command-line-arguments

How to write text containing newline given as command line arguments in C?

孤街浪徒 提交于 2021-02-10 15:46:26
问题 I want to create a text file with mulitple lines using system calls in C and populate it with the text provided as command line arguments. This is what I wrote: #include <stdio.h> #include <fcntl.h> #include <string.h> #include <stdlib.h> #include <unistd.h> #define MAX_SZ 1024 int main(int argc, char *argv[]) { if (argc != 3) { printf("Invalid Number of arguments\n"); printf("USAGE: ./a.out file_name \"msg\"\n"); } else { int fd_creat, fd_open, fd_write; char file_name[MAX_SZ]; char *msg =

DOS Multiline batch command. How to add comments between arguments?

左心房为你撑大大i 提交于 2021-02-10 12:02:03
问题 Id like to add comments like this: makecert -r ^ // This means SelfSigned -pe ^ // Private key is exportable -a sha512 ^ // The algoritm ... Is this possible? How? 回答1: Nothing official, but there is a simple and very effective hack - use undefined variables. At least one = is added to guarantee that the content cannot be a valid variable name, since the character cannot be used in a variable name. I use one at the beginning and end just for symmetry. Also, the comment cannot contain % or : .

DOS Multiline batch command. How to add comments between arguments?

折月煮酒 提交于 2021-02-10 12:01:52
问题 Id like to add comments like this: makecert -r ^ // This means SelfSigned -pe ^ // Private key is exportable -a sha512 ^ // The algoritm ... Is this possible? How? 回答1: Nothing official, but there is a simple and very effective hack - use undefined variables. At least one = is added to guarantee that the content cannot be a valid variable name, since the character cannot be used in a variable name. I use one at the beginning and end just for symmetry. Also, the comment cannot contain % or : .

DOS Multiline batch command. How to add comments between arguments?

你。 提交于 2021-02-10 12:01:23
问题 Id like to add comments like this: makecert -r ^ // This means SelfSigned -pe ^ // Private key is exportable -a sha512 ^ // The algoritm ... Is this possible? How? 回答1: Nothing official, but there is a simple and very effective hack - use undefined variables. At least one = is added to guarantee that the content cannot be a valid variable name, since the character cannot be used in a variable name. I use one at the beginning and end just for symmetry. Also, the comment cannot contain % or : .

Gradle command line arguments to override properties in build.gradle

让人想犯罪 __ 提交于 2021-02-08 13:33:47
问题 Whenever an existing android project is imported, in most cases we need to change values following with our installed tools version number in project/build.gradle buildscript { ... dependencies { classpath 'com.android.tools.build:gradle:x.x.x' } } in project/app/build.gradle android { compileSdkVersion xx buildToolsVersion "xx.x.x" defaultConfig { applicationId "com.example.app.xyz" minSdkVersion xx targetSdkVersion xx versionCode x versionName "x.x" } ... } dependencies { compile fileTree

Gradle command line arguments to override properties in build.gradle

杀马特。学长 韩版系。学妹 提交于 2021-02-08 13:33:17
问题 Whenever an existing android project is imported, in most cases we need to change values following with our installed tools version number in project/build.gradle buildscript { ... dependencies { classpath 'com.android.tools.build:gradle:x.x.x' } } in project/app/build.gradle android { compileSdkVersion xx buildToolsVersion "xx.x.x" defaultConfig { applicationId "com.example.app.xyz" minSdkVersion xx targetSdkVersion xx versionCode x versionName "x.x" } ... } dependencies { compile fileTree

Compile groovy script statically with command line arguments

不问归期 提交于 2021-02-07 19:38:14
问题 I am trying to statically compile a groovy script to speed up it's execution, but am not able to get it to work if command line arguments are used. My actual script is much longer, but the one-line script I use for this question perfectly reproduces my error. Using the following script ( test.groovy ) println(args.length) This can be compiled with the command groovyc test.groovy and ran by the java command java -cp .;%GROOVY_HOME%\lib\* test and will simply print the number of command line

In Visual Studio Code, how to pass arguments in launch.json

China☆狼群 提交于 2021-02-07 12:53:20
问题 In Visual Studio Code, in the launch.json file that launches the app I'm writing, how do I add command line arguments? 回答1: As described in the documentation, you need to use the args attribute. E.g. { "type": "node", "request": "launch", "name": "Debug App", "program": "${workspaceFolder}/main.js", "args": ["arg1", "arg2", "arg3"] } 来源: https://stackoverflow.com/questions/57889703/in-visual-studio-code-how-to-pass-arguments-in-launch-json

Unable to pass '#' character as a command-line argument

前提是你 提交于 2021-02-07 04:41:12
问题 I can't pass strings starting with # as command-line arguments. Here is a simple test: #include <stdio.h> int main(int argc, char *argv[]) { for (int i = 1; i < argc; i++) printf("%s ", argv[i]); putchar('\n'); return 0; } If I input the arguments as follows: 2 4 # 5 6 The value of argc is 3 and not 6 . It reads # and stops there. I don't know why, and I can't find the answer in my copies of The C Programming Language and C Primer Plus . 回答1: # begins a comment in Unix shells, much like // in

Without access to argv[0], how do I get the program name?

为君一笑 提交于 2021-02-06 10:12:47
问题 I know the program name is passed as the first argument, and next simple example will print it to the standard output : #include <iostream> int main ( int argc, char *argv[] ) { std::cout<<argv[0]<<std::endl; } Is there a function to get the program name? EDIT I am starting the program from the shell, and the above code will always print the program name (I am using fedora 9, but I am sure it works in other distros). I have found that /proc/self/ directory might contain what I am looking for,