classpath

I've been trying in vain to get ant to execute some tests written in junit. Any advice would be much appreciated. I'm pretty new to both ant and Java so please be patient. As a quick summary, what i'm doing is trying to get ant to execute a very simple test, the classpath looks ok considering the output from ant -debug. I'm getting a null test error for a test who's class file is explicitly mentioned in the classpath. Also, i'm getting a ZipException, i dont know what that's about. Here's a testcase i'm trying to run: package testmanagment; import junit.framework.*; public abstract class

I am upgrading my application from java 1.6 to 1.7. When I try to build using Maven 3.2.1, my build fails with below error msg: [ERROR] Failed to execute goal org.apache.maven.plugins:maven-compiler-plugin:2.0.2:compile (default-compile) on project my-app5: Compilation failure: Compilation failure: [ERROR] could not parse error message: warning: [options] bootstrap class path not set in conjunction with -source 1.6 I am using java 1.7 hotspot and previously I was using 1.6 jrockit. My application is multi module and few modules compile and build as usual, this module failed. I have set java

Any suggestions as to how to approach how I would find out a list of package names that exist on the current classpath ? This needs to be done programmatically at run time by one of the classes loaded (and executing) on the classpath (i.e. inside out , not outside in). More details: One approach I considered was to use reflection on each of the classes loaded thus far by the class loader, and extract the package names from them. However, my application already runs into thousands of classes, so I need a more efficient approach. Another thing I considered was something analogous to finding out

Under Linux I am trying to run a jar file as follows: java -jar plantuml.jar -testdot while having CLASSPATH set to any of the following (the file is located at /home/user/plantuml.jar ): export CLASSPATH=/home/user export CLASSPATH=/home/user/ export CLASSPATH=/home/user/plantuml.jar In either case, no matter how I define CLASSPATH , the java command gives an error Unable to access jarfile plantuml.jar . What am I doing wrong here? You have to supply the complete path after the parameter -jar . So for your example you have to call java -jar /home/user/plantuml.jar -testdot The $CLASSPATH is

is it possible to add to the classpath of a runnable jar file some properties file? I tryed these solutions solutions: running the executable file using the following command: java -cp ../prop_dir/prop1.properties;../prop_dir/prop2.properties -jar MyRunnableJar.jar adding to the MANIFEST FILE (in the Class-Path section) ../prop_dir/prop1.properties ../prop_dir/prop1.properties but none of them works. The architecture of the running dir is the following + + MyRunnableJar.jar + prop_dir/ + prop1.properties + prop2.properties Thanks so much, Daniele EDIT When I execute the following line System

A library that my java application uses needs looks for a file (log4j.xml) in the class path. I use netbeans to manage my project, but I can't find a way to include the lib/ folder. Netbeans automatically creates a MANIFEST.MF file inside the application jar and also creates a folder called lib/ which includes all dependencies. This manifest specifies a Class-Path attribute that overrides any -cp argument provided on the command line. I can select an arbitrary folder in netbeans' library panel, but it creates a sub folder in the manifest's classpath. I'd like all dependencies and the log4j.xml