character

问题 I'm trying to process this shell script in applescript, but it keeps saying error EOF, because of the single quote in the folder name. do shell script "cp -R " & a & " " & "'" & d & "/My 'Folder/java/" & "'" The folder /My 'Folder/ is a legitimate directory. The variable a = '/Applications/MyProgram/' (and includes the single quotes) The variable d = /Folders (with no single quotes) However, shell is getting stuck processing it, im guessing because the folder is enclosed in quotes. Is there

问题 I'm working in R and have a dataframe, dd_2006, with numeric vectors. When I first imported the data, I needed to remove $'s, decimal points, and some blank spaces from 3 of my variables: SumOfCost, SumOfCases, and SumOfUnits. To do that, I used str_replace_all . However, once I used str_replace_all , the vectors were converted to characters. So I used as.numeric(var) to convert the vectors to numeric, but NAs were introduced, even though when I ran the code below BEFORE I ran the as.numeric

问题 I want to fill an ArrayList with these characters +,-,*,^ etc. How can I do this without having to add every character with arrayList.add() ? 回答1: Collections.addAll is what you want. Collections.addAll(myArrayList, '+', '-', '*', '^'); Another option is to pass the list into the constructor using Arrays.asList like this: List<Character> myArrayList = new ArrayList<Character>(Arrays.asList('+', '-', '*', '^')); If, however, you are good with the arrayList being fixed-length, you can go with

问题 If I have the string "12121211122" and I want to get the last 3 characters (e.g. "122"), is that possible in Go? I've looked in the string package and didn't see anything like getLastXcharacters . 回答1: You can use a slice expression on a string to get the last three bytes. s := "12121211122" first3 := s[0:3] last3 := s[len(s)-3:] Or if you're using unicode you can do something like: s := []rune("世界世界世界") first3 := string(s[0:3]) last3 := string(s[len(s)-3:]) Check Strings, bytes, runes and

问题 I have been tasked with writing a Fortran 95 program that will read character input from a file, and then (to start with) simply spit it back out again. The tricky part is that these lines of input are of varying length (no maximum length given) and there can be any number of lines within the file. I've used do read( 1, *, iostat = IO ) DNA ! reads to EOF -- GOOD!! if ( IO < 0 ) exit ! if EOF is reached, exit do I = I + 1 NumRec = I ! used later for total no. of records allocate( Seq(I) ) Seq

问题 I've seen a lot of discussion on URL Routing, and LOTS of great suggestions... but in the real world, one thing I haven't seen discussed are: Creating Friendly URLs with Spaces and illegal characters Querying the DB Say you're building a Medical site, which has Articles with a Category and optional Subcategory . (1 to many). ( Could've used any example, but the medical field has lots of long words ) Example Categories/Sub/Article Structure: Your General Health (Category) Natural Health

问题 hi i want to check if a string from user input has two repeated characters/letters in a string next to eachother.. i have a simple code to check if the first letter and second letter in the string are the same. def two_same(): d = [] while len(d) <= 1: d = input("enter the same letter twice:") if d[0] == d[1]: return print(d[0]) two_same() but how would i check all the characters in the string and for a repeated letter from a user input. 回答1: As the comments already mentioned you should use a

问题 I'm having a problem with storing amazing amounts of text in a rich TextBox. I'm trying to read a text file fairly big( anywhere from 90mb to 450mb), and put what I've read in a rich textbox. It works in a simple program, but when I do in a complicated program I get an OutOfMemory exception. One thing to note is that when I exit my simple program, I get an OutOfMemory exception right before the program returns 0. Here is my simple program's code: array<String^>^ strArray; StreamReader^ sr;

问题 Trying to figure out how to use character wrapping to mutate a string based on user input. If string is 'Bob loves to build building' and user chooses to replace all letter B/b with T/t how do I need to code it to get 'Tom loves to tuild tuildings'? 回答1: I think there is a String class built-in replace function. String text = "Bob loves to build building"; text = text.replace("B","T").replace("b","t"); something like this ? 回答2: Your question is unclear (how 'b' becomes 'm' in Bob -> Tom?).

问题 I would like to reformat a factor vector so the figures that it contains have a thousand separator. The vector contains integer and real number without any particular rule with respect to the values or order. Data In particular, I'm working with a vector vec similar to the one generated below: content <- c("0 - 100", "0 - 100", "0 - 100", "0 - 100", "150.22 - 170.33", "1000 - 2000","1000 - 2000", "1000 - 2000", "1000 - 2000", "7000 - 10000", "7000 - 10000", "7000 - 10000", "7000 - 10000",