broadcast

According to socket.io examples: To broadcast, simply add a broadcast flag to emit and send method calls. Broadcasting means sending a message to everyone else except for the socket that starts it. var io = require('socket.io').listen(80); io.sockets.on('connection', function (socket) { socket.broadcast.emit('user connected'); }); I tried to combine this with the new socket.io namsepace feature, so I got this: var chat = ioserver.of('/chat'); chat.on('connection', function (socket) { console.log('chat connection'); socket.on('message', function (msg) { console.log(msg); chat.send(msg); }); });

I have a C-project that has n numbers of processors working on a kind of tree search. At any given time of the program, any of these processes may find something of interest and want to send this to all other processors asynchronously. How can I listen for new messages on the other processes without having to loop through all possible senders each loop iteration? I have read other questions about this, for example this one ( MPI - Asynchronous Broadcast/Gather ), however, all I've seen so far either doesn't handle unpredictable senders or loops through each possible sender, which I don't

How do I go about calculating the Broadcast Address in Objective C I would like to have the Broadcast Address resolve to the same result as shown in the following Subnet Calculator - http://www.subnet-calculator.com/subnet.php I have the IP Address of my local IOS device and the Subnet Mask. And I know that the Broadcast Address uses the following formula broadcast = ip | ( ~ subnet ) (I am answering my self, as I have not seen this on the Internet anywhere, and also I am not aware of any libraries which perform this calculation. Happy to see if anyone else has a better solution or is aware of

For the following I'm assuming one network card. I have a component of my program which is designed to let others in the subnet know of its existence. For this, I've implemented a solution where whenever the program starts up (and periodically afterwards) it sends a broadcast to INADDR_BROADCAST - whoever listens on the required port will remember where it came from for later use. The problem with this is that I don't want to remember my own broadcasts. I thought that in theory this would be easy to do - simply find out the local ip and compare to what you get in recvfrom . However, I've found

I'm programming a networking program in java , and I want to send some Packets to 255.255.255.255, but it fails , even when I send them to 192.168.1.255, which according to the output of ifconfig command , is the broadcast address. But when I send them to my mate's IP it works fine. Here's the code to my program : public class StackOverFlow { public static void main(String[] args) { Network net= new Network(); Scanner input= new Scanner(System.in); while(input.hasNext()) net.sendMessage(input.nextLine()); } } I've used DatagarmSocket and DatagramPacket to do so , here's my implementation of

I'm writing a server/client system in C, which uses BSD Sockets under a TCP connection. The server is multi-threaded, with each connection running in its own receptor. Each client does a good job talking with the server on a one-to-one basis, sadly I can't think of a way to implement a SendToAll() function, for instance, if client A does something that requires sending a packet to all of the clients. How would I do this? I was considering implementing a queue in every receptor, and any broadcast gets sent to those queues; when the receptor sends out a new packet, it adds that message onto the

For Internet Protocol (IP) I can use multicast : in IPv4: Internet Group Management Protocol (IGMP) in IPv6: Multicast Listener Discovery Also, in example, for UDP I can use: broadcast - to send packet to range of addresses multicast - to send packet to list of specified addresses But can I use something of these for TCP? No, you can't. TCP is a protocol for communication between exactly two endpoints. Compared to UDP it features reliable transport, that means, that packets get not only send, but it is expected that the peer acknowledges the receipt of the data and that data will be