biginteger

Why does BigInteger.ToString(“x”) prepend a 0 for values between signed.MaxValue (exclusive) and unsigned.MaxValue (inclusive)?

谁都会走 提交于 2019-12-01 04:51:58
问题 Examples (asterisks next to odd behavior): [Fact] public void BigInteger_ToString_behavior_is_odd() { writeHex(new BigInteger(short.MaxValue)); // 7fff writeHex(new BigInteger(short.MaxValue) + 1); // 08000 ** writeHex(new BigInteger(ushort.MaxValue)); // 0ffff ** writeHex(new BigInteger(ushort.MaxValue) + 1); // 10000 writeHex(new BigInteger(int.MaxValue)); // 7fffffff writeHex(new BigInteger(int.MaxValue) + 1); // 080000000 ** writeHex(new BigInteger(uint.MaxValue)); // 0ffffffff **

How do I write a long integer as binary in Python?

强颜欢笑 提交于 2019-12-01 03:56:59
In Python, long integers have unlimited precision. I would like to write a 16 byte (128 bit) integer to a file. struct from the standard library supports only up to 8 byte integers. array has the same limitation. Is there a way to do this without masking and shifting each integer? Some clarification here: I'm writing to a file that's going to be read in from non-Python programs, so pickle is out. All 128 bits are used. Sven Marnach Two possible solutions: Just pickle your long integer. This will write the integer in a special format which allows it to be read again, if this is all you want.

BCD math library for arbitrary big numbers?

倾然丶 夕夏残阳落幕 提交于 2019-12-01 03:45:29
I'm looking for a replacement of the stock Delphi Data.FmtBcd library because I just hit its limits like maximum decimal digits it can represent and program terminates with EBcdOverflowException . For the curious, I'm calculating arithmetic series members and need to handle very large numbers - hundred-thousands positions are not so uncommon. And also get results in a reasonable time. I did rewritten part of the code to Python 3.2 for the testing purposes and calculation speed would be sufficient for the Delphi's equivalent. Some recommendations for a such library, preferably free or

Optimizing Karatsuba Implementation

放肆的年华 提交于 2019-12-01 03:45:17
So, I'm trying to improve some of the operations that .net 4's BigInteger class provide since the operations appear to be quadratic. I've made a rough Karatsuba implementation but it's still slower than I'd expect. The main problem seems to be that BigInteger provides no simple way to count the number of bits and, so, I have to use BigInteger.Log(..., 2). According to Visual Studio, about 80-90% of the time is spent calculating logarithms. using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Numerics; namespace Test { class Program { static

Hibernate returns BigIntegers instead of longs

蹲街弑〆低调 提交于 2019-12-01 03:03:41
This is my Sender entity @Entity public class Sender { @Id @GeneratedValue(strategy = GenerationType.AUTO) private long senderId; ... ... public long getSenderId() { return senderId; } public void setSenderId(long senderId) { this.senderId = senderId; } } When I try to execute following query: StringBuilder query = new StringBuilder(); query.append("Select sender.* "); query.append("From sender "); query.append("INNER JOIN coupledsender_subscriber "); query.append("ON coupledsender_subscriber.Sender_senderId = sender.SenderId "); query.append("WHERE coupledsender_subscriber.Subscriber

How do I write a long integer as binary in Python?

吃可爱长大的小学妹 提交于 2019-12-01 00:52:38
问题 In Python, long integers have unlimited precision. I would like to write a 16 byte (128 bit) integer to a file. struct from the standard library supports only up to 8 byte integers. array has the same limitation. Is there a way to do this without masking and shifting each integer? Some clarification here: I'm writing to a file that's going to be read in from non-Python programs, so pickle is out. All 128 bits are used. 回答1: Two possible solutions: Just pickle your long integer. This will

Optimizing Karatsuba Implementation

廉价感情. 提交于 2019-12-01 00:44:41
问题 So, I'm trying to improve some of the operations that .net 4's BigInteger class provide since the operations appear to be quadratic. I've made a rough Karatsuba implementation but it's still slower than I'd expect. The main problem seems to be that BigInteger provides no simple way to count the number of bits and, so, I have to use BigInteger.Log(..., 2). According to Visual Studio, about 80-90% of the time is spent calculating logarithms. using System; using System.Collections.Generic; using

Is it possible to conditionally “use bigint” with Perl?

喜欢而已 提交于 2019-11-30 23:21:18
问题 I know I can conditionally use a module in Perl but what about the "pragmas"? My tests have shown that use bigint can be much slower than normal math in Perl and I only need it to handle 64-bit integers so I only want to use it when Perl wasn't built with 64-bit integer support, which I also know how to check for using the Config module. I tried various things with eval and BEGIN blocks but couldn't work out a way to conditionally use bigint. I know I can use Math::BigInt but then I can't use

I need very big array length(size) in C#

别说谁变了你拦得住时间么 提交于 2019-11-30 22:38:31
public double[] result = new double[ ??? ]; I am storing results and total number of the results are bigger than the 2,147,483,647 which is max int32. I tried biginteger, ulong etc. but all of them gave me errors. How can I extend the size of the array that can store > 50,147,483,647 results (double) inside it? Thanks... An array of 2,147,483,648 double s will occupy 16GB of memory. For some people, that's not a big deal. I've got servers that won't even bother to hit the page file if I allocate a few of those arrays. Doesn't mean it's a good idea. When you are dealing with huge amounts of

How can I create a random BigDecimal in Java?

一曲冷凌霜 提交于 2019-11-30 21:21:51
This question: How to generate a random BigInteger describes a way to achieve the same semantics as Random.nextInt(int n) for BigIntegers. I would like to do the same for BigDecimal and Random.nextDouble(). One answer in the above question suggests creating a random BigInteger and then creating a BigDouble from it with a random scale. A very quick experiment shows this to be a very bad idea :) My intuition is that using this method would require the integer to be scaled by something like n-log10(R) , where n is the number of digits of precision required in the output and R is the random