biginteger

BigInteger to byte[]

拟墨画扇 提交于 2019-11-28 10:53:14
I need to convert a Java BigInteger instance to its value in bytes. From the API, I get this method toByteArray() , that returns a byte[] containing the two's-complement representation of this BigInteger. Since all my numbers are positive 128 bits (16 bytes) integer, I don't need the 2's-complement form that give me 128 bits + sign bit (129 bits)... Is there a way to get the standard (without the 2's-complement form) representation directly from a BigInteger? If not, how can I right shift the whole byte[17] array to lose the sign bit in order to get a byte[16] array? Thomas You don't have to

How can I use bigint with C#?

泄露秘密 提交于 2019-11-28 09:17:15
I work to implement an RSA key algorithm. But I couldn't use a 2048-bit value. How I can use it? I want to use big integer. You can use System.Numerics.BigInteger (add a reference to System.Numerics assembly). As mentioned in the comments this might not be the right approach though. Native support for big integers has been introduced in .NET 4.0. Just add an assembly reference to System.Numerics , add a using System.Numerics; declaration at the top of your code file, and you’re good to go. The type you’re after is BigInteger . Sunil Chandurkar Here's using BigInteger . This method Prints

How to work with BIG numbers? [duplicate]

戏子无情 提交于 2019-11-28 09:08:51
问题 Possible Duplicates: “BigInt” in C? How to implement big int in C++ How do we work with big numbers without making use of external libraries and functions? Some problems are as follows: What is the sum of the digits of the number 21000? Work out the first ten digits of the sum of the following one-hundred 50-digit numbers. 37107287533902102798797998220837590246510135740250 46376937677490009712648124896970078050417018260538 74324986199524741059474233309513058123726617309629

Java BigInteger vs Mono .net BigInteger

大兔子大兔子 提交于 2019-11-28 08:17:15
问题 I use in .Net project mono implementation of BigInteger (link) In Java I use java.math.BigInteger. The same code produces different results in Java. .Net code String inputBytes = "8E5BD77F0DCC30864634C134E28BFB42A149675A320786B616F4530708350D270353C30A40450325801B7AFED12BCCA274B8187072A89CC0CC3F95A24A8251243C1835898246F4D64CA3AC61DB841518F0E8FBC8996A40EB626153AE7F0BB87FD713FAC522719431428DE178E780A3FA45788A72C431926AED990E6DA268D2CC"; String modulus =

Fastest 128 bit integer library [closed]

北城以北 提交于 2019-11-28 07:38:07
I am working on a CPU-heavy numerical computation app. Without going into many details, it's a computational math research project that involves computing a certain function f(x) for large integer x. Right now everything is implemented in C++ in x64 mode, using native 64-bit ints. That limits me to x<2^64~1.8*10^19. I want to go further, to do that, I need a library that does 128-bit arithmetic. And it has to be very fast. In particular, integer divisions should be fast. Otherwise I'll be sitting here waiting for the results till Thanksgiving. And I'd rather not reinvent the wheel. I found a

Decimals and commas when entering a number into a Ruby on Rails form

断了今生、忘了曾经 提交于 2019-11-28 06:58:25
What's the best Ruby/Rails way to allow users to use decimals or commas when entering a number into a form? In other words, I would like the user be able to enter 2,000.99 and not get 2.00 in my database. Is there a best practice for this? -- Update --- Does gsub work with floats or bigintegers? Or does rails automatically cut the number off at the , when entering floats or ints into a form? I tried using self.price.gsub(",", "") but get "undefined method `gsub' for 8:Fixnum" where 8 is whatever number I entered in the form. I had a similar problem trying to use localized content inside forms.

Long vs BigInteger

可紊 提交于 2019-11-28 06:16:18
I understand that both java.lang.Long and java.math.BigInteger can hold very large natural numbers. I also know Long's max value, but what is the max value for BigInteger? And aside from capacity, would BigInteger ever perform better when working with generally large integers that still fall in Long's range? Question Is the only consideration: is my value too large for Long? AHungerArtist BigInteger is capable of holding far bigger numbers than Long. BigInteger seems capable of holding (2 ^ 32) ^ Integer.MAX_VALUE, though that depends on the implementation (and, even if truly unbounded in the

Efficient Exponentiation For HUGE Numbers (I'm Talking Googols)

Deadly 提交于 2019-11-28 05:50:07
问题 I am in the midst of solving a simple combination problem whose solution is 2^(n-1). The only problem is 1 <= n <= 2^31 -1 (max value for signed 32 bit integer) I tried using Java's BigInteger class but It times out for numbers 2^31/10^4 and greater, so that clearly doesn't work out. Furthermore, I am limited to using only built-in classes for Java or C++. Knowing I require speed, I chose to build a class in C++ which does arithmetic on strings. Now, when I do multiplication, my program

Converting a big integer to decimal string

僤鯓⒐⒋嵵緔 提交于 2019-11-28 05:16:22
问题 At the risk of having this question voted as a duplicate, or even to have it closed, I had this question has come up. Background In "normal" data types such as int, long long, etc..., to convert from the binary numeric value to a decimal string, you would do the following (in pseudo code): Set length = 0 Set divisor to largest base10 value the data type will hold (Divisor). Loop Divide number in question by divisor. Place result in a string at position length. Increment the length by 1.

Log of a very large number

99封情书 提交于 2019-11-28 04:46:45
问题 I'm dealing with the BigInteger class with numbers in the order of 2 raised to the power 10,000,000. The BigInteger Log function is now the most expensive function in my algorithm and I am desperately looking for an alternative. Since I only need the integral part of the log, I came across this answer which seems brilliant in terms of speed but for some reason I am not getting accurate values. I do not care about the decimal part but I do need to get an accurate integral part whether the