class

问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: Derived class defined later in the same file “does not exist”? Does anyone has the slighties idea why I'm getting a Fatal Error: Class 'PublicacionController' not found when trying to initialize it in the if statement below ? --PublicacionController.php-- <?php /*Some random includes, those are right as far as Im concerned*/ //AJAX call if(!empty($_POST)){ if($_POST['call']=='nuevaPublicacion'){ $pc = new

问题 How can I use global DB variable inside class? Let's say I have this in my config.php $dbh = new PDO("mysql:host=localhost;dbname=mydb", "root", ""); and I want to use this $dbh inside class as follows (MyClass.php) class MyClass { public function DoSomething($plogin_id) { $sql = "SELECT * FROM mytable WHERE login_id = :login_id"; $stmt = $dbh->prepare($sql); //line 14 $stmt->bindParam(':login_id', $plogin_id, PDO::PARAM_STR); } } And inside my index.php file I am using this MyClass as

问题 I am working on a game in pygame, so far the player can walk around, 50 blue blocks spawn randomly on the screen and the player can walk around and shoot them, but there is one problem the player can only shoot up, I want the player to shoot towards the mouse but am having some trouble getting it to do this. this is my code import pygame from pygame import * import random black = ( 0, 0, 0) white = ( 255, 255, 255) red = ( 255, 0, 0) blue = ( 0, 0, 255) player_x, player_y = 0, 0 move_player_x

问题 I am a newbie to the world of Spring. In an interview, it was asked if we can create a bean in XML without specifying the class (that is, the bean would only have an id attribute). I did not have the answer to this. Please advise if we can create a bean in XML in Spring without specifying the class attribute and under which conditions we would normally do this. 回答1: Spring documentation makes it quite clear: <!-- Each bean definition must specify the fully qualified name of the class, except

问题 How can I call a derived function from a base class? I mean, being able to replace one function from the base to the derived class. Ex. class a { public: void f1(); void f2(); }; void a::f1() { this->f2(); } /* here goes the a::f2() definition, etc */ class b : public a { public: void f2(); }; /* here goes the b::f2() definition, etc */ void lala(int s) { a *o; // I want this to be class 'a' in this specific example switch(s) { case 0: // type b o = new b(); break; case 1: // type c o = new c

问题 I am developing an Android crypto library in Kotlin. I have a couple of internal classes which become publicly visible in a Java app. Found this in documentations. internal declarations become public in Java. Members of internal classes go through name mangling, to make it harder to accidentally use them from Java and to allow overloading for members with the same signature that don't see each other according to Kotlin rules; Is there a way to get around this? 回答1: I have seen all of your

问题 I am developing an Android crypto library in Kotlin. I have a couple of internal classes which become publicly visible in a Java app. Found this in documentations. internal declarations become public in Java. Members of internal classes go through name mangling, to make it harder to accidentally use them from Java and to allow overloading for members with the same signature that don't see each other according to Kotlin rules; Is there a way to get around this? 回答1: I have seen all of your

问题 Trying out ES6 and tried to create a class with static properties and function for parsing. Then I want to extend the base parser for each different type I am parsing. Not sure if I am doing a anti-pattern but I cannot override static properties. This is my base parser class Module { static name = 'Default Module' static version = {major:10000, minor: 10000} static checkVersion({majorVersion = 10000, minorVersion = 10000}) { if(this.version.major !== majorVersion || this.version.minor >

问题 Trying out ES6 and tried to create a class with static properties and function for parsing. Then I want to extend the base parser for each different type I am parsing. Not sure if I am doing a anti-pattern but I cannot override static properties. This is my base parser class Module { static name = 'Default Module' static version = {major:10000, minor: 10000} static checkVersion({majorVersion = 10000, minorVersion = 10000}) { if(this.version.major !== majorVersion || this.version.minor >

问题 Coming from this thread I implemented a similar system in c++ to the chosen solution there. My problem now is that it is stated there by the user Daniel James that this solution might not work with every compiler (I'm using gcc currently) and is not defined in the c++ standard. Suppose I have an abstract base-class for the interface and a factory-class as a singleton that stores pointers to a function that constructs the specific classes derived from that interface. then I have a helper class