boolean-expression

问题 Do they have a reason for doing so? I mean, in the sum of minterms, you look for the terms with the output 1; I don't get why they call it "minterms." Why not maxterms because 1 is well bigger than 0? Is there a reason behind this that I don't know? Or should I just accept it without asking why? 回答1: The convention for calling these terms "minterms" and "maxterms" does not correspond to 1 being greater than 0. I think the best way to answer is with an example: Say that you have a circuit and

问题 In Numpy, I can generate a boolean array like this: >>> arr = np.array([1, 2, 1, 2, 3, 6, 9]) >>> arr > 2 array([False, False, False, False, True, True, True], dtype=bool) Is is possible to chain comparisons together? For example: >>> 6 > arr > 2 array([False, False, False, False, True, False, False], dtype=bool) 回答1: AFAIK the closest you can get is to use & , | , and ^ : >>> arr = np.array([1, 2, 1, 2, 3, 6, 9]) >>> (2 < arr) & (arr < 6) array([False, False, False, False, True, False, False

问题 I'm trying to write a program that requires the calculation of a specific value dealing with Boolean functions. Given a single-output Boolean function f, given by a cover F, let's say I define the density of the function as the fraction of all input vectors where the function has the value 1. For example, suppose I pass in the given function f(a, b, c) which is defined by cover F = ab'+c'. The function has 5 ON-set minterms, and 8 total minterms, hence its density is d(f) = 5/8 = 0.625. It

问题 Can you break a while loop from outside the loop? Here's a (very simple) example of what I'm trying to do: I want to ask for continuous inside a While loop, but when the input is 'exit', I want the while loop to break! active = True def inputHandler(value): if value == 'exit': active = False while active is True: userInput = input("Input here: ") inputHandler(userInput) 回答1: In your case, in inputHandler , you are creating a new variable called active and storing False in it. This will not

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I'm looking for a tool to refactor boolean expression. I've got expressions like a1 => (b1 <=> c or d) AND a2 => (b2 <=> c or d) AND a2 => (b2 <=> c or d) The tool should be able to simplify expressions, e.g. extract the sub expression "c or d" in the example above. Is there a free computer algebra system which

问题 I am new to the topic of propositional logic and boolean expressions. So this is why I need help. Here is my problem: In the car industry you have thousand of different variants of components available to choose from when you buy a car. Not every component is combinable, so for each car there exist a lot of rules that are expressed in propositional logic. In my case each car has between 2000 and 4000 rules. They look like this: A → B ∨ C ∨ D C → ¬F F ∧ G → D ... where "∧" = "and" / "∨" = "or"

问题 Is it pythonic to use or , similar to how PHP would use or die() ? I have been using quiet or print(stuff) instead of if verbose: print(stuff) lately. I think it looks nicer, they do the same thing, and it saves on a line. Would one be better than the other in terms of performance? The bytecode for both look pretty much the same to me, but I don't really know what I'm looking at... or 2 0 LOAD_FAST 0 (quiet) 3 JUMP_IF_TRUE_OR_POP 15 6 LOAD_GLOBAL 0 (print) 9 LOAD_CONST 1 ('foo') 12 CALL

问题 Its the same thing right? Or is there a slight difference? I just wanna make sure I'm not misunderstanding anything. 回答1: Boolean duals are generated by simply replacing ANDs with ORs and ORs with ANDs. The complements themselves are unaffected, where as the complement of an expression is the negation of the variables WITH the replacement of ANDs with ORs and vice versa. Consider: A+B Complement: A'B' Dual: AB 回答2: "The Dual of an identity is also an identity. This is called the Duality

问题 Consider the following method in Java: public static boolean expensiveComputation() { for (int i = 0; i < Integer.MAX_VALUE; ++i); return false; } And the following main method: public static void main(String[] args) { boolean b = false; if (expensiveComputation() && b) { } } Logical conjunction (same as &&) is a commutative operation. So why the compiler doesn't optimize the if-statement code to the equivalent: if (b && expensiveComputation()) { } which has the benefits of using short

问题 This question is based on another question I asked, where I didn't cover the problem entirely: Pandas - check if a string column contains a pair of strings This is a modified version of the question. I have two dataframes : df1 = pd.DataFrame({'consumption':['squirrel ate apple', 'monkey likes apple', 'monkey banana gets', 'badger gets banana', 'giraffe eats grass', 'badger apple loves', 'elephant is huge', 'elephant eats banana tree', 'squirrel digs in grass']}) df2 = pd.DataFrame({'food':[