autostart

I've been programming Android in Eclipse for about a year now and I have always launched my app by right clicking on my project name in the project explorer, followed by "run as", then "Android Application". There has to be a better way... Is there a way to change this (three mouse clicks): "Right click on project" -> "run as" -> "Android Application" To this (one hotkey press): <My favorite hotkey> So I can just press one button to launch my app? Thanks! In preferences, go to General -> keys and search for the Android Application command. You can set a new key combination from here. Eclipse

1 先创建一个空项目（自己起名字） 2 在1步骤中创建的空项目中创建两个模块，创建方式如下图所示 1）创建启动器模块用maven项目我的启动器名称为 mao-spring-boot-starter pom.xml如下所示 <?xml version="1.0" encoding="UTF-8"?> <project xmlns=" http://maven.apache.org/POM/4.0.0 " xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>com.mao.starter</groupId> <artifactId>mao-spring-boot-starter</artifactId> <version>1.0-SNAPSHOT</version> <!-- 启动器--> <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>

Short Description: I want to auto-start an executable (opencv binary file, generate via c++) via a systemd service-script after booting, but I am unsuccessful. I narrowed down the error to the code statement "cv::imshow(....)" which opens a window and displays an image. At this point, the code throws the error: "QXcbConnection: Could not connect to display" However, if I manually execute the sh-script or the binary, both work fine. I searched around stackoverflow for the most common errors, and I tried to fix all I could found. I am quite sure, that: My service file actually runs at start

I have the need for my application to start and stop Windows Services based on certain events. The thing is that this application needs to run as an elevated normal user (In order to stop services), as well as auto start when Windows starts. Additionally, it need to be in the systray with an user interface. What are my options here? I suppose that there are at least two possibillities: To make the application auto start by putting it in the Startup folder or in the ..\Run key in the registry. But the question is, can this be done without the UAC prompt dialog pops up every time Windows starts?

I am creating a program in c++, which I want to be able to have the option to have users let it auto start in windows. So when a user starts his computer, windows will auto start this program. I have read stuff about modifying the registry or putting it in the startup folder, but what would be the best "clean" way to do this? Startup folder is clean enough. Gives the user the possibility to remove it if needed. There are many ways to autostart an application, but the easiest, most common and IMO best are: Put a shortcut in the autostart folder Add an autostart entry to the registry (Software

How can I autostart my application's service at device boot (with the possibility of enabling/disabling this feature)? What permissions do I have to include in AndroidManifest? Thanks this permission are use <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" /> In your <application> element (be sure to use a fully-qualified [or relative] class name for your BroadcastReceiver): <receiver android:name="com.example.MyBroadcastReceiver"> <intent-filter> <action android:name="android.intent.action.BOOT_COMPLETED" /> </intent-filter> </receiver> In MyBroadcastReceiver.java:

I have researched this to death online and cannot find anything regarding auto launching an iphone app when an external accessory is either paired using BT or plugged into the dock connector. We are an MFi developer with a BT accessory and application that we would like to launch when paired. We have the Info.plist containing our protocols and the device containing the correct protocol all working and communicating. The application works well with our BT device, however I would like to see the app launch when paired. I have seen this before with accessories plugged into the connector and would