cakephp

问题 I'm working with CakePHP 2.0 and want to handle a ForbiddenException. I've followed the example explained at the CakePHP Cookbook. My exception is now caught at the AppExceptionHandler but I don't know how to move from here. I want to render a relevant View but $this is not available. Does anyone have a starting point for me? Edit: My code so far is identical to the Cookbook example: In app/Config/core.php Configure::write('Exception.handler', 'AppExceptionHandler::handle'); In app/Config

问题 I don't think I fully understand Amazon Web Services yet, which is why I'm asking this question. I want to know if AWS would be a nice host for a CakePHP application that of course runs off PHP, and MySQL? Would I have to change or add anything to my code if used a service like EC2? I also noticed that Amazon has it's own database system, does that mean no mysql. Also as a side question, what do you guys think of the cost AWS? Sorry if my question is a little scattered, or somewhat "noobish,"

问题 In controller actions to make redirect I use this: $this->redirect(array('controller' => 'tools', 'action' => 'index')); or this $this->redirect('/tools/index'); And when I pass data with redirect I use this: $this->redirect('tools/index/?myArgument=12'); But I couldn't find how to pass "myargument" by "this-redirect-array" notation. I don't want to use this because some routing issues: $this->redirect(array('controller' => 'tools', 'action' => 'index', "myArgument")); I need something like

问题 In controller actions to make redirect I use this: $this->redirect(array('controller' => 'tools', 'action' => 'index')); or this $this->redirect('/tools/index'); And when I pass data with redirect I use this: $this->redirect('tools/index/?myArgument=12'); But I couldn't find how to pass "myargument" by "this-redirect-array" notation. I don't want to use this because some routing issues: $this->redirect(array('controller' => 'tools', 'action' => 'index', "myArgument")); I need something like

问题 I'm nearling completion of my first CakePHP-driven website and just saw they're already working on CakePHP 2.0 (not the stable release yet). My questions: Is it incredibly time consuming to move to a new version of CakePHP (when it becomes the "stable" release that is)? I know they have migration guides, but - I've never used a framework before, so I've never had to migrate anything. Do you migrate your code for existing projects, or leave it as is and use the new stable version for future

问题 I am trying to get CakeEmail working and I am getting a "Could not send email" Internal Error. The last line of the stack trace is CORE/Cake/Network/Email/MailTransport.php line 47 -> MailTransport->_mail(string,string,string,string,null) In my email.php config I have class EmailConfig { public $default = array( 'transport' => 'Mail', 'from' => 'no-reply@xxxxx.com.au' ); } I receive my email address from a form and am trying to send an email to the subscriber. My code is as follows $email

问题 i would have to show the table of reservation of 3 biens it should show me 3 line of 3 reservation but it show me just one line in the controllers public function index_hote() { $this->Reservation->recursive = 1; $this->loadModel("BiensPersonne"); if($this->Session->read('Auth.User.0.Personne.id')){ $options = $this->BiensPersonne->findByPersonneId($this->Session- >read('Auth.User.0.Personne.id')); $this->loadModel("Personne"); $biens=$this->Personne->findById( $options['BiensPersonne'][

问题 I'm using CakePHP 1.2 with Auth and ACL components. In my user register action, the password is coming in unhashed. Specifically, this expression: if ($this->data['User']['password'] != $this->Auth->password($this->data['User']['confirm_password'])) This is evaluating to true, even when I submit identical values for password and confirm_password . I know that password is unhashed because when I remove the call to Auth->password , the expression evaluates to false. I expected the Auth module

问题 I'm trying to change the database connection used in cakephp 3 on the fly. Every answer to this question that I found refers to cakephp 2 (These three for instance). This guy found a solution for cakephp 3 having a finite number of databases, and specifically defining which Database would be used by which Table file. The thing is that I want to create a new database for every new user, and change to his database when he logs in. I can't know in advance all the databases that will exist, to

问题 I have been stuck at this problem for a whole day. What im trying to do is to send 2 values from view to controller using Ajax. This is my code in hot_products view: <script> $(function(){ $('#btnSubmit').click(function() { var from = $('#from').val(); var to = $('#to').val(); alert(from+" "+to); $.ajax({ url: "/orders/hot_products", type: 'POST', data: {"start_time": from, "end_time": to, success: function(data){ alert("success"); } } }); }); }); and my hot_products controller: public