bindparam

What exactly does first parameter in bind_param() do?

吃可爱长大的小学妹 提交于 2020-01-15 09:27:49
问题 I am trying to understand prepared statements using PHP and mysqli. I tried to read on some tutorials, manual and this one: Bind_Param in PHP, but I have not yet found any satisfying answer. Someone wrote in answer as: When you prepare an SQL statement, you can insert a placeholder (?) where a column value would go, then use bind_param() to safely substitute that placeholder for the real column's value. This prevents any possibility of an SQL injection. I found some code in tutorials like

What exactly does first parameter in bind_param() do?

寵の児 提交于 2020-01-15 09:27:09
问题 I am trying to understand prepared statements using PHP and mysqli. I tried to read on some tutorials, manual and this one: Bind_Param in PHP, but I have not yet found any satisfying answer. Someone wrote in answer as: When you prepare an SQL statement, you can insert a placeholder (?) where a column value would go, then use bind_param() to safely substitute that placeholder for the real column's value. This prevents any possibility of an SQL injection. I found some code in tutorials like

Understanding PDO Prepared Statements and Binding Parameters

别说谁变了你拦得住时间么 提交于 2020-01-14 06:15:14
问题 From experience and also having been told constantly the benefits of using prepared statements and binding my parameters, I have constantly used those two techniques in my code, however I would like to understand exactly the purpose of each of those two techiques: From my understanding of prepared statements: $sql = "SELECT * FROM myTable WHERE id = ".$id; $stmt = $conn->prepare($sql); $stmt->execute(); The previous code should create a sort of a buffer in the database with the query I

How to debug SQLSTATE[HY000]: General error: 2031 in prepared statements

泪湿孤枕 提交于 2020-01-11 13:12:30
问题 I have this prepared statement query $stmt = $conn->prepare(" UPDATE language SET lang_alias=:lang_alias , lang_name=:lang_name WHERE lang_id=:lang_id" ); If I set an array to bind the values $query_array = array ( ":lang_alias" => "en", ":lang_name" => "English (UK)", ":lang_id" => 1 ) ; and then execute it $stmt->execute(array($query_array)); it wont work, I get Notice: Array to string conversion referring to $stmt->execute(array($query_array)); and Uncaught exception 'PDOException' with

PHP -> PDO -> Prepare -> Call Procedure -> Insert Into -> Bind Parameters

和自甴很熟 提交于 2019-12-25 09:58:18
问题 using this procedure CREATE PROCEDURE `Insert_New_Return_Id`(IN Insert_Stmnt varchar(1000), OUT IDNum int) BEGIN SET @buffer = Insert_Stmnt; PREPARE stmt FROM @buffer; EXECUTE stmt; SELECT LAST_INSERT_ID() INTO IDNum; DEALLOCATE PREPARE stmt; END the following code works fine : $statement=$con->prepare("CALL Insert_New_Return_Id (\"INSERT INTO users (first_name,last_name)VALUES('test','test')\",@ID)"); $statement->execute(); $statement=$con->query("SELECT @ID"); while ($row = $statement-

PHP bind_param not defined [duplicate]

爷,独闯天下 提交于 2019-12-24 13:49:07
问题 This question already has answers here : Fatal error: Call to undefined method mysqli::bind_param() in (3 answers) Closed 4 years ago . I am working in MAMP trying to make a login function. My connection code is: $servername = "localhost"; $username = "root"; $password = "root"; $db = "world"; $mysqli = new mysqli($servername, $username, $password, $db); if($mysqli->connect_error){ die("Connection failed: " . $conn->connect_error); } My login function: if (isset($_POST['email'], $_POST['p']))

PDO bindParam not working in loop

纵然是瞬间 提交于 2019-12-20 07:25:08
问题 I am having trouble getting bindParam to work inside of a foreach loop. If I use bindParam outside of a loop or hardcode the values into the sql query everything works perfectly. According to this page it is suggested to use bindValue instead. However, when I use bindValue it says that the three variables used inside the bindValue are undefined. Which obviously they are at this point. What am I doing wrong? <?php $found_update = false; $installed_groups = array( array( "group_id" => 14,

Is it possible to bindParam WHERE name like %:name%

試著忘記壹切 提交于 2019-12-19 04:05:41
问题 I'm testing a small search feature: But I've come across an error that I cannot seem to solve. You can see the PDO query here: $search = "test1"; //later to be changes to $_POST ['search']; $sql = "SELECT id, name FROM clients WHEE name like %:name% order by id LIMIT 5"; $stm = $db->prepare ( $sql ); $stm->bindParam ( ":name" , $search); $result = $stm->execute (); As you can see, I'm trying to bind the parameter %:name% from my query, but I don't know if that's actually possible? I receive

Confusion between bindValue() and bindParam()?

微笑、不失礼 提交于 2019-12-17 10:42:49
问题 I am confuse between these two functions Bindvalue() and BindParam() I read on php.net it does not escape % and _ , so be careful when using LIKE . So i think BindValue() is not used when we are using LIKE query. when we using LIKE query BindParam() is used. Because as i know BindParam can escape these % and _ . BindValue() doesn't gives protection against sql injection. I am not sure about this, is it true? friends tell what i mention in these 3 points is right or wrong. i am beginner in PDO

How to prepare statement for update query?

故事扮演 提交于 2019-12-17 06:14:08
问题 I have a mysqli query with the following code: $db_usag->query("UPDATE Applicant SET phone_number ='$phone_number', street_name='$street_name', city='$city', county='$county', zip_code='$zip_code', day_date='$day_date', month_date='$month_date', year_date='$year_date' WHERE account_id='$account_id'"); However all the data is extracted from HTML documents so to avoid errors I would like to use a prepared statement. I found PHP documentation on bind_param() but there is no UPDATE example. 回答1: