awk

问题 I am trying to extract the To header from an email file using sed on linux. The problem is that the To header could be on multiple lines. e.g: To: name1@mydomain.org, name2@mydomain.org, name3@mydomain.org, name4@mydomain.org, name5@mydomain.org Message-ID: <46608700.369886.1549009227948@domain.org> I tried the following: sed -n -e '/^[Tt]o: / { N; p; }' _message_file_ | awk '{$1=$1;printf("%s ",$0)};NR%2==0{print ""}' The sed command extracts the line starting with To and next line. I pipe

问题 I have two different files. Part of those files are: file 1: ifile1.txt 21 10.3 70.32 09 32 11.3 71.43 10 33 15.4 75.00 00 54 17.3 68.03 12 95 19.2 65.02 21 99 20.1 80.10 11 and so on...... Where 1st column is the ID, 2nd column refers to x-axis, 3rd column refers to y-axis, 4th column refers to value file2: ifile2.txt 10.10 70.12 10 10.11 73.33 08 11.05 72.40 00 11.30 69.13 15 12.00 64.02 27 12.05 79.20 25 13.10 80.32 10 13.11 75.43 06 14.05 74.00 02 14.20 69.03 15 16.40 65.02 13 16.55 68.10

问题 $ cat file aaa bbb ccc ddd eee jjj kkk lll mmm nnn ooo ppp The following AWK command will paste the 'mmm' line at the end of the 'ddd eee' line. Is there a simpler way to do this using AWK or sed? $ awk 'FNR==NR {if (NR==4) foo=$0; next} FNR==2 {print $0" "foo; next} FNR==4 {next} 1' file file aaa bbb ccc ddd eee mmm jjj kkk lll nnn ooo ppp To clarify: I want to paste line 4 at the end of line 2 in this particular file, with a single space between the 'ddd eee' and the 'mmm'. That's the task.

问题 $ cat file aaa bbb ccc ddd eee jjj kkk lll mmm nnn ooo ppp The following AWK command will paste the 'mmm' line at the end of the 'ddd eee' line. Is there a simpler way to do this using AWK or sed? $ awk 'FNR==NR {if (NR==4) foo=$0; next} FNR==2 {print $0" "foo; next} FNR==4 {next} 1' file file aaa bbb ccc ddd eee mmm jjj kkk lll nnn ooo ppp To clarify: I want to paste line 4 at the end of line 2 in this particular file, with a single space between the 'ddd eee' and the 'mmm'. That's the task.

问题 $ cat file aaa bbb ccc ddd eee jjj kkk lll mmm nnn ooo ppp The following AWK command will paste the 'mmm' line at the end of the 'ddd eee' line. Is there a simpler way to do this using AWK or sed? $ awk 'FNR==NR {if (NR==4) foo=$0; next} FNR==2 {print $0" "foo; next} FNR==4 {next} 1' file file aaa bbb ccc ddd eee mmm jjj kkk lll nnn ooo ppp To clarify: I want to paste line 4 at the end of line 2 in this particular file, with a single space between the 'ddd eee' and the 'mmm'. That's the task.

问题 I have a file containing the following lines (3 fields delimited by space): component1 /dev/user/test 12344 component2 master abcefa123 component3 trunk 72812 component4 /branch/user/integration bc89fa component5 trunk 989091 component6 integration/test bc7829ac component7 /branch/dev/user/various eded34512 I need to manipulate the field 2 to cut its long prefix (same as you do in bash with ${string##*}) and to get the following result: component1 test 12344 component2 master abcefa123

问题 I have a file b.xyz as, -19.794325 -23.350704 -9.552335 -20.313872 -23.948248 -8.924463 -18.810708 -23.571757 -9.494047 -20.048543 -23.660052 -10.478968 I want to limit each of the entries to three decimal digits. I tried this one awk '{ $1=sprintf("%.3f",$1)} {$2=sprintf("%.3f",$2)} {$3=sprintf("%.3f",$3)} {print $1, $2, $3}' b.xyz it works for three columns, but how to expand it to apply for n/all columns? 回答1: If you will always have three fields, then you can use: $ awk '{printf "%.3f %

问题 I have a file b.xyz as, -19.794325 -23.350704 -9.552335 -20.313872 -23.948248 -8.924463 -18.810708 -23.571757 -9.494047 -20.048543 -23.660052 -10.478968 I want to limit each of the entries to three decimal digits. I tried this one awk '{ $1=sprintf("%.3f",$1)} {$2=sprintf("%.3f",$2)} {$3=sprintf("%.3f",$3)} {print $1, $2, $3}' b.xyz it works for three columns, but how to expand it to apply for n/all columns? 回答1: If you will always have three fields, then you can use: $ awk '{printf "%.3f %

问题 I have a file b.xyz as, -19.794325 -23.350704 -9.552335 -20.313872 -23.948248 -8.924463 -18.810708 -23.571757 -9.494047 -20.048543 -23.660052 -10.478968 I want to limit each of the entries to three decimal digits. I tried this one awk '{ $1=sprintf("%.3f",$1)} {$2=sprintf("%.3f",$2)} {$3=sprintf("%.3f",$3)} {print $1, $2, $3}' b.xyz it works for three columns, but how to expand it to apply for n/all columns? 回答1: If you will always have three fields, then you can use: $ awk '{printf "%.3f %

问题 In awk, I have 2 fields: $1 and $2. They are both strings that I want to concatenate and assign to a variable. 回答1: Just use var = var1 var2 and it will automatically concatenate the vars var1 and var2 : awk '{new_var=$1$2; print new_var}' file You can put an space in between with: awk '{new_var=$1" "$2; print new_var}' file Which in fact is the same as using FS , because it defaults to the space: awk '{new_var=$1 FS $2; print new_var}' file Test $ cat file hello how are you i am fine $ awk '