bash

问题 I want to run a command n number of times if it returns unsuccessful I have started with the below loop until find . -type f -exec md5sum {} \; do <something > done I want to run the about n times before it goes continues to the next file Not sure how I can continue from here. I have tried using the return variable $? and looping using this but had no luck Also how could I use the above loop or what is proposed here to put the output of the find into a variable thanks Let me make this abit

问题 I made a Bash script that extracts words from a text file with grep and sed and then sorts them with sort and counts the repetitions with wc , then sort again by frequency. The example output looks like this: 12 the 7 code 7 with 7 add 5 quite 3 do 3 well 1 quick 1 can 1 pick 1 easy Now I'd like to merge all words with the same frequency into one line, like this: 12 the 7 code with add 5 quite 3 do well 1 quick can pick easy Is there any way to do that with Bash and standard Unix toolset? Or

问题 I made a Bash script that extracts words from a text file with grep and sed and then sorts them with sort and counts the repetitions with wc , then sort again by frequency. The example output looks like this: 12 the 7 code 7 with 7 add 5 quite 3 do 3 well 1 quick 1 can 1 pick 1 easy Now I'd like to merge all words with the same frequency into one line, like this: 12 the 7 code with add 5 quite 3 do well 1 quick can pick easy Is there any way to do that with Bash and standard Unix toolset? Or

问题 I'd like to loop over an associative array and print out the key / value pairs in a nice way. Therefore I'd like to indent the values in such a way, that they all start at the same position behind their respective keys. Here's an example: declare -A my_array my_array["k 1"]="value one" my_array["key two"]="value two" for key in "${!my_array[@]}"; do echo "$key: ${my_array[$key]}" done The output is k 1: value one key two: value two The output I'd like to have would be (for arbitrary key

问题 I have installed anaconda in ubuntu and am facing a problem with anaconda. I was running the following command in a conda environment: 271 pip install --user -r requirements.txt 272 cd .. 273 conda install ipython jupyter 274 conda install jupyter 275 python 276 sudo apt-get install python-vtk python-wxgtk2.6 python-setuptools python-numpy python-configobj 277 sudo apt-get install python-vtk python-wxgtk2.8 python-setuptools python-numpy python-configobj 278 conda install -c anaconda mayavi=

问题 So I have a bash script which deletes all contents from an AWS S3 bucket and then uploads the contents of a local folder to that same bucket. #!/bin/bash # deploy to s3 function deploy(){ aws s3 rm s3://bucketname --profile Administrator --recursive aws s3 sync ./ s3://bucketname --profile Administrator --exclude='node_modules/*' --exclude='.git/*' --exclude='clickCounter.py' --exclude='package-lock.json' --exclude='bundle.js.map' --exclude='package.json' --exclude='webpack_dev_server.js' -

问题 This question already has answers here : Dynamic variable names in Bash (16 answers) How to use a variable's value as another variable's name in bash [duplicate] (6 answers) Closed 3 years ago . In my bash scripts, I often prompt users for y/n answers. Since I often use this several times in a single script, I'd like to have a function that checks if the user input is some variant of Yes / No, and then cleans this answer to "y" or "n". Something like this: yesno(){ temp="" if [[ "$1" =~ ^([Yy

问题 I have 2 files in below formats. File1_Stored.txt ABC:100, 83 ABC:84, 53 ABC:14, 1222 File2_Stored.txt ABC:100 , 83 ABC:84 , 1553 ABC:524 , 2626 I am trying to get the 3rd file in below format. So, whenever difference is 0 it shouldnt appear but if the diffence is not 0 then it should appear like Value , File1 Value , File2 Value , Difference ---------------------------------------------- ABC:84, 53 ,1553 , -1500 ABC:14, 1222 , 0 , 1222 ABC:524, 0 ,2626 ,-2626 I tried doing it using awk to

问题 I have my data in a file store by lines like this : 3.172704445659,50.011996744997,3.1821975358417,50.012335988197,3.2174797791605,50.023182479597 And I would like 2 columns : 3.172704445659 50.011996744997 3.1821975358417 50.012335988197 3.2174797791605 50.023182479597 I know sed command for delete ','(sed "s/,/ /") but I don't know how to "back to line" every two digits ? Do you have any ideas ? 回答1: One in awk: $ awk -F, '{for(i=1;i<=NF;i++)printf "%s%s",$i,(i%2&&i!=NF?OFS:ORS)}' file

问题 I'm trying to loop over unique names and commit messages from a github json object. However when there are spaces in the arrays bash will treat them as individual array items #!/usr/bin/env bash commits='[ { "author": { "email": "email@example.com", "name": "Chris", "username": "chris" }, "committer": { "email": "email@example.com", "name": "Chris", "username": "chris" }, "message": "commit message 1" }, { "author": { "email": "email@example.com", "name": "John", "username": "jdoe" },