binary-tree

Closed. This question is off-topic. It is not currently accepting answers. Learn more . Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 5 years ago . I have a non-balanced (not binary-search) binary tree Need to incode (and later decode) it to txt file. How can I do it in efficient way? I found this link which talks about similar (same) problem,but it is obvious for me Zegar Please look at this on LeetCode . I like this solution because it's relatively efficient and produces light output files. Assuming that you've got a tree like this: _30_ / \

I've been playing around with binary trees in Haskell, and I am attempting to implement a dfs variant that returns the path (composed of left and rights) from the root node to the node containing the value searched for. I think it would be best to return a Maybe Directions type. Here is what has been implemented so far. data Tree a = Empty | Node a (Tree a) (Tree a) deriving (Show, Eq) data Direction = L | R deriving (Show) type Directions = [Direction] inTree :: (Eq a) => a -> Tree a -> [Direction] inTree val (Node x l r) | val == x = [] | l /= Empty = L:(inTree val l) | r /= Empty = R:

How do I make a BST when I have an array list of 100 elements like {3,2,6,7,...,99} ? I believe TreeSet is an implementation of a binary search tree. Since integers have a natural ordering you could simply loop through your array of integers and add them all to a TreeSet<Integer> . Note also, that there is a method Arrays.binarySearch that does a binary search in a sorted array. int[] someInts = {3,2,6,7, /*...,*/ 99}; // use a TreeSet TreeSet<Integer> ints = new TreeSet<Integer>(); for (int i : someInts) ints.add(i); System.out.println(ints.contains(2)); // true System.out.println(ints

I have been trying to wrap my brain around how to write code for rotation of binary tree. I looked at http://en.wikipedia.org/wiki/Tree_rotation and enfuzzled.com I have been staring at this for 2 hours and have looked at it multiple times earlier. I still see problems in the wikipedia article and cannot understand the other one completely e.g. Both these lines mentioned in the wikipedia article cannot be true at once Let P be Q's left child. Set P to be the new root. Can anyone please help?Thanks According to your comments to the question you are looking for the guidance for the rotation

I am not sure how to determine if a tree is balanced, perfectly balanced, or neither if I have it as a picture not a code For example if I have this tree How can I check if it's balanced, perfectly balanced, or unbalanced? and can someone give me an example of a perfectly balanced tree? [o] / \ [b] [p] \ / \ [d] [m] [r] Clearly I can tell that the tree is unbalanced if it was something like this: [b] \ [d] \ [r] \ [c] However, if it was something very similar to the one above I don't know how to get it This is a perfectly balanced and balanced tree: [k] / \ [A] [p] / \ [N] [R] Can someone

I want to write a function to construct a full binary tree from a given preorder and postorder array. I found that link http://www.geeksforgeeks.org/full-and-complete-binary-tree-from-given-preorder-and-postorder-traversals/ which proposes the following C code : struct node* constructTreeUtil (int pre[], int post[], int* preIndex, int l, int h, int size) { // Base case if (*preIndex >= size || l > h) return NULL; // The first node in preorder traversal is root. So take the node at // preIndex from preorder and make it root, and increment preIndex struct node* root = newNode ( pre[*preIndex] );