callstack

问题 What'll be the behaviour of the 8086 Microprocessor when the stack is full and even then I push something into it? 回答1: On the 8086, a PUSH instruction or implicit stack push will decrement the SP register by two and store the appropriate quantity at SS:SP (i.e. 16*SS+SP). If the SP register was $0000, the data will go to SS:$FFFE. If the SP register was $0001, the MSB of the data will go to SS:$0000 and the LSB will go to SS:$FFFF. The processor will not take any special notice of the stack

问题 Is there a relation between endianness of a processor and the direction of stack growth? For example, x86 architecture is little endian and the stack grows downwards (i.e. it starts at highest address and grows towards lower address with each push operation). Similarly, in SPARC architecture , which is big endian , the stack starts at lowest address and grows upwards towards higher addresses. This relationship pattern is seen in almost all architectures. I believe there must be a reason for

问题 How can I get a full call stack for a c++ application developed with Visual Studio 2005? I would like to have a full call stack including the code in the system libraries. Do I have to change some settings in Visual Studio, or do I have to install additional software? 回答1: Get debug information for all project dependencies. This is specified under the "Configuration Properties -> C/C++ -> General" section of the project properties. On the menu, go to "Tools -> Options" then select "Debugging

问题 If I run the following test, it fails: public class CrazyExceptions { private Exception exception; @Before public void setUp(){ exception = new Exception(); } @Test public void stackTraceMentionsTheLocationWhereTheExceptionWasThrown(){ String thisMethod = new Exception().getStackTrace()[0].getMethodName(); try { throw exception; } catch(Exception e) { assertEquals(thisMethod, e.getStackTrace()[0].getMethodName()); } } } With the following error: Expected

问题 I am just curious how CasperJS handles events with regards to the call stack. Let's say we have some code: casper.on('foo', function() { this.wait(60000); this.echo('foo'); }); casper.start('http://www.stackoverflow.com', function() { this.echo('start'); this.emit('foo'); }); casper.then(function() { this.echo('done'); }); casper.run(); I know that then() will wait check against 3 flags: pendingWait, loadInProgress, and navigationRequested. Printing out the call stack shows the emit call to

问题 I need some advice on "forwarding" arguments to a callee (in the LLVM-IR). Suppose I have a function F that is called at the beginning of all other functions in the module. From F I need to access (read) the arguments passed to its immediate caller. Right now to do this I box all arguments in the caller inside a struct and pass a i8* pointer to the struct to F , alongside an identifier telling which caller F is being called from. F has then a giant switch that branches to the appropriate

问题 I have a php application that I have just re-factored. Unfortunately it spewing out warnings like: Warning: preg_match() expects parameter 2 to be string, object given in /home/yacoby/dev/netbeans/php/Zend/Db/Select.php on line 776 Which is impossible (or very hard work) to work out the issue as I don't have a callstack so can't tell which parts of my code are causing the warning and there is a lot of code. I need a method to either treat warnings like errors (In that the application dies and

问题 What is the difference between the terms "Call Stack" and "Stack Trace" ? 回答1: A call stack is typically "the current stack of operations" - i.e. while it's running. A stack trace is typically a copy of the call stack which is logged at some sort of failure, e.g. an exception. In other words, while you're debugging you will look at the current call stack - but when you look at logs, you'll get a stack trace. At least, that's my interpretation of the terms :) 回答2: Call stack is a data

问题 I'm getting confused on what does pop actually do in assembly. Does pop move the value PUSH ed onto the stack last (meaning it doesn't apply if we MOV a value after the the last element PUSH ed) or does it just pop whatever value that's last on the stack (thus, applying to both MOV and PUSH ), or does it pop what ever value pointed to by the stack pointer? Consider the following code: push $4 mov $5, -4(%esp) add $4, %esp (esp pointing to an unknown value) pop %ebp So in this code will the

问题 I've spent about 12 hours looking through this code, and fiddling with it, trying to find out where there's a recursion problem because I'm getting the, "maximum call stack size exceeded," error, and haven't found it. Someone smarter than me please help me! so far, all I found was that when I make the object, spot , a circle , object, the problem disappears, but when I make it a, 'pip', I get this stack overflow error. I've gone over the pip class with a friggin' microscope, and still have no