class

Error Class Controller not found in CodeIgniter

谁都会走 提交于 2019-12-31 02:29:44
问题 Hello, I am getting Controller not found error in CodeIgniter. This is my Controller code <?php class HelloWorld extends Controller { function HelloWorld() { parent::Controller(); } function index() { $this->load->view('index_view'); } function hello() { $this->load->view('hello_view'); } } ?> This is the view code: Hello, Nice to see you! I have this error when it executes: Fatal error: Class 'Controller' not found in D:\wamp\www\CodeIgniter_2.0.2\application\controllers\helloworld.php on

PHP object class variable

自作多情 提交于 2019-12-31 01:59:07
问题 I have built a class in PHP and I must declare a class variable as an object. Everytime I want to declare an empty object I use: $var=new stdClass; But if I use it to declare a class variable as class foo { var $bar=new stdClass; } a parse error occurs. Is there a way to do this or must I declare the class variable as an object in the constructor function? PS: I'm using PHP 4. 回答1: You can only declare static values this way for class members, i.e. ints , strings , bools , arrays and so on.

Python: how to refer to an instance name?

只谈情不闲聊 提交于 2019-12-31 01:52:09
问题 I'm collecting instances using the following code: class Hand(): instances = [] def __init__(self): Hand.instances.append(self) self.value = 5 def do_something(self, a): self.value = self.value * a class Foo(): def __init__(self): pass def insty(self): self.hand1 = Hand() self.hand2 = Hand() foo = Foo() foo.insty() print Hand.instances for hand in Hand.instances: print "how do I print the instance name?" The last line is just a way to learn how to to access the instance name so i can call the

Why aren't parent constructors being called?

不羁岁月 提交于 2019-12-31 01:48:23
问题 I added in parent::__construct(); to the constructors of table and bookmark in order to get this code to work. Why are they not called automatically? If I create an object of type bookmark $obj_ref_bo = new bookmark(); should not bookmark also create objects from each of its parent classes (besides abstract classes). The call chain is bookmark->table->database(abstract)->single_connect /*single_connect*/ class single_connect { protected static $_db_pointer = NULL; private function __construct

Every java program I try to start shows error

孤街醉人 提交于 2019-12-31 01:46:10
问题 SOLVED, Program was in location with national symbol in it's path. I just started studying java, but every program i try to start (even example ones from my course) shows an error. Error: Could not find or load main class "Any class name of program I try start" C:\Users\Mine\AppData\Local\NetBeans\Cache\8.1\executor-snippets\run.xml:53: Java returned: 1 BUILD FAILED (total time: 0 seconds) edit: example of code, but happens to any code. public class Hello { static void hello(){ System.out

Force a Derived Class to use the Constructor of the Base Class

别来无恙 提交于 2019-12-31 00:57:26
问题 Is there a way to force a derived class to use the constructor of the abstract base class? It must not be a real constructor, I have an open mind about creative solutions. class Abstract { private: int Member; string Text; public: Abstract(int Member, string Text) { this->Member = Member; this->Text = Text; } // e.g. defining virtual functions } For example my abstract class has some private members which every derived class should also have. And they should be defined in the constructor,

面向对象基础

偶尔善良 提交于 2019-12-30 23:55:06
面向对象 ''' #类 class bar: def foo(self,arg): print(self.name,self.age,self.gender,arg) z = bar() #封装公有部分到内存里 z.name = 'hao' z.age = 11 z.gender = '男' z.foo(666) z1 = bar() z.name = 'xue' z.age= 18 z.gender = '女' z.foo('hahaha') ''' ''' class bar: def __init__(self,name,age): self.name = name self.age = age def show(self): print('%s:%s' %(self.name,self.age)) z = bar('hao',11) z.show() z1 =bar('haha',33) z1.show() #输出结果: hao:11 haha:33 ''' #继承 class F: def f1(self): print('F.f1') def f2(self): print('F.f2') class s(F): def s1(self): print('s.s1') def f2(self): super(s,self).f2() #执行父类(基类)中的方法

Class类文件格式

扶醉桌前 提交于 2019-12-30 23:36:11
Class类文件格式 类型 名称 数量 描述 u4 magic 1 魔数。用来鉴别是不是class文件 u2 minor_version 1 jdk的支线版本号 u2 major_version 1 jdk的主线版本号 u2 constant_pool_count 1 常量池数量 cp_info constant_pool constant_pool_count-1 常量池(从1开始计数,0表示没有常量。属于特殊的处理) u2 access_flags 1 访问类型。关乎限定词、final、是否是接口、注解、枚举,是否是抽象的等等 u2 this_class 1 类索引。保存了该类的全限定名 此项与uper_class、nterfaces项确定类的继承关系 u2 super_class 1 父类索引。保存了父类的全限定名 u2 interfaces_count 1 接口索引集合的数量 u2 interfaces interfaces_count 接口索引。保存了implements(extends)语句后的接口名。顺序从左到右 u2 fields_count 1 字段表集合的数量 field_info fields fields_count 字段表 u2 methods_count 1 数量 method_info methods methods_count u2

What does the new() constraint do on a class definition?

只愿长相守 提交于 2019-12-30 23:27:09
问题 I saw this code example and was wondering what the purpose of the new() constraint was: public class Client<T> : IClient where T : IClientFactory, new() { public Client(int UserID){ } } 回答1: That's called a "'new' constraint". Here's the documentation on it. The new constraint specifies that any type argument in a generic class declaration must have a public parameterless constructor . To use the new constraint, the type cannot be abstract. (Emphasis mine) Basically, you need it whenever you

Android-反射调用通知栏回收

笑着哭i 提交于 2019-12-30 23:04:12
Class<?> serviceManagerClass; serviceManagerClass = Class.forName("android.os.ServiceManager"); Method getService = serviceManagerClass.getMethod("getService", String.class); IBinder retbinder = (IBinder) getService.invoke(serviceManagerClass, "statusbar"); Class<?> statusBarClass = Class.forName(retbinder.getInterfaceDescriptor()); Object statusBarObject = statusBarClass.getClasses()[0].getMethod("asInterface", IBinder.class).invoke(null, new Object[] { retbinder }); Method collapsePanels = statusBarClass.getMethod("collapsePanels"); collapsePanels.setAccessible(true); collapsePanels.invoke