charsequence

How to compare string values of CharSequence[]?

由 百般思念 提交于 2019-12-13 03:59:48
问题 I have the following CharSequence defined: final CharSequence[] videoQualities = {"any", "medium", "high", "hd"}; I am getting two string values: availableQuality and requestedQuality . Both can contain values from the CharSequence above only. How can I check if availableQuality more or equal to requestedQuality ? 回答1: Try using an ArrayList instead of CharSequence[]. You can then use ArrayList.indexOf() to return a numeric index that you can use to compare position in the ArrayList. 回答2:

What is the return type of TextView.getText() in android?

由 亡梦爱人 提交于 2019-12-11 12:36:16
问题 Why does TextView.getText() return a CharSequence instead of a String ? (String is the implementation of the CharSequence) 回答1: Because it might contain a Spannable object. From the doc: If setText() was called with an argument of BufferType.SPANNABLE or BufferType.EDITABLE , you can cast the return value from this method to Spannable or Editable , respectively. 回答2: it actually returns Editable and not CharSequence but you can store it in a String variable by calling toString() on it. 来源：

Android, how to populate a CharSequence array dynamically (not initializing?)

由 筅森魡賤 提交于 2019-12-09 02:10:24
问题 How do I change something like this: CharSequence cs[] = { "foo", "bar" }; to: CharSequence cs[]; cs.add("foo"); // this is wrong... cs.add("bar"); // this is wrong... 回答1: Use a List object to manage items and when you have all the elements then convert to a CharSequence. Something like this: List<String> listItems = new ArrayList<String>(); listItems.add("Item1"); listItems.add("Item2"); listItems.add("Item3"); final CharSequence[] charSequenceItems = listItems.toArray(new CharSequence

How to override println behavior for reference types

由 跟風遠走 提交于 2019-12-07 05:34:23
问题 I have a cyclic graph I created using dosync and ref-set . When I pass this to println I get a java.lang.StackOverflowError as I would expect, because it's effectively trying to print an infinitely-nested structure. I found that if I do (str my-ref) it creates something that looks like vertex@23f7d873 and doesn't actually try to traverse the structure and print everything out, so this solves the problem in the immediate sense, but only helps when I'm very careful about what I'm printing to

How to override println behavior for reference types

由 佐手、 提交于 2019-12-05 09:38:19
I have a cyclic graph I created using dosync and ref-set . When I pass this to println I get a java.lang.StackOverflowError as I would expect, because it's effectively trying to print an infinitely-nested structure. I found that if I do (str my-ref) it creates something that looks like vertex@23f7d873 and doesn't actually try to traverse the structure and print everything out, so this solves the problem in the immediate sense, but only helps when I'm very careful about what I'm printing to the screen. I'd like to be able to call (println my-graph) have it print the ref as some type of custom

R.string.value Help android notification

由 懵懂的女人 提交于 2019-12-04 15:37:41
问题 whats the deal with CharSequence contentTitle = R.string.value; Error cannot convert from int to CharSequence. Is there a way around this or am i missing something? i tried String s = R.string.value + ""; CharSequence contentTitle = s; it returns integers values. Any help? 回答1: R.string.value is a call to the static field in the class R, which is auto generated by Eclipse and which does a kind of summary of all your resources. To retrieve the string, you need to use : CharSequence

How to convert CharSequence to String?

由 早过忘川 提交于 2019-12-02 18:17:38
How can I convert a Java CharSequence to a String ? By invoking its toString() method. Returns a string containing the characters in this sequence in the same order as this sequence. The length of the string will be the length of this sequence. fragorl There is a subtle issue here that is a bit of a gotcha. The toString() method has a base implementation in Object . CharSequence is an interface; and although the toString() method appears as part of that interface, there is nothing at compile-time that will force you to override it and honor the additional constraints that the CharSequence

convert at symbol (“@”) to CharSequence

由 吃可爱长大的小学妹 提交于 2019-12-01 21:04:26
问题 I am testing site with selenium and I need to send an e-mail to one of the fields. So far I am using this Java method: String email = "test@example.com" WebElement emailField = driver.findElement(By.id("mainForm:accountPanelTabId:1:accountEmails"); emailField.sendKeys(email); But from (to me) uknown reason, this is sending exactly this value to the field: testvexample.com (so basically the "@" got replaced by "v") Just out of curiosity: I am Czech and have Czech keyboard. One shortcut to

convert at symbol (“@”) to CharSequence

由 妖精的绣舞 提交于 2019-12-01 19:33:42
I am testing site with selenium and I need to send an e-mail to one of the fields. So far I am using this Java method: String email = "test@example.com" WebElement emailField = driver.findElement(By.id("mainForm:accountPanelTabId:1:accountEmails"); emailField.sendKeys(email); But from (to me) uknown reason, this is sending exactly this value to the field: testvexample.com (so basically the "@" got replaced by "v") Just out of curiosity: I am Czech and have Czech keyboard. One shortcut to write "@" symbol is rightAlt + v so I believe this can be connected... So I am searching any "bulletproof"

Android, how to populate a CharSequence array dynamically (not initializing?)

由 时间秒杀一切 提交于 2019-12-01 02:14:40
How do I change something like this: CharSequence cs[] = { "foo", "bar" }; to: CharSequence cs[]; cs.add("foo"); // this is wrong... cs.add("bar"); // this is wrong... David Guerrero Use a List object to manage items and when you have all the elements then convert to a CharSequence. Something like this: List<String> listItems = new ArrayList<String>(); listItems.add("Item1"); listItems.add("Item2"); listItems.add("Item3"); final CharSequence[] charSequenceItems = listItems.toArray(new CharSequence[listItems.size()]); Heiko Rupp You are almost there. You need to allocate space for the entries,
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