ceil

问题 Anyone has ever programmed a PHP (or Perl) function to get the ceiling value Excel style? 回答1: This should be the answer, from php.net comments: // MS Excel function: Ceiling( number, significance ) // duplicates m$ excel's ceiling function if( !function_exists('ceiling') ) { function ceiling($number, $significance = 1) { return ( is_numeric($number) && is_numeric($significance) ) ? (ceil($number/$significance)*$significance) : false; } } echo ceiling(0, 1000); // 0 echo ceiling(1, 1); //

问题 Anyone has ever programmed a PHP (or Perl) function to get the ceiling value Excel style? 回答1: This should be the answer, from php.net comments: // MS Excel function: Ceiling( number, significance ) // duplicates m$ excel's ceiling function if( !function_exists('ceiling') ) { function ceiling($number, $significance = 1) { return ( is_numeric($number) && is_numeric($significance) ) ? (ceil($number/$significance)*$significance) : false; } } echo ceiling(0, 1000); // 0 echo ceiling(1, 1); //

问题 So I see this question has a good answer, but I want to round up no matter what, instead of rounding down no matter what. Adding 1 to it before casting int wouldn't work because it would "round" 5.0 into 6.0, for example. So how should I implement ceil in SQLite? 回答1: How about this? select (case when x = cast(x as int) then cast(x as int) else 1 + cast(x as int) end) 回答2: This will give you the same answer more elegantly: SELECT CAST(x+1-1e-n AS INT); (assuming you won't have a precision

问题 I have tried to implement Floor and Ceiling Function as defined in the following link https://math.stackexchange.com/questions/3619044/floor-or-ceiling-function-encoding-in-first-order-logic/3619320#3619320 But Z3 query returning counterexample. Floor Function _X=Real('_X') _Y=Int('_Y') _W=Int('_W') _n=Int('_n') _Floor=Function('_Floor',RealSort(),IntSort()) .. _s.add(_X>=0) _s.add(_Y>=0) _s.add(Implies(_Floor(_X)==_Y,And(Or(_Y==_X,_Y<_X),ForAll(_W,Implies(And(_W>=0,_W<_X),And(_W ==_Y,_W<_Y))

问题 I want to implement my own ceil() in C . Searched through the libraries for source code & found here, but it seems pretty difficult to understand. I want clean & elegant code. I also searched on SO, found some answer here. None of the answer seems to be correct. One of the answer is: #define CEILING_POS(X) ((X-(int)(X)) > 0 ? (int)(X+1) : (int)(X)) #define CEILING_NEG(X) ((X-(int)(X)) < 0 ? (int)(X-1) : (int)(X)) #define CEILING(X) ( ((X) > 0) ? CEILING_POS(X) : CEILING_NEG(X) ) AFAIK, the

问题 I would like to tally each time a value lies within a given range in a matrix by-row, and then sum these logical outcomes to derive a "measure of consistency" for each row. Reproducible example: m1 <- matrix(c(1,2,1,6,3,7,4,2,6,8,11,15), ncol=4, byrow = TRUE) # expected outcome, given a range of +/-1 either side exp.outcome<-matrix(c(TRUE,TRUE,TRUE,FALSE, TRUE,FALSE,TRUE,TRUE, FALSE,FALSE,FALSE,FALSE), ncol=4, byrow=TRUE) Above I've indicated the the expected outcome, in the case where each

问题 I would like to tally each time a value lies within a given range in a matrix by-row, and then sum these logical outcomes to derive a "measure of consistency" for each row. Reproducible example: m1 <- matrix(c(1,2,1,6,3,7,4,2,6,8,11,15), ncol=4, byrow = TRUE) # expected outcome, given a range of +/-1 either side exp.outcome<-matrix(c(TRUE,TRUE,TRUE,FALSE, TRUE,FALSE,TRUE,TRUE, FALSE,FALSE,FALSE,FALSE), ncol=4, byrow=TRUE) Above I've indicated the the expected outcome, in the case where each

问题 I would like to tally each time a value lies within a given range in a matrix by-row, and then sum these logical outcomes to derive a "measure of consistency" for each row. Reproducible example: m1 <- matrix(c(1,2,1,6,3,7,4,2,6,8,11,15), ncol=4, byrow = TRUE) # expected outcome, given a range of +/-1 either side exp.outcome<-matrix(c(TRUE,TRUE,TRUE,FALSE, TRUE,FALSE,TRUE,TRUE, FALSE,FALSE,FALSE,FALSE), ncol=4, byrow=TRUE) Above I've indicated the the expected outcome, in the case where each

来源： https://stackoverflow.com/questions/25925290/c-round-a-double-up-to-2-decimal-places

问题 I need to floor a float number with an specific number of decimals. So: 2.1235 with 2 decimals --> 2.12 2.1276 with 2 decimals --> 2.12 (round would give 2.13 wich is not what I need) The function np.round accepts a decimals parameter but it appears that the functions ceil and floor don't accept a number of decimals and always return a number with zero decimals. Of course I can multiply the number by 10^ndecimals , then apply floor and finally divide by 10^ndecimals new_value = np.floor(old