base

算法训练 回文数 时间限制：1.0s 内存限制：256.0MB 问题描述 　　若一个数（首位不为零）从左向右读与从右向左读都一样，我们就将其称之为回文数。 　　例如：给定一个10进制数56，将56加65（即把56从右向左读），得到121是一个回文数。 　　又如：对于10进制数87： 　　STEP1：87+78 = 165 STEP2：165+561 = 726 　　STEP3：726+627 = 1353 STEP4：1353+3531 = 4884 　　在这里的一步是指进行了一次N进制的加法，上例最少用了4步得到回文数4884。 　　写一个程序，给定一个N（2<=N<=10或N=16）进制数M（其中16进制数字为0-9与A-F），求最少经过几步可以得到回文数。 　　如果在30步以内（包含30步）不可能得到回文数，则输出“Impossible!” 输入格式 　　两行，N与M 输出格式 　　如果能在30步以内得到回文数，输出“STEP=xx”（不含引号），其中xx是步数；否则输出一行”Impossible!”（不含引号） 样例输入 9 87 样例输出 STEP=6 题意： 略，注意范围 分析： 主要是对进制的转化，细心点分析即可，这里可以不用stringsteam相关字符串流的，也是熟悉下吧，所以就这样写了，思路很清晰，就是模拟即可，麻烦了点,由于样例水了点，不然得高精度模拟

7-4 列表数字元素加权和(1) (40 分) 输入一个嵌套列表，嵌套层次不限，根据层次，求列表元素的加权和。第一层每个元素 的值为：元素值*1，第二层每个元素的值为：元素值*2，第三层每个元素的值为：元素值*3， ...,以此类推！ 输入格式: 在一行中输入列表 输出格式: 在一行中输出加权和 输入样例: 在这里给出一组输入。例如： [1,2,[3,4,[5,6],7],8] 输出样例: 在这里给出相应的输出。例如： 72 a = eval(input()) def fn(base, power): if type(base) == int: return base * power else: return sum(fn(i, power+1) for i in base) print(fn(a, 0)) 来源： https://www.cnblogs.com/nobilis/p/11921779.html

指令 mov ds:[dx],dx 原因：上述指令使用寄存器相对寻址方式，只能使用BX，BP，SI，DI 方括号里必须是变址（index，指SI, DI）或基址（base，指BX, BP）寄存器 正确写法： mov ds:[bx],bx 来源： https://www.cnblogs.com/luocodes/p/11919598.html

当页面上的First Name是已知得元素，但是位置不固定得时候，选择Anchor Base 锚点，选择属性auto,可以找到不确定位置得First Name 来源： https://www.cnblogs.com/fanqiusha1988/p/11919337.html

Let's see this code: class CBase { public: virtual vfunc() { cout << "CBase::vfunc()" << endl; } }; class CChild: public CBase { public: vfunc() { cout << "CChild::vfunc()" << endl; } }; int main() { CBase *pBase = new CBase; ((CChild*)pBase)->vfunc(); // !!! important delete pBase; return 0; } The output is: CBase::vfunc() But I want to see: CChild::vfunc() Explicit ((CChild*)pBase) casts to type "CChild*". So why to call derived vfunc() I need replace "important" string with: ((CChild*)pBase)->CChild::vfunc(); That's not how it works - this is: CBase *pBase = new CChild; pBase->vfunc();

/*公共样式*/ /*css初始化*/ html,body,ul,li,ol,ul,dl,dd,dt,p,h1,h2,h3,h4,h5,h6,form,fieldset{ margin: 0; padding: 0; } /*fieldset组合表单中的相关元素*/ fieldset,img,input,button{ border: none; padding: 0; margin: 0; outline-style: none; } /*清除列表风格*/ ul,ol{ list-style: none; } input{ padding-top: 0; padding-bottom: 0; font-family: "simsun","宋体"; } select,input{ vertical-align: middle; } select,input,textarea{ font-size: 12px; margin: 0; } /*防止多行文本拖拽*/ textarea{ resize: none; } /*去掉图片底侧默认的3像素空白空隙*/ img{ border: 0; vertical-align: middle; } /*合并外边线*/ table{ border-collapse: collapse; } body{ font: 12px/150% arial

We have a content-managed solution (SDL Tridion, to be specific; however, the question is more general), which includes multiple sites with content of different languages. They all share a number of Razor-based templates, which are used to render HTML fragments with specific injected content when pages are published. CRM is also managed through the CMS and the same templating is used for the creation of email newsletters. These HTML emails contain images, which are published out to whatever site manages the distribution list in question. Because the templating system is generic and the CMS has

Which of the two should be preferred? There are some methods which are called by class A, B and C. Should those methods be encapsulated in a class D (base of A, B and C) ? OR Should those methods be encapsulated in a class U and other classes creats it's object to use the methods as required. On what basis decision should be taken? Thanks. You should make a static utility class. Only use inheritance if it's actually meaningful—if A , B , and C actually are a D . I'd base the decision on what the methods are doing, if they're doing things specific to classes A, B and C then they should be in

BASE 模型是CAP定理牺牲强一致性、保证可用性的折中方案： 1、 B asically A vailable-基本可用 　　分布式系统发生不可预知的故障时，允许损失部分可用性，如服务降级等。 2、 S oft state-弱状态 　　分布式系统不同节点间某个时刻数据允许存在中间状态，不同节点的数据副本之间进行同步时可能存在时延，如主从同步。 3、 E ventually consistent-最终一致 　　分布式系统不同节点的所有数据副本，在经过一段时间数据同步后，最终达到一致状态，即保证最终一致性，不保证实时一致性。 我们通常接触的常见中间件，如mysql、zookeeper、redis、elasticsearch等都是基于BASE理论建立的 来源： https://www.cnblogs.com/jackcto/p/11904616.html

I'm getting a very confusing error in my program. I think I may have two different objects of the same class where I thought I had the same object. It is confusing because I am dealing with a very large framework where it is not simple to obtain a pointer to the object I need. My question is, if I have a class Derived which in inherits from Base, and I have a pointer to a Derived object, how can I get the address of the Base object from the derived object? I am working with the source code of the Base Class and am printing out the address of "this" in Base. In another part of my code a