c

Backspace(\b) not clearing text in Non-canonical mode termios

旧巷老猫 提交于 2021-02-17 02:17:29
问题 i am trying to clear text by pressing the backspace key, i am using termios in non canonical mode. i have created a conditional statement that when the users press backspace it should remove the previous character by going one character back. But when i press Backspace instead of removing the character it prints ^? on that line. I don't want to use canonical mode. My Code: #include <stdio.h> #include <stdlib.h> #include <termios.h> #include <unistd.h> #include <sys/types.h> #include <string.h

Memcpy segfaulting with valid pointers

穿精又带淫゛_ 提交于 2021-02-17 02:16:08
问题 I'm using libcurl in my program, and running into a segfault. Before I filed a bug with the curl project, I thought I'd do a little debugging. What I found seemed very odd to me, and I haven't been able to make sense of it yet. First, the segfault traceback: Program received signal SIGSEGV, Segmentation fault. [Switching to Thread 0x7fffe77f6700 (LWP 592)] 0x00007ffff6a2ea5c in memcpy () from /lib/x86_64-linux-gnu/libc.so.6 (gdb) bt #0 0x00007ffff6a2ea5c in memcpy () from /lib/x86_64-linux

Memcpy segfaulting with valid pointers

房东的猫 提交于 2021-02-17 02:13:08
问题 I'm using libcurl in my program, and running into a segfault. Before I filed a bug with the curl project, I thought I'd do a little debugging. What I found seemed very odd to me, and I haven't been able to make sense of it yet. First, the segfault traceback: Program received signal SIGSEGV, Segmentation fault. [Switching to Thread 0x7fffe77f6700 (LWP 592)] 0x00007ffff6a2ea5c in memcpy () from /lib/x86_64-linux-gnu/libc.so.6 (gdb) bt #0 0x00007ffff6a2ea5c in memcpy () from /lib/x86_64-linux

Linked List Delete Node , Simple linked list

有些话、适合烂在心里 提交于 2021-02-17 02:08:34
问题 I'm trying to implement a function that deletes nodes from a linked list. So far, I can delete just the first node of the list(3). I tried to go to the for loop from delete, I thought that the memory is not well allocated, I have been struggling for a few days and I don't understand, please help me a little, it's the topic I received from college. #include <stdio.h> #include <stdlib.h> typedef struct nod { int key; struct nod *urm; } NOD; NOD *first=0,*last=0; void add(int x) { NOD *p=(NOD*

Linked List Delete Node , Simple linked list

邮差的信 提交于 2021-02-17 02:08:25
问题 I'm trying to implement a function that deletes nodes from a linked list. So far, I can delete just the first node of the list(3). I tried to go to the for loop from delete, I thought that the memory is not well allocated, I have been struggling for a few days and I don't understand, please help me a little, it's the topic I received from college. #include <stdio.h> #include <stdlib.h> typedef struct nod { int key; struct nod *urm; } NOD; NOD *first=0,*last=0; void add(int x) { NOD *p=(NOD*

warning: unknown escape sequence '\

爷,独闯天下 提交于 2021-02-16 21:32:22
问题 I'm trying to run a regex through a system command in the code, I have gone through the threads in StackOverflow on similar warnings but I couldn't understand on how to fix the below warnings, it seems to come only for the closed brackets on doing \\}. The warnings seem to disappear but not able to get the exact output in the redirected file. #include<stdio.h> int main(){ FILE *in; char buff[512]; if(system("grep -o '[0-9]\{1,3\}\\.[0-9]\{1,3\}\\.[0-9]\{1,3\}\\.[0-9]\{1,3\}' /home/santosh

Variable Scope in C programming

假装没事ソ 提交于 2021-02-16 21:26:39
问题 In c, when this block of code is run,it outputs 10 10 10 10 10. I think the loop should exit after 1st execution as i becomes 11 but it is not happening. Why it is so? #include<stdio.h> int main() { int i; for(i=0;i<5;i++) { int i=10; printf("%d\t",i); i++; } return; } But when program is written as below the output is similar to what i am thinking(i.e.10 ).What is the exact difference between above code and the code shown below? How C is handling these variable? I would be glad if anyone

Recursive C macro not expanded

和自甴很熟 提交于 2021-02-16 21:25:13
问题 I am working on a recursive macro. However, it seems that it is not expanded recursively. Here is a minimal working example to show what I mean: // ignore input, do nothing #define ignore(...) // choose between 6 names, depending on arity #define choose(_1,_2,_3,_4,_5,_6,NAME,...) NAME // if more than one parameter is given to this macro, then execute f, otherwise ignore #define ifMore(f,...) choose(__VA_ARGS__,f,f,f,f,f,ignore)(__VA_ARGS__) // call recursively if there are more parameters

Variable Scope in C programming

你离开我真会死。 提交于 2021-02-16 21:23:00
问题 In c, when this block of code is run,it outputs 10 10 10 10 10. I think the loop should exit after 1st execution as i becomes 11 but it is not happening. Why it is so? #include<stdio.h> int main() { int i; for(i=0;i<5;i++) { int i=10; printf("%d\t",i); i++; } return; } But when program is written as below the output is similar to what i am thinking(i.e.10 ).What is the exact difference between above code and the code shown below? How C is handling these variable? I would be glad if anyone

Unable to compile sample code from The C Programming Language 2nd , page 29

不问归期 提交于 2021-02-16 21:19:09
问题 Unable to compile the code on page 29, The C Programming Language, 2nd Edition. I changed ' getline ' to ' GetLine ' in the code to make it work. What can we do to make the program compile without changing it? How did the author compile the code? Here is the code: #include <stdio.h> #define MAXLINE 1000 /* maximum input line size */ int GetLine(char line[], int maxline); void copy(char to[], char from[]); /* print longest input line */ main() { int len; /* current line length */ int max; /*