char-pointer

char *str; str=“HELLO”; How does that work without allocating any memory for the string?

你离开我真会死。 提交于 2019-12-06 07:34:32
问题 Code: #include <stdio.h> int main() { char *str; char i = 'a'; str = &i; str = "Hello"; printf("%s, %c, %x, %x", str, i, str, &i); return 0; } I get this output: Hello, a, 403064, 28ff0b I have following two doubts: How can I store a string without allocating any memory for it. str is a character pointer and is pointing to where char variable i . When I add str = "Hello"; aren't I using 5 bytes from that location 4 of which are not allocated? Since, I code str = &i; shouldn't str and &i have

Generate Unique Values

╄→гoц情女王★ 提交于 2019-12-06 04:37:39
I want to create a C program to generate numbers from 0 to 999999, keeping in mind that the number generated should not have any digits that are repetitive within it. For example, "123" is an acceptable value but not "121" as the '1' is repeated. I have sourced other program codes that check if an integer has repeated digits: Check if integer has repeating digits. No string methods or arrays What is the fastest way to check for duplicate digits of a number? However these do not really solve my problem and they are very inefficient solutions if I were to perform the check for 1,000,000

char *str; str=“HELLO”; How does that work without allocating any memory for the string?

对着背影说爱祢 提交于 2019-12-04 12:23:00
Code: #include <stdio.h> int main() { char *str; char i = 'a'; str = &i; str = "Hello"; printf("%s, %c, %x, %x", str, i, str, &i); return 0; } I get this output: Hello, a, 403064, 28ff0b I have following two doubts: How can I store a string without allocating any memory for it. str is a character pointer and is pointing to where char variable i . When I add str = "Hello"; aren't I using 5 bytes from that location 4 of which are not allocated? Since, I code str = &i; shouldn't str and &i have same value when I printf them? When I remove the str = "Hello"; statement str and &i are same. And if

Cast a vector of std::string to char***

蹲街弑〆低调 提交于 2019-12-02 16:11:22
问题 I have an API function that expects a char*** parameter and want to pass a vector<std::string> . Are there member functions of std::string that let me do that? This way, I only get the char pointer to the first element: std::vector<std::string> oList(128); myFunction(oList[0].c_str()); 回答1: "Are there member functions of std::string that let me do that?" In short: No. That std::vector<std::string> stores the std::string instances in a contiguous array, doesn't mean that the pointers to the

Cast a vector of std::string to char***

夙愿已清 提交于 2019-12-02 11:01:29
I have an API function that expects a char*** parameter and want to pass a vector<std::string> . Are there member functions of std::string that let me do that? This way, I only get the char pointer to the first element: std::vector<std::string> oList(128); myFunction(oList[0].c_str()); "Are there member functions of std::string that let me do that?" In short: No. That std::vector<std::string> stores the std::string instances in a contiguous array, doesn't mean that the pointers to the underlying char arrays of these string instances appear contiguously in memory. There is no way to cast the

JNI. How to get jstring from jobject and convert it to char*

两盒软妹~` 提交于 2019-12-01 16:01:56
问题 This is what I have so far: I pass an object which has 2 fields: String and Integer, as a parameter and I want to send information to process it in C part, which is not important at this point... I get complains at jstring declaration JNIEXPORT jint JNICALL Java_Tier3_NativeMethods_totalPalletsIn( JNIEnv *env, jclass cls, jobject stat) { jclass staticsitcs = (*env)->GetObjectClass(env, stat); // Here I try to get it using the ID jfieldID idDate = (*env)->GetFieldID(env, staticsitcs, "date",

Pass a string Recursively without Recreation

瘦欲@ 提交于 2019-11-28 02:27:20
I answered a question here: https://stackoverflow.com/a/28862668/2642059 Where I needed to use recurrence to step through a string . I wanted to use a const string& as my parameter on each function, but unless I wanted to reconstruct the string each recursion I found that I needed to pass a start and finish position as well as the string itself. So it became pointless to pass the string at all. In the end I choose to just pass a start and finish pointer to the char[] . As an example, say that I'm given a string which contains nested parenthesis (but no side by side parenthetical insertions.)

Why can't I assign an array variable directly to another array variable with the '=' operator?

旧巷老猫 提交于 2019-11-27 15:50:52
Why does the following assignment not work? I would like a low-level explanation if possible. Also, here's the compiler error I get: incompatible types in assignment of 'char*' to 'char [20]' class UCSDStudent { char name[20]; public: UCSDStudent( char name[] ) { //this-> name = name; does not work! Please explain why not strcopy( this -> copy, copy ); //works } }; Because when you have a function call like this UCSDStudent( char name[] ) only the adress of the array name is copied instead of the whole array. It is a C\C++ feature. Furthermore the name defined as char name [20] is not a

Pass a string Recursively without Recreation

老子叫甜甜 提交于 2019-11-26 23:45:41
问题 I answered a question here: https://stackoverflow.com/a/28862668/2642059 Where I needed to use recurrence to step through a string . I wanted to use a const string& as my parameter on each function, but unless I wanted to reconstruct the string each recursion I found that I needed to pass a start and finish position as well as the string itself. So it became pointless to pass the string at all. In the end I choose to just pass a start and finish pointer to the char[] . As an example, say that