binaryfiles

问题 Does anyone know how I can find the version of a binary file that has been passed to my function? I got the following code from this page: def version(fpath): f = open(fpath, 'rb') s = f.read(1024) print s f.close() However, this does not give me any useful output similar to what the mentioned website shows. Edit : @BoazYaniv tells me that the file format plays in important part in this problem. This is a windows EXE file 回答1: We use this code to pull versions from one of our executables for

问题 I am trying to write the file in binary format. I have the following code with me, but it save the file in text format. #include <iostream> #include <fstream> using namespace std; int main(){ std::string ref = "Ecoli. 123"; unsigned int size = 124; std::ofstream supp_info_output("binary_file", std::ios::out | std::ios::binary); // saving file supp_info_output << ref << std::endl; supp_info_output << size << std::endl; supp_info_output.close(); std::ifstream supp_info_input("binary_file", std:

问题 Form view: <form enctype="multipart/form-data" ng-submit="upload(file)"> <input type="file" ng-model="modal.file" accept="image/gif" app-filereader /><br /> <br> <textarea name="description" placeholder="Description" ng-model="description" id="" cols="30" rows="10"></textarea> <br> <input type="hidden" name="user" ng-model="user" value="{{ user }}" /> <br> <input type="submit" value="Submit" class="network-sensitive button button-block button" /> </form> Directive: .directive('appFilereader',

问题 I am trying to use mmap in C just to see how it exactly works. Currently I am try to read a binary file byte by byte using mmap. My code is like this: #include <unistd.h> #include <sys/types.h> #include <sys/mman.h> #include <stdio.h> #include <stdlib.h> #include <fcntl.h> int main(int argc, char *argv[]) { int fd; char *data; for ( int i = 1; i<argc; i++) { if(strcmp(argv[i],"-i")==0) fd = open(argv[i+1],O_RDONLY); } data = mmap(NULL, 4000, PROT_READ, MAP_SHARED, fd, 8000); int i = 0;

问题 I've searched in StackOverFlow website and over the internet for this question and its relevant questions but I still haven't got a clear answer. I want to know what software may I use to convert any file (regarding size) into a text file that contains zeros and ones (only) of this specific file, then convert this text file that contains these zeros and ones back to the original file. Execuse my ignorance if the files that contains zeros and ones are not called "binary files", I searched the

问题 I'm writing a M/R job that processes large time-series-data files written in binary format that looks something like this (new lines here for readability, actual data is continuous, obviously): TIMESTAMP_1---------------------TIMESTAMP_1 TIMESTAMP_2**********TIMESTAMP_2 TIMESTAMP_3%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%TIMESTAMP_3 .. etc Where timestamp is simply a 8 byte struct, identifiable as such by the first 2 bytes. The actual data is bounded between duplicate value timestamps, as displayed

问题 I need to parse and encode to a legacy binary message format in Java. I began by using DataOutputStream to read/write primitive types but the problem I'm having is that the message format doesn't align nicely to byte offsets and includes bit flags. For example I have to deal with messages like this: +----------+---+---+----------+---------+--------------+ +uint32 +b +b + uint32 +4bit enum+32 byte string+ +----------+---+---+----------+---------+--------------+ Where (b) is a one bit flag. The

问题 So, I created a binary file with fortran, using something similar to this: open (3,file=filename,form="unformatted",access="sequential") write(3) matrix(i,:) The way I understand it, fortran pads the file with 4 bytes on either end of the file, and the rest is just the data that I want (in this case, a list of 1000 doubles). I want to read this in with gnuplot, however, I don't know how to get gnuplot to skip the first and last 4 bytes, and read the rest in as doubles. The documentation isn't

问题 I need to read a file as binary data, then be able encrypt and decrypt it. I am testing speeds of different algorithms in Crypto++. Up until now, I have been using getline to read text files. int main( int argc, char* argv[] ) { string plaintext, ciphertext, encoded, recovered, sample_files_path, data_file, line_contents, file_size; ifstream initial_file_contents ( "1MB.txt"); if (initial_file_contents.is_open()) { plaintext = ""; while ( getline( initial_file_contents, line_contents ) ) {

问题 I want to be able to use an ostream_iterator to stream to a binary file. But the ostream_iterator uses a FormattedOuputFunction so it will write ASCII, not binary: std::ostream_iterator is a single-pass OutputIterator that writes successive objects of type T into the std::basic_ostream object for which it was constructed, using operator<< Beyond writing my own iterator is there a way to use an iterator to write binary? A simplified example of what I'm trying to do, but the copy statement is