codeblocks

CodeBlocks Breakpoints Ignoring Scope

流过昼夜 提交于 2019-12-12 01:45:14
问题 I set a breakpoint inside a conditional statement that checks for a certain value of a custom datatype. The game will break, but the line it breaks on is completely outside of my breakpoint's scope. Watch variables reveal that it just breaks the first time that loop is iterated through, rendering my debugging conditional statement absolutely useless. In Visual Studio, the debugger would respect scope, and placing a breakpoint inside a conditional statement would only stop the game if that

error: expected ';', ',' or ')' before '&' token| on a simple C program found online [closed]

夙愿已清 提交于 2019-12-12 00:28:41
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I found this program online to practice C. When I tried to compile this program in Code blocks, I am getting this error "error: expected ';', ',' or ')' before '&' token| " in two places (mentioned in the codes). It would be really helpful, if someone could explain me the reason for the error. #include<stdio.h>

Classes from C++ Primer going into Cyclic Dependency

一曲冷凌霜 提交于 2019-12-12 00:27:05
问题 I am following the book - C++ Primer for learning C++. I'm in middle of the chapter introducing classes, and I'm stuck in resolving the header files include of two classes taken as example there. Here are the two classes, and the header files: ScreenCls.h: #ifndef SCREENCLS_H #define SCREENCLS_H #include <iostream> #include "WindowManager.h" using namespace std; class ScreenCls { friend void WindowManager::clear(ScreenIndex); public: typedef string::size_type pos; ScreenCls() { } ScreenCls

Basic I/O in Microcontroller AVR using WinAVR

廉价感情. 提交于 2019-12-11 20:13:36
问题 I want to drive a BLDC motor, i use ATMEGA32 as CPU of controller , i have a problem in reading hall effect sensor from BLDC motor this is my code : DDRB=(1<<0)|(1<<1)|(1<<2)|(1<<3)|(1<<4)|(1<<5); DDRD=(0<<0)|(0<<1)|(0<<2)|(0<<3); PORTD=(1<<0)|(1<<1)|(1<<2)|(1<<3); PORTB as OUTPUT and PORTD as INPUT this is main program : if (~(PORTD &(1<<0)) && PORTD &(1<<1) && ~(PORTD &(1<<2))) /// 0 1 0 { PORTB=(1<<0)|(0<<1)|(0<<2)|(1<<3)|(0<<4)|(0<<5); } else if (~(PORTD &(1<<0)) && PORTD &(1<<1) && PORTD

for loop , loops one more time than it have to

徘徊边缘 提交于 2019-12-11 19:16:17
问题 I'm working on a simple short C++ code and the for loop is looping one more than it have to (developed using code::blocks): #include <iostream> using namespace std; int main() { int x = 0; for (x=10; x<20; x++); cout<<x; return 0; } The out put is 20 but as far as I know it has to be 19. link for image : https://drive.google.com/file/d/0B9WsVzm6FTagbC1uNHpMZ1p6SW8/edit?usp=sharing 回答1: x < 20 is the condition that must be met in order to stay inside the loop, which means that you'll only exit

Convert base 10 to base 2, C programming

两盒软妹~` 提交于 2019-12-11 18:58:13
问题 I'm still new with programming and I'd like to ask about one specific question about the C language. I'm using codeblocks compiler. Here is a piece of code: int n, c, k; scanf("%d",&n); for(c = 31;c >= 0;c--) { k = n >> c; if(k & 1) printf("1"); else printf("0"); } return 0; that I got from one website and it converts the base to the binary one. My question is, where I have an if&else statement, why is there if(k & 1) printf("1") ?? I thought that k can be both 1 and 0 and if I use (k & 1)

Codeblocks, C++ build: Permission denied collect2.exe

大城市里の小女人 提交于 2019-12-11 17:45:38
问题 I'm trying to build and run a C++ source file with 2 header files in Codeblocks (Windows). I built a Codeblocks project to do so (this is the 1st time). I have also looked online for solutions on settings but I keep getting same message. This is the build log: cannot find C:\Users\cs106: Permission denied collect2.exe: error: ld returned 1 exit status search directories/compiler: "C:\MinGW\bin" search directories/linker: "C:\MinGW\bin" search directories/resource compiler: "C:\MinGW\bin" I

How to fix codeblocks debugger's “unknown option 'nx'”

时间秒杀一切 提交于 2019-12-11 17:22:01
问题 I am trying to debug my program using codeblock's debug option for the first time and I am getting an error message: "unknown option 'nx'". Because of which my debugger is not working and I am unable to use it, can anyone tell how to fix it? 来源: https://stackoverflow.com/questions/55473658/how-to-fix-codeblocks-debuggers-unknown-option-nx

undefined reference to function code blocks

半城伤御伤魂 提交于 2019-12-11 16:09:29
问题 main.cpp #include <iostream> #include <string> using namespace std; void echo(string); int main() { echo("hello"); cout << "Hello world!" << endl; return 0; } print.cpp #include <iostream> #include <string> void echo(string code){ cout << code; } After compiling the code in code blocks 12.11, it gives me that error: undefined reference to `echo(std::string) I use windows 7 x64. I have added the directory; Project>build options > search directories and added the current working directory. All

Why am I getting a procedure entry point error for this simple C++ code?

≯℡__Kan透↙ 提交于 2019-12-11 15:04:28
问题 I'm writing an SFML game and when I try to run the code this is the error I get: The procedure entry point _gxx_personality_v0 could not be located in the dynamic link library libstdc++-6.dll I've linked to all the libraries correctly and the include files are correct. I've even tried what other answers suggested by putting the libstdc++-6.dll inside the directory of my exectable but still nothing. Another answer said to put the MinGW/bin directory before any other directory in the PATH