ceil | 易学教程

How to use sqrt and ceil with Boost::multiprecision?

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问题 Do you know how to do this simple line of code without error using Boost::multiprecison ? boost::multiprecision::cpp_int v, uMax, candidate; //... v += 6 * ceil((sqrt(uMax * uMax - candidate) - v) / 6); Using MSVC there is an error for "sqrt" and it's possible to fix it with: v += 6 * ceil((sqrt(static_cast<boost::multiprecision::cpp_int>(uMax * uMax - candidate)) - v) / 6); Then there is an error for "ceil" and it's possible to fix it with: namespace bmp = boost::multiprecision; typedef bmp:

Floor or ceiling of a pandas series in python?

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问题 I have a pandas series series . If I want to get the element-wise floor or ceiling, is there a built in method or do I have to write the function and use apply? I ask because the data is big so I appreciate efficiency. Also this question has not been asked with respect to the Pandas package. 回答1: You can use NumPy's built in methods to do this: np.ceil(series) or np.floor(series) . Both return a Series object (not an array) so the index information is preserved. 回答2: You could do something

Rounding up to the second decimal place [duplicate]

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问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: PHP Round function - round up to 2 dp? What my problem is: When i use ceil(3.6451895227869); i get like 4 but i want 3.65 Can you help me out? UPDATE Please remember: This should always round to ceil like while rounding 3.6333333333333 it must not be 3.63 but should be 3.64 回答1: Check out http://www.php.net/manual/en/function.round.php <?php echo round(3.6451895227869, 2); ?> EDIT Try using this custom function

Rounding to nearest fraction (half, quarter, etc.)

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问题 So, I need to create the following functions but my head can't think of any possibility in PHP without complicated math. Round always up to the nearest decimal (1.81 = 1.90, 1.89 = 1.90, 1.85 = 1.90) Round always down to the nearest decimal (1.81 = 1.80, 1.89 = 1.80, 1.85 = 1.80) Round always up to the nearest x.25 / x.50 / x.75 / x.00 (1.81 = 2, 1.32 = 1.50) Round always down to the nearest x.25 / x.50 / x.75 / x.00 (1.81 = 1.75, 1.32 = 1.25) Round always up to the nearest x.50 / 1 (1.23 = 1

Java: BigInteger floor and ceil functions [closed]

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问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 7 years ago . I'm trying to implement an RSA attack in Java and I need to compute math operations like floor and ceil to BigInteger variables. As we know math.ceil and math.floor only apply to double variables, do you know any

CEIL and FLOOR in SQLite

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问题 What is the cleanest method to find the ciel and floor of a number in SQLite ? Unfortunately SQLite only has ROUND() function. 回答1: Formulas Ceil : cast ( x as int ) + ( x > cast ( x as int )) Take integer part of x and add 1 if decimal value is greater than 0 Floor : cast ( x as int ) - ( x < cast ( x as int )) Take integer part of x and subtract 1 if decimal value is less than 0 Examples Ceil : SELECT (cast ( amount as int ) + ( amount > cast ( amount as int ))) AS amount FROM SALES WHERE

Java中的向上取整 Math.ceil(double)

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在调外部接口获取列表数据时, 需要判断是否已经取完了所有的值，因此需要用到向上取整。 Math.ceil(）函数就是向上取整，即取大于参数的最小整数值。只要参数有小数，都会去掉小数位，将整数位加一（对于正数来说）。只要参数有小数，都会去掉小数位和负号，取整数位（对于负数来说）。这是一个很简单的计算函数，但是有一个坑需要注意。 Math.ceil(int/int)；如果参数是int/int，则向上取整不会生效。比如Math.ceil(14/5); 得到的值会是2. 这种情况, 可以将参数形式改变一下–Math.ceil(14*1.0/5)，最终答案是3. 来源： CSDN 作者：自由的bug 链接： https://blog.csdn.net/weixin_44440658/article/details/103472022

C++ ceil and negative zero

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问题 On VC++ 2008, ceil(-0.5) is returning -0.0 . Is this usual/expected behavior? What is the best practice to avoid printing a -0.0 to i/o streams. 回答1: ceil in C++ comes from the C standard library. The C standard says that if a platform implements IEEE-754 arithmetic, ceil( ) behaves as though its argument were rounded to integral according to the IEEE-754 roundTowardPositive rounding attribute. The IEEE-754 standard says (clause 6.3): the sign of the result of conversions, the quantize

PHP关于数据的舍入归类：round、ceil、floor、number_format

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下面是关于数字转化的几种方法： round -- 对浮点数进行四舍五入例子： <?php echo round ( 3.4 ); // 3 echo round ( 3.6 ); // 4 echo round ( 3.6 , 0 ); // 4 echo round ( 1.95583 , 2 ); // 1.96 echo round ( 1241757 , - 3 ); // 1242000 echo round ( 5.055 , 2 ); // 5.06 ?> ceil -- 进一法取整例子： <?php echo ceil ( 4.3 ); // 5 echo ceil ( 9.999 ); // 10 ?> floor -- 舍去法取整，跟ceil刚刚相反例子： <?php echo floor ( 4.3 ); // 4 echo floor ( 9.999 ); // 9 ?> number_format -- 格式化数字为千分位 <?php $number = 1234; // english notation (default) $english_format_number = number_format($number); echo "First:".$english_format_number."<br />"; // French notation

getting Ceil() of Decimal in python?

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问题 Is there a way to get the ceil of a high precision Decimal in python? >>> import decimal; >>> decimal.Decimal(800000000000000000001)/100000000000000000000 Decimal('8.00000000000000000001') >>> math.ceil(decimal.Decimal(800000000000000000001)/100000000000000000000) 8.0 math rounds the value and returns non precise value 回答1: x = decimal.Decimal('8.00000000000000000000001') with decimal.localcontext() as ctx: ctx.prec=100000000000000000 ctx.rounding=decimal.ROUND_CEILING y = x.to_integral_exact