cakephp

问题 I have a web application that is set up in CakePHP 3 WAMP environment. I would like to set it up as a Progressive Web App. So have the existing Model/ Controller act as an API that is exposed to a PWA framework like Angular, (P)React, Vue.js. Where can I find a clear guide/ tutorial on what steps to take to turn my existing application into a functioning backend API? Any tips from someone who has done this? 回答1: Here we go! Read: REST RequestHandlerComponent Routing 来源： https://stackoverflow

问题 I have a web application that is set up in CakePHP 3 WAMP environment. I would like to set it up as a Progressive Web App. So have the existing Model/ Controller act as an API that is exposed to a PWA framework like Angular, (P)React, Vue.js. Where can I find a clear guide/ tutorial on what steps to take to turn my existing application into a functioning backend API? Any tips from someone who has done this? 回答1: Here we go! Read: REST RequestHandlerComponent Routing 来源： https://stackoverflow

问题 This is my first time installing a framework, and I am pretty clueless. I am on OSX 10.7 and I have the cakephp framework loaded into /Library/WebServer/Documents/cakephp and I have been able to load the test page and get rid of some of the errors and warnings. Right now I am trying to resolve this Warning (2): PDO::__construct() [pdo.--construct]: [2002] No such file or directory (trying to connect via unix:///var/mysql/mysql.sock) [CORE/Cake/Model/Datasource/Database/Mysql.php, line 160]

问题 This is my first time installing a framework, and I am pretty clueless. I am on OSX 10.7 and I have the cakephp framework loaded into /Library/WebServer/Documents/cakephp and I have been able to load the test page and get rid of some of the errors and warnings. Right now I am trying to resolve this Warning (2): PDO::__construct() [pdo.--construct]: [2002] No such file or directory (trying to connect via unix:///var/mysql/mysql.sock) [CORE/Cake/Model/Datasource/Database/Mysql.php, line 160]

问题 I dont know whats wrong but my code dont output the paid amount column $payment_tbl = TableRegistry::get("MembershipPayment"); $payments = $payment_tbl->find(); $payments->select(['payment_total'=> $payments->func()->sum('paid_amount')]); $this->set("payments",$payments); and then echo this as echo $payments->payment_total; 回答1: $payments will be a query result object, not a single result. With this query, where you're expecting just a single row, add ->first() after your sum call. In general

问题 I dont know whats wrong but my code dont output the paid amount column $payment_tbl = TableRegistry::get("MembershipPayment"); $payments = $payment_tbl->find(); $payments->select(['payment_total'=> $payments->func()->sum('paid_amount')]); $this->set("payments",$payments); and then echo this as echo $payments->payment_total; 回答1: $payments will be a query result object, not a single result. With this query, where you're expecting just a single row, add ->first() after your sum call. In general

问题 I am trying to customize the pagination query for CakePHP I am using a Model based around a view. The view has some complex calculations in it and when the pagination runs it takes about 3 seconds to pull the 20 rows or so. Then it is running the same view wrapped in a count for the count used in pagination. I can run a simple table count on another table which would cut the load times in half but I am unable to find a simple way to customize a seperate query to run for the counts. Is this

问题 I'm sorry for being such a dumb ass. I'm following a tutorial to add admin routing to my cakephp application that I'm trying to create as a learning exercise. The tutorial isn't hugely well explained (I think I'm just too much of a beginner in reality) and I don't understand the following, could anyone please tell me in english what is happening here. public function isAuthorized() { $role = $this->Auth->user('role'); $neededRole = null; $prefix = !empty($this->params['prefix']) ? $this-

问题 i tried the CakePHP 3.x "Bookmaker Tutorial" and i followed the instruction step by step. Unfortunately, at the end of the first chapter i get the attached error: Error: SQLSTATE[42000]: Syntax error or access violation: 1055 Expression #8 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'wis.Tags.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by Furthermore, i get the information to check my

问题 I am going mad on this issue please somebody help me :) I have this models: Order hasMany--> Orderitem hasOne--> Product Product has field vendor_id. I would like to paginate orders wich have products with a particular vendor_id. How I could achieve this? My code in the orders_controller: if(!empty($this->data['Order']['vendor_id'])) { $conditions['Product.vendor_id']=$this->data['Order']['vendor_id']; } if(!empty($this->data['Order']['startdate'])) { $conditions['Order.date >=']=$this->data[