' to form this string "79". First, I initialized the variables. (Restriction: I have to use char types only and I must not make another charac alike variable.) char *charac = (char *) malloc(sizeof(char) * 200); char *combined = (char *) malloc(sizeof(char) * 200); Then I gave the values for charac[0] and charac[1]. charac[0] = '7'; charac[1] = '9'; printf("charac[0] : %c\n", charac[0] ); printf("charac[1] : %c\n", charac[1] ); I want to

问题 $a = 'hello' . 3 + 6 + 10; echo $a; // 16 I would expect it to be hello19 not 16. I know I can put the math operation in (): $a = 'hello' . (3 + 6 + 10); echo $a; // hello19 But why is php returning 16? Thank in advance. 回答1: In PHP both . and + have equal precedence and are both left associative. As a result 'hello' . 3 + 6 + 10; is evaluated as ('hello' . 3) + 6 + 10; = 'hello3' + 6 + 10 = ('hello3' + 6) + 10 // String 'hello3' when interpreted as a number gives 0 // as it starts with a non