class

问题 I have an error when upgrading laravel 6 Symfony \ Component \ Debug \ Exception \ FatalThrowableError (E_ERROR) Class 'Illuminate\Support\Facades\Input' not found Source code: ERROR: can you help to fix my code? 回答1: if you're using less version of Laravel 5.2 In config/app.php , replace: 'Input' => Illuminate\Support\Facades\Input::class, Or You can import Input facade directly as required, use Illuminate\Support\Facades\Input; In Laravel 5.2 Input:: is replaced with Request:: use Request::

问题 I have some cases where I have to call method names from class names. string scenario1 = "MockScenario1"; string scenario2 = "MockScenario2"; MockScenario1.GetInfo(); MockScenario2.GetInfo(); How can I dynamically use the strings to call method name here like scenario1.GetInfo() scenario2.GetInfo() I tried to find out all options by string and control space to find related options. Any suggestions? I am tried the below and trying to Get class name generated dynamically The below code

问题 I was trying to understand the usage of explicit keyword in c++ and looked at this question on SO What does the explicit keyword mean in C++? However, examples listed there (actually both top two answers) are not very clear regarding the usage. For example, // classes example #include <iostream> using namespace std; class String { public: explicit String(int n); // allocate n bytes to the String object String(const char *p); // initializes object with char *p }; String::String(int n) { cout<<

问题 I was working on the Android library which I'm developing in Kotlin. I kept access modifier of some classes as internal . Internal classes are only visible in that library module in Kotlin. If I implement that library in the app then it's not visible at all. But the problem comes when accessing that library from Java code. If I create .java file and type name of that internal class of library then IDE is suggesting name and it's resolved and compiled without any error. For e.g. Library Module

问题 I have an class object that I create, with references to other classes (none of the other classes reference each other). I am having a memory issue that gives the 'out of memory' error when I loop through and create instances of the class. A simplified code snippet for the class and subroutine follows: Class aclsWell Option Explicit Option Compare Text Option Base 1 Private zclsSettings As bclsSettings Private zclsInfo As bclsInfo Private zclsProduction As bclsProduction Private Sub Class

问题 I have a dictionary looking like this: d ={'key1':{'key2':{'key11':{'key12':'value 13'}}},'key3':[{'key4':'value2', 'key5': 'value3'}]} I want to get the value for 'key12' so I can do this: d.get('key1').get('key2').get('key11').get('key12') and it will return this: 'value 13' if I had a list like this: ['key1', 'key2', 'key11', 'key12'] how could I call the get recursively over the above list to return the same result? 回答1: You can use functools.reduce: >>> from functools import reduce >>>

问题 I'm using type() to dynamically generate classes that will ultimately be pickled. The problem is that the un-pickling process needs the definition of the class in order to re-construct the object that has been pickled. This is where I'm stuck. I don't know how to somehow provide the unpickler a way to generate an instance from a class that was dynamically generated. Any hints appreciated. Thanks! Here's an example of the problem: >>> class Foo(object): ... pass >>> g=type('Goo',(Foo,),{'run'

问题 I'm using type() to dynamically generate classes that will ultimately be pickled. The problem is that the un-pickling process needs the definition of the class in order to re-construct the object that has been pickled. This is where I'm stuck. I don't know how to somehow provide the unpickler a way to generate an instance from a class that was dynamically generated. Any hints appreciated. Thanks! Here's an example of the problem: >>> class Foo(object): ... pass >>> g=type('Goo',(Foo,),{'run'

问题 I'm working on a Python project and I want to do something like the next example, but is incorrect. I need some help, please! names = ['name1', 'name2'] for name in names: class name: [statements] Thank you! 回答1: The class statement requires a hard-coded class name. You can use the type function, however, to create such dynamic classes. names = ['name1', 'name2'] class_dict = {} for name in names: # statements to prepare d class_dict[name] = type(name, (object,), d) Here, d is a dictionary

问题 I'm working on a Python project and I want to do something like the next example, but is incorrect. I need some help, please! names = ['name1', 'name2'] for name in names: class name: [statements] Thank you! 回答1: The class statement requires a hard-coded class name. You can use the type function, however, to create such dynamic classes. names = ['name1', 'name2'] class_dict = {} for name in names: # statements to prepare d class_dict[name] = type(name, (object,), d) Here, d is a dictionary