bearing

Difference (angle) between two bearings

蹲街弑〆低调 提交于 2021-02-10 06:27:23
问题 Using geosphere::bearing I can calculate the bearing of two lines, but is it possible to calculate the angle between the two bearings ? Of course you can try and subtract or sum up the bearings but in specific cases where one is negative and the other is positive this doesn't work. For example if the ber1 = - 175 and ber2 = 175 the angle between should be 10. Any suggestions ? 回答1: I am not sure of a ready-made package but in case you are interested in a solution then you can try angle_diff <

Mapbox GL JS Bearing

↘锁芯ラ 提交于 2020-12-06 06:43:45
问题 Is it possible in Mapbox GL JS to get the users bearing? I would like to show the direction in which the user is facing, to assist them in navigating to nearby POI. I understand that it is possible to set the bearing of the map and also get the current bearing of it, but i need the actual real life bearing of the user. Kind of the same thing as on Google Maps: The service is intended to run as an Ionic app on iOS and Android, and the assistance in bearing is a key feature in helping them

Bearing between two points

别来无恙 提交于 2020-01-22 12:43:29
问题 Ive been using the geopy package , which does a great job, however some of the results i get are inconsistant or come with a relatively large displacement, i suspect that the problem resides with my bearing calculation: def gb(x,y,center_x,center_y): dx=x-center_x dy=y-center_y if ((dy>=0)and((dx>0)or(dx<0))): return math.degrees(math.atan2(dy,dx)) elif (dy<=0)and((dx>0)or (dx<0)): return (math.degrees(math.atan2(dy,dx))+360) else: return (math.degrees(math.atan2(dy,dx))+360)%360 I need to

Bearing between two points

只愿长相守 提交于 2020-01-22 12:43:26
问题 Ive been using the geopy package , which does a great job, however some of the results i get are inconsistant or come with a relatively large displacement, i suspect that the problem resides with my bearing calculation: def gb(x,y,center_x,center_y): dx=x-center_x dy=y-center_y if ((dy>=0)and((dx>0)or(dx<0))): return math.degrees(math.atan2(dy,dx)) elif (dy<=0)and((dx>0)or (dx<0)): return (math.degrees(math.atan2(dy,dx))+360) else: return (math.degrees(math.atan2(dy,dx))+360)%360 I need to

Rotate marker as per user direction on Google Maps V2 Android

假如想象 提交于 2020-01-17 10:18:19
问题 I want to rotate marker as per bearing or sensor value received from Accelerometer to show the user where actually he is moving. I have set marker icon and flat value to true but its not working as required. mCurrentLocationMarker.position(new LatLng( LocationUtils.sLatitude, LocationUtils.sLongitude)); mCurrentLocationMarker.icon(icon); mCurrentLocationMarker.flat(true); mCurrentLocationMarker.rotation(LocationUtils.sBearing); if (currentMarker != null) { currentMarker.setPosition(new LatLng

Given point of (latitude,longitude), distance and bearing, How to get the new latitude and longitude

情到浓时终转凉″ 提交于 2020-01-11 09:33:10
问题 I found a piece of code on web. It calculates the Minimum bounding rectangle by a given lat/lon point and a distance. private static void GetlatLon(double LAT, double LON, double distance, double angle, out double newLon, out double newLat) { double dx = distance * 1000 * Math.Sin(angle * Math.PI / 180.0); double dy = distance * 1000 * Math.Cos(angle * Math.PI / 180.0); double ec = 6356725 + 21412 * (90.0 - LAT) / 90.0; double ed = ec * Math.Cos(LAT * Math.PI / 180); newLon = (dx / ed + LON *

Using Compass to point to actual coordinate location instead of just North

我只是一个虾纸丫 提交于 2019-12-21 20:59:25
问题 I have seen a few examples of this but am not sure exactly how to implement it, (such as iPhone Compass GPS Direction) in do I need to call calcBearingWithLatitude in (void)startup? All I am trying to do is have the compass pull a point from memory and use that point as its "north" so to speak and point to it, no need for distance or anything like that. My implementation file as of now looks like @implementation TrackerViewController @synthesize locationManager; @synthesize compass;

Geoalgorithm for finding coordinates of point from a known location by distance and bearing

那年仲夏 提交于 2019-12-19 04:11:30
问题 I'd like to use Google maps static API to display a map with a path overlay indicating a boundary. AFAICT the static API doesn't support polygons, so I intend to circumvent this by drawing the boundary using paths. To do this I need to determine the points to draw the straight lines (paths) between; so I'd like an algorithm that returns the geographic location (i.e. WGS84 coordinates) a given bearing and distance from a known point. Can anyone point me to such an algorithm. Preferably in C#,

GMap Bearing rotation in smooth motion (avoid jerky effect when changing bearing values)

走远了吗. 提交于 2019-12-18 18:55:52
问题 I want to rotate GMap by changing the bearing angle value, so the camera rotates around the center point (360-Degree one full round ). When we change the bearing, there is a easing effect at camera start and end points. How can I control/change that in order to make the rotation smooth when change Bearing values (in order to rotate map in 360 Degree, smooth animation)? Required this for all languages as it appears the easing effect is different in different language libraries. e.g. Swift,

How do you find relative bearing between two points?

半世苍凉 提交于 2019-12-13 01:28:01
问题 double computeHeading(double latitude1, double longitude1, double latitude2, double longitude2) { double degToRad = PI / 180.0; double phi1 = latitude1*degToRad; double phi2 = latitude2*degToRad; double lam1 = longitude1*degToRad; double lam2 = longitude2*degToRad; double x,y; x = cos(phi2) * sin(lam2-lam1); printf("X is %lf\n", x); y = cos(phi1) * sin(phi2) - sin(phi1) * cos(phi2) * cos(lam2-lam1); printf("Y is %lf\n", y); return atan2(x,y)*180/PI; } I am using the above function to