bigdecimal

问题 I wanted to see if anyone can explain why the following code works with valueOf but not others. import java.math.BigDecimal; public class Change { public static void main(String args[]) { double a = 4.00d; double b = 3.10d; BigDecimal a1 = new BigDecimal(a); BigDecimal b1 = new BigDecimal(b); BigDecimal diff = a1.subtract(b1); System.out.println("Double difference"); System.out.println(diff); float c = 4.00f; float d = 3.10f; BigDecimal a2 = new BigDecimal(c); BigDecimal b2 = new BigDecimal(d

问题 I wanted to see if anyone can explain why the following code works with valueOf but not others. import java.math.BigDecimal; public class Change { public static void main(String args[]) { double a = 4.00d; double b = 3.10d; BigDecimal a1 = new BigDecimal(a); BigDecimal b1 = new BigDecimal(b); BigDecimal diff = a1.subtract(b1); System.out.println("Double difference"); System.out.println(diff); float c = 4.00f; float d = 3.10f; BigDecimal a2 = new BigDecimal(c); BigDecimal b2 = new BigDecimal(d

问题 I have BigDecimal value. BigDecimal price = new BigDecimal("100500100500.9999999").setScale(2, BigDecimal.ROUND_HALF_EVEN); It prints 100500100501.00 , although I need 100500100500.99 . Is it possible to make some restriction to precision evaluating? 回答1: You can use the rounding mode constant ROUND_DOWN in setScale . However, the overloaded setScale method that takes a RoudingMode is preferred. BigDecimal price = new BigDecimal("100500100500.9999999") .setScale(2, RoundingMode.DOWN); Output:

问题 I have BigDecimal value. BigDecimal price = new BigDecimal("100500100500.9999999").setScale(2, BigDecimal.ROUND_HALF_EVEN); It prints 100500100501.00 , although I need 100500100500.99 . Is it possible to make some restriction to precision evaluating? 回答1: You can use the rounding mode constant ROUND_DOWN in setScale . However, the overloaded setScale method that takes a RoudingMode is preferred. BigDecimal price = new BigDecimal("100500100500.9999999") .setScale(2, RoundingMode.DOWN); Output:

问题 I have a number of type BigDecimal, for example 18446744073709551616, and I want to convert it to hexadecimal value. I'm fine with truncating the fractional portion. Is there a way to do this instead of doing it manually? 回答1: Judging by your example you should use BigInteger instead of BigDecimal . This way you could use new BigInteger("18446744073709551616").toString(16) If you can't change type of original object convert it to BigInteger later in method new BigDecimal("18446744073709551616

来源： https://stackoverflow.com/questions/60226893/rails-nomethoderror-undefined-method-new-for-bigdecimalclass

来源： https://stackoverflow.com/questions/60226893/rails-nomethoderror-undefined-method-new-for-bigdecimalclass

问题 For a BigDecimal number such as 42.7, how can I tear this apart to get the integer part (42) and the decimal fractional part (0.7)? I would like to retrieve both as BigDecimal objects. But I will take what I can get and make BigDecimal object from them. 回答1: setScale() I think I’d go for setScale() . BigDecimal bd = new BigDecimal("42.7"); BigDecimal integerPart = bd.setScale(0, RoundingMode.DOWN); BigDecimal fractionalPart = bd.subtract(integerPart); System.out.println(integerPart); System

问题 For a BigDecimal number such as 42.7, how can I tear this apart to get the integer part (42) and the decimal fractional part (0.7)? I would like to retrieve both as BigDecimal objects. But I will take what I can get and make BigDecimal object from them. 回答1: setScale() I think I’d go for setScale() . BigDecimal bd = new BigDecimal("42.7"); BigDecimal integerPart = bd.setScale(0, RoundingMode.DOWN); BigDecimal fractionalPart = bd.subtract(integerPart); System.out.println(integerPart); System

问题 This question already has answers here : Removing trailing zeros from BigDecimal in Java (6 answers) Closed 2 years ago . How to set generic scaling according to decimal roundness as a number BigDecimal num = new BigDecimal(25) BigDecimal result = num.divide(new BigDecimal(13), 7, RoundingMode.HALF_EVEN) // 1.9230769 but BigDecimal result = num.divide(new BigDecimal(10), 7, RoundingMode.HALF_EVEN) // 2.5000000 that should be 2.5 Probably analyzing remainder? Is there something in the API for